def sum_of_powers(end, power = 2, start = 1):
  return sum([(i) ** power for i in range(start, end + 1)])

sum_of_powers(10) # 385
sum_of_powers(10, 3) # 3025
sum_of_powers(10, 3, 5) # 2925

# Input for row and column
R = int(input())
C = int(input())

# Using list comprehension for input
matrix = [[int(input()) for x in range (C)] for y in range(R)]

""" Rock Paper Scissors
----------------------------------------
"""
import random
import os
import re
os.system('cls' if os.name=='nt' else 'clear')
while (1 < 2):
    print "\n"
    print "Rock, Paper, Scissors - Shoot!"
    userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ")
    if not re.match("[SsRrPp]", userChoice):
        print "Please choose a letter:"
        print "[R]ock, [S]cissors or [P]aper."
        continue
    // Echo the user's choice
    print "You chose: " + userChoice
    choices = ['R', 'P', 'S']
    opponenetChoice = random.choice(choices)
    print "I chose: " + opponenetChoice
    if opponenetChoice == str.upper(userChoice):
        print "Tie! "
    #if opponenetChoice == str("R") and str.upper(userChoice) == "P"
    elif opponenetChoice == 'R' and userChoice.upper() == 'S':      
        print "Scissors beats rock, I win! "
        continue
    elif opponenetChoice == 'S' and userChoice.upper() == 'P':      
        print "Scissors beats paper! I win! "
        continue
    elif opponenetChoice == 'P' and userChoice.upper() == 'R':      
        print "Paper beat rock, I win! "
        continue
    else:       
        print "You win!"

import itertools

def compute_permutations(string):
    # Generate all permutations of the string
    permutations = itertools.permutations(string)

    # Convert each permutation tuple to a string
    permutations = [''.join(permutation) for permutation in permutations]

    return permutations

# Prompt the user for a string
string = input("Enter a string: ")

# Compute permutations
permutations = compute_permutations(string)

# Display the permutations
print("Permutations:")
for permutation in permutations:
    print(permutation)

my_list = [1, 2, 3, 4, 5]
removed_element = my_list.pop(2)  # Remove and return element at index 2
print(removed_element)  # 3
print(my_list)  # [1, 2, 4, 5]

last_element = my_list.pop()  # Remove and return the last element
print(last_element)  # 5
print(my_list)  # [1, 2, 4]

import re
_proposal_regex = r'(?:(?:(IKE|ESP):)?[\w/]+(?:/NO_EXT_SEQ)?(?:, ?(IKE|ESP):[\w/]+(?:/NO_EXT_SEQ)?)*)?'
_proposals_re = rf'(?P<proposals>{_proposal_regex}|)'
pattern = rf'received proposals: {_proposals_re}'
match = re.match(pattern, 'received proposals: ')
print(match.group('proposals') if match else "No match")  # Prints "No match"