• Nov 19, 2022 •CodeCatch
0 likes • 3 views
# Input for row and column R = int(input()) C = int(input()) # Using list comprehension for input matrix = [[int(input()) for x in range (C)] for y in range(R)]
• May 5, 2026 •CodeCatch
0 likes • 6 views
{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}
# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
• Dec 29, 2025 •CodeCatch
def bitonic_sort(arr, low, cnt, direction): ...
def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
• May 31, 2023 •CodeCatch
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def generate_floyds_triangle(num_rows): triangle = [] number = 1 for row in range(num_rows): current_row = [] for _ in range(row + 1): current_row.append(number) number += 1 triangle.append(current_row) return triangle def display_floyds_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Floyd's Triangle: ")) # Generate Floyd's Triangle floyds_triangle = generate_floyds_triangle(num_rows) # Display Floyd's Triangle display_floyds_triangle(floyds_triangle)