Binary search
0 likes • Sep 22, 2023 • 11 views
Python
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# Prompt user for a decimal numberdecimal = int(input("Enter a decimal number: "))# Convert decimal to binarybinary = bin(decimal)# Convert decimal to hexadecimalhexadecimal = hex(decimal)# Display the resultsprint("Binary:", binary)print("Hexadecimal:", hexadecimal)
class Rectangle:passclass Square(Rectangle):passrectangle = Rectangle()square = Square()print(isinstance(rectangle, Rectangle)) # Trueprint(isinstance(square, Rectangle)) # Trueprint(isinstance(square, Square)) # Trueprint(isinstance(rectangle, Square)) # False
#question1.pydef rose(n) :if n==0 :yield []else :for k in range(0,n) :for l in rose(k) :for r in rose(n-1-k) :yield [l]+[r]+[r]def start(n) :for x in rose(n) :print(x) #basically I am printing x for each rose(n) fileprint("starting program: \n")start(2) # here is where I call the start function
# function which return reverse of a stringdef isPalindrome(s):return s == s[::-1]# Driver codes = "malayalam"ans = isPalindrome(s)if ans:print("Yes")else:print("No")
color2 = (60, 74, 172)color1 = (19, 28, 87)percent = 1.0for i in range(101):resultRed = round(color1[0] + percent * (color2[0] - color1[0]))resultGreen = round(color1[1] + percent * (color2[1] - color1[1]))resultBlue = round(color1[2] + percent * (color2[2] - color1[2]))print((resultRed, resultGreen, resultBlue))percent -= 0.01
def generate_floyds_triangle(num_rows):triangle = []number = 1for row in range(num_rows):current_row = []for _ in range(row + 1):current_row.append(number)number += 1triangle.append(current_row)return triangledef display_floyds_triangle(triangle):for row in triangle:for number in row:print(number, end=" ")print()# Prompt the user for the number of rowsnum_rows = int(input("Enter the number of rows for Floyd's Triangle: "))# Generate Floyd's Trianglefloyds_triangle = generate_floyds_triangle(num_rows)# Display Floyd's Triangledisplay_floyds_triangle(floyds_triangle)