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class Solution(object):def floodFill(self, image, sr, sc, newColor):R, C = len(image), len(image[0])color = image[sr][sc]if color == newColor: return imagedef dfs(r, c):if image[r][c] == color:image[r][c] = newColorif r >= 1: dfs(r-1, c)if r+1 < R: dfs(r+1, c)if c >= 1: dfs(r, c-1)if c+1 < C: dfs(r, c+1)dfs(sr, sc)return image
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'
# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.# Python program to print all primes smaller than or equal to# n using Sieve of Eratosthenesdef SieveOfEratosthenes(n):# Create a boolean array "prime[0..n]" and initialize# all entries it as true. A value in prime[i] will# finally be false if i is Not a prime, else true.prime = [True for i in range(n + 1)]p = 2while (p * p <= n):# If prime[p] is not changed, then it is a primeif (prime[p] == True):# Update all multiples of pfor i in range(p * 2, n + 1, p):prime[i] = Falsep += 1prime[0]= Falseprime[1]= False# Print all prime numbersfor p in range(n + 1):if prime[p]:print (p)# driver programif __name__=='__main__':n = 30print("Following are the prime numbers smaller")print("than or equal to ", n)print("than or equal to ", n)SieveOfEratosthenes(n)
def when(predicate, when_true):return lambda x: when_true(x) if predicate(x) else xdouble_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)print(double_even_numbers(2)) # 4print(double_even_numbers(1)) # 1
filename = "data.txt"data = "Hello, World!"with open(filename, "a") as file:file.write(data)
# Deleting all even numbers from a lista = [1,2,3,4,5]del a[1::2]print(a)