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print("hello world")
def when(predicate, when_true):return lambda x: when_true(x) if predicate(x) else xdouble_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)print(double_even_numbers(2)) # 4print(double_even_numbers(1)) # 1
filename = "data.txt"with open(filename, "r") as file:file_contents = file.readlines()file_contents = [line.strip() for line in file_contents]print("File contents:")for line in file_contents:print(line)
# Python program for implementation of Bubble Sortdef bubbleSort(arr):n = len(arr)# Traverse through all array elementsfor i in range(n-1):# range(n) also work but outer loop will repeat one time more than needed.# Last i elements are already in placefor j in range(0, n-i-1):# traverse the array from 0 to n-i-1# Swap if the element found is greater# than the next elementif arr[j] > arr[j+1] :arr[j], arr[j+1] = arr[j+1], arr[j]# Driver code to test abovearr = [64, 34, 25, 12, 22, 11, 90]bubbleSort(arr)print ("Sorted array is:")for i in range(len(arr)):print ("%d" %arr[i]),
# Python program to reverse a linked list# Time Complexity : O(n)# Space Complexity : O(n) as 'next'#variable is getting created in each loop.# Node classclass Node:# Constructor to initialize the node objectdef __init__(self, data):self.data = dataself.next = Noneclass LinkedList:# Function to initialize headdef __init__(self):self.head = None# Function to reverse the linked listdef reverse(self):prev = Nonecurrent = self.headwhile(current is not None):next = current.nextcurrent.next = prevprev = currentcurrent = nextself.head = prev# Function to insert a new node at the beginningdef push(self, new_data):new_node = Node(new_data)new_node.next = self.headself.head = new_node# Utility function to print the linked LinkedListdef printList(self):temp = self.headwhile(temp):print temp.data,temp = temp.next# Driver program to test above functionsllist = LinkedList()llist.push(20)llist.push(4)llist.push(15)llist.push(85)print "Given Linked List"llist.printList()llist.reverse()print "\nReversed Linked List"llist.printList()
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'