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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.# Python program to print all primes smaller than or equal to# n using Sieve of Eratosthenesdef SieveOfEratosthenes(n):# Create a boolean array "prime[0..n]" and initialize# all entries it as true. A value in prime[i] will# finally be false if i is Not a prime, else true.prime = [True for i in range(n + 1)]p = 2while (p * p <= n):# If prime[p] is not changed, then it is a primeif (prime[p] == True):# Update all multiples of pfor i in range(p * 2, n + 1, p):prime[i] = Falsep += 1prime[0]= Falseprime[1]= False# Print all prime numbersfor p in range(n + 1):if prime[p]:print (p)# driver programif __name__=='__main__':n = 30print("Following are the prime numbers smaller")print("than or equal to ", n)print("than or equal to ", n)SieveOfEratosthenes(n)
def key_of_min(d):return min(d, key = d.get)key_of_min({'a':4, 'b':0, 'c':13}) # b
# Python program to reverse a linked list# Time Complexity : O(n)# Space Complexity : O(n) as 'next'#variable is getting created in each loop.# Node classclass Node:# Constructor to initialize the node objectdef __init__(self, data):self.data = dataself.next = Noneclass LinkedList:# Function to initialize headdef __init__(self):self.head = None# Function to reverse the linked listdef reverse(self):prev = Nonecurrent = self.headwhile(current is not None):next = current.nextcurrent.next = prevprev = currentcurrent = nextself.head = prev# Function to insert a new node at the beginningdef push(self, new_data):new_node = Node(new_data)new_node.next = self.headself.head = new_node# Utility function to print the linked LinkedListdef printList(self):temp = self.headwhile(temp):print temp.data,temp = temp.next# Driver program to test above functionsllist = LinkedList()llist.push(20)llist.push(4)llist.push(15)llist.push(85)print "Given Linked List"llist.printList()llist.reverse()print "\nReversed Linked List"llist.printList()
# Python program for Plotting Fibonacci# spiral fractal using Turtleimport turtleimport mathdef fiboPlot(n):a = 0b = 1square_a = asquare_b = b# Setting the colour of the plotting pen to bluex.pencolor("blue")# Drawing the first squarex.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Drawing the rest of the squaresfor i in range(1, n):x.backward(square_a * factor)x.right(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Bringing the pen to starting point of the spiral plotx.penup()x.setposition(factor, 0)x.seth(0)x.pendown()# Setting the colour of the plotting pen to redx.pencolor("red")# Fibonacci Spiral Plotx.left(90)for i in range(n):print(b)fdwd = math.pi * b * factor / 2fdwd /= 90for j in range(90):x.forward(fdwd)x.left(1)temp = aa = bb = temp + b# Here 'factor' signifies the multiplicative# factor which expands or shrinks the scale# of the plot by a certain factor.factor = 1# Taking Input for the number of# Iterations our Algorithm will runn = int(input('Enter the number of iterations (must be > 1): '))# Plotting the Fibonacci Spiral Fractal# and printing the corresponding Fibonacci Numberif n > 0:print("Fibonacci series for", n, "elements :")x = turtle.Turtle()x.speed(100)fiboPlot(n)turtle.done()else:print("Number of iterations must be > 0")
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'
def check_prop(fn, prop):return lambda obj: fn(obj[prop])check_age = check_prop(lambda x: x >= 18, 'age')user = {'name': 'Mark', 'age': 18}check_age(user) # True