Loading...
More Python Posts
x[cat_var].isnull().sum().sort_values(ascending=False)
"""Take screenshots at x interval - make a movie of doings on a computer."""import timefrom datetime import datetimeimport ffmpegimport pyautoguiwhile True:epoch_time = int(time.time())today = datetime.now().strftime("%Y_%m_%d")filename = str(epoch_time) + ".png"print("taking screenshot: {0}".format(filename))myScreenshot = pyautogui.screenshot()myScreenshot.save(today + "/" + filename)time.sleep(5)## and then tie it together with: https://github.com/kkroening/ffmpeg-python/blob/master/examples/README.md#assemble-video-from-sequence-of-frames#"""import ffmpeg(ffmpeg.input('./2021_01_22/*.png', pattern_type='glob', framerate=25).filter('deflicker', mode='pm', size=10).filter('scale', size='hd1080', force_original_aspect_ratio='increase').output('movie.mp4', crf=20, preset='slower', movflags='faststart', pix_fmt='yuv420p').run())"""
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)
import anytree as atimport random as rm# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.def random_tree(node_count):# Generates the list of nodesnodes = []for i in range(node_count):test = rm.randint(1,2)if test == 1:nodes.append(at.Node(str(i),color="white"))else:nodes.append(at.Node(str(i),color="red"))#Creates the various main branchesfor i in range(node_count):for j in range(i, len(nodes)):test = rm.randint(1,len(nodes))if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):nodes[j].parent = nodes[i]#Collects all the main branches into a single tree with the first node being the rootfor i in range(1, node_count):if nodes[i].parent == None and (not nodes[i] == nodes[0]):nodes[i].parent = nodes[0]return nodes[0]
def calculate_values():value1 = 10value2 = 20return value1, value2result1, result2 = calculate_values()print("Result 1:", result1)print("Result 2:", result2)
def key_of_min(d):return min(d, key = d.get)key_of_min({'a':4, 'b':0, 'c':13}) # b