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Check Armstrong Number

May 31, 2023CodeCatch
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Calculator

Nov 19, 2022CodeCatch

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""" Calculator
----------------------------------------
"""
def addition ():
print("Addition")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 0
while n != 0:
ans = ans + n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def subtraction ():
print("Subtraction");
n = float(input("Enter the number: "))
t = 0 //Total number enter
sum = 0
while n != 0:
ans = ans - n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def multiplication ():
print("Multiplication")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 1
while n != 0:
ans = ans * n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def average():
an = []
an = addition()
t = an[1]
a = an[0]
ans = a / t
return [ans,t]
// main...
while True:
list = []
print(" My first python program!")
print(" Simple Calculator in python by Malik Umer Farooq")
print(" Enter 'a' for addition")
print(" Enter 's' for substraction")
print(" Enter 'm' for multiplication")
print(" Enter 'v' for average")
print(" Enter 'q' for quit")
c = input(" ")
if c != 'q':
if c == 'a':
list = addition()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 's':
list = subtraction()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'm':
list = multiplication()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'v':
list = average()
print("Ans = ", list[0], " total inputs ",list[1])
else:
print ("Sorry, invilid character")
else:
break

Hello World

Sep 9, 2023AustinLeath

0 likes • 23 views

print("test")

integer to roman numeral

Nov 19, 2022CodeCatch

0 likes • 1 view

def to_roman_numeral(num):
lookup = [
(1000, 'M'),
(900, 'CM'),
(500, 'D'),
(400, 'CD'),
(100, 'C'),
(90, 'XC'),
(50, 'L'),
(40, 'XL'),
(10, 'X'),
(9, 'IX'),
(5, 'V'),
(4, 'IV'),
(1, 'I'),
]
res = ''
for (n, roman) in lookup:
(d, num) = divmod(num, n)
res += roman * d
return res
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

LeetCode Flood Fill

Oct 15, 2022CodeCatch

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class Solution(object):
def floodFill(self, image, sr, sc, newColor):
R, C = len(image), len(image[0])
color = image[sr][sc]
if color == newColor: return image
def dfs(r, c):
if image[r][c] == color:
image[r][c] = newColor
if r >= 1: dfs(r-1, c)
if r+1 < R: dfs(r+1, c)
if c >= 1: dfs(r, c-1)
if c+1 < C: dfs(r, c+1)
dfs(sr, sc)
return image

combine values

Nov 19, 2022CodeCatch

0 likes • 0 views

from collections import defaultdict
def combine_values(*dicts):
res = defaultdict(list)
for d in dicts:
for key in d:
res[key].append(d[key])
return dict(res)
d1 = {'a': 1, 'b': 'foo', 'c': 400}
d2 = {'a': 3, 'b': 200, 'd': 400}
combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}

bruteforce password cracker

Nov 18, 2022AustinLeath

0 likes • 4 views

import itertools
import string
import time
def guess_password(real):
chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation
attempts = 0
for password_length in range(1, 9):
for guess in itertools.product(chars, repeat=password_length):
startTime = time.time()
attempts += 1
guess = ''.join(guess)
if guess == real:
return 'password is {}. found in {} guesses.'.format(guess, attempts)
loopTime = (time.time() - startTime);
print(guess, attempts, loopTime)
print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n")
val = input("Enter a password you want to crack that is 9 characters or below: ")
print(guess_password(val.lower()))