• Mar 12, 2021 •mo_ak
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prime_lists=[] # a list to store the prime numbers def prime(n): # define prime numbers if n <= 1: return False # divide n by 2... up to n-1 for i in range(2, n): if n % i == 0: # the remainder should'nt be a 0 return False else: prime_lists.append(n) return True for n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30 prime(n) check=0 # a var to limit the output to 10 only for n in prime_lists: for x in prime_lists: val= n *x if (val > 1000 ): check=check +1 if (check <10) : print("the num is:", val , "=",n , "* ", x ) break
• Nov 18, 2022 •AustinLeath
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# List lst = [1, 2, 3, 'Alice', 'Alice'] # One-Liner indices = [i for i in range(len(lst)) if lst[i]=='Alice'] # Result print(indices) # [3, 4]
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#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
• Nov 19, 2022 •CodeCatch
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def when(predicate, when_true): return lambda x: when_true(x) if predicate(x) else x double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2) print(double_even_numbers(2)) # 4 print(double_even_numbers(1)) # 1
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primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)
• Dec 24, 2025 •CodeCatch
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