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my_list = [1, 2, 3, 4, 5]removed_element = my_list.pop(2) # Remove and return element at index 2print(removed_element) # 3print(my_list) # [1, 2, 4, 5]last_element = my_list.pop() # Remove and return the last elementprint(last_element) # 5print(my_list) # [1, 2, 4]
print('hello, world')
print(“Hello World”)
# Python program for Plotting Fibonacci# spiral fractal using Turtleimport turtleimport mathdef fiboPlot(n):a = 0b = 1square_a = asquare_b = b# Setting the colour of the plotting pen to bluex.pencolor("blue")# Drawing the first squarex.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Drawing the rest of the squaresfor i in range(1, n):x.backward(square_a * factor)x.right(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Bringing the pen to starting point of the spiral plotx.penup()x.setposition(factor, 0)x.seth(0)x.pendown()# Setting the colour of the plotting pen to redx.pencolor("red")# Fibonacci Spiral Plotx.left(90)for i in range(n):print(b)fdwd = math.pi * b * factor / 2fdwd /= 90for j in range(90):x.forward(fdwd)x.left(1)temp = aa = bb = temp + b# Here 'factor' signifies the multiplicative# factor which expands or shrinks the scale# of the plot by a certain factor.factor = 1# Taking Input for the number of# Iterations our Algorithm will runn = int(input('Enter the number of iterations (must be > 1): '))# Plotting the Fibonacci Spiral Fractal# and printing the corresponding Fibonacci Numberif n > 0:print("Fibonacci series for", n, "elements :")x = turtle.Turtle()x.speed(100)fiboPlot(n)turtle.done()else:print("Number of iterations must be > 0")
#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77# xor a list of integers to find the lonely integerres = a[0]for i in range(1,len(a)):res = res ^ a[i]
import pandas as pdx = pd.read_excel(FILE_NAME)print(x)