• Mar 10, 2021 •Skrome
0 likes • 2 views
color2 = (60, 74, 172) color1 = (19, 28, 87) percent = 1.0 for i in range(101): resultRed = round(color1[0] + percent * (color2[0] - color1[0])) resultGreen = round(color1[1] + percent * (color2[1] - color1[1])) resultBlue = round(color1[2] + percent * (color2[2] - color1[2])) print((resultRed, resultGreen, resultBlue)) percent -= 0.01
• Nov 19, 2022 •CodeCatch
# Deleting all even numbers from a list a = [1,2,3,4,5] del a[1::2] print(a)
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from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
• Oct 4, 2023 •AustinLeath
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weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))
• Nov 18, 2022 •AustinLeath
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import itertools import string import time def guess_password(real): chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation attempts = 0 for password_length in range(1, 9): for guess in itertools.product(chars, repeat=password_length): startTime = time.time() attempts += 1 guess = ''.join(guess) if guess == real: return 'password is {}. found in {} guesses.'.format(guess, attempts) loopTime = (time.time() - startTime); print(guess, attempts, loopTime) print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n") val = input("Enter a password you want to crack that is 9 characters or below: ") print(guess_password(val.lower()))
• Jun 1, 2023 •CodeCatch
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bytes_data = b'Hello, World!' string_data = bytes_data.decode('utf-8') print("String:", string_data)