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from math import pidef rads_to_degrees(rad):return (rad * 180.0) / pirads_to_degrees(pi / 2) # 90.0
magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits)sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits))print("64 bit sum:", magnitude(64) * sign(64))print("32 bit sum:", magnitude(32) * sign(32))print("16 bit sum:", magnitude(16) * sign(16))
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)
#You are given a two-digit integer n. Return the sum of its digits.#Example#For n = 29 the output should be solution (n) = 11def solution(n):return (n//10 + n%10)
from statistics import median, mean, modedef print_stats(array):print(array)print("median =", median(array))print("mean =", mean(array))print("mode =", mode(array))print()print_stats([1, 2, 3, 3, 4])print_stats([1, 2, 3, 3])
# Python program for implementation of Radix Sort# A function to do counting sort of arr[] according to# the digit represented by exp.def countingSort(arr, exp1):n = len(arr)# The output array elements that will have sorted arroutput = [0] * (n)# initialize count array as 0count = [0] * (10)# Store count of occurrences in count[]for i in range(0, n):index = (arr[i]/exp1)count[int((index)%10)] += 1# Change count[i] so that count[i] now contains actual# position of this digit in output arrayfor i in range(1,10):count[i] += count[i-1]# Build the output arrayi = n-1while i>=0:index = (arr[i]/exp1)output[ count[ int((index)%10) ] - 1] = arr[i]count[int((index)%10)] -= 1i -= 1# Copying the output array to arr[],# so that arr now contains sorted numbersi = 0for i in range(0,len(arr)):arr[i] = output[i]# Method to do Radix Sortdef radixSort(arr):# Find the maximum number to know number of digitsmax1 = max(arr)# Do counting sort for every digit. Note that instead# of passing digit number, exp is passed. exp is 10^i# where i is current digit numberexp = 1while max1/exp > 0:countingSort(arr,exp)exp *= 10# Driver code to test abovearr = [ 170, 45, 75, 90, 802, 24, 2, 66]radixSort(arr)for i in range(len(arr)):print(arr[i]),