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def hex_to_rgb(hex):return tuple(int(hex[i:i+2], 16) for i in (0, 2, 4))hex_to_rgb('FFA501') # (255, 165, 1)
class Rectangle:passclass Square(Rectangle):passrectangle = Rectangle()square = Square()print(isinstance(rectangle, Rectangle)) # Trueprint(isinstance(square, Rectangle)) # Trueprint(isinstance(square, Square)) # Trueprint(isinstance(rectangle, Square)) # False
from collections import Counterdef find_parity_outliers(nums):return [x for x in numsif x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]]find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]
filename = "data.txt"data = "Hello, World!"with open(filename, "a") as file:file.write(data)
def calculate_values():value1 = 10value2 = 20return value1, value2result1, result2 = calculate_values()print("Result 1:", result1)print("Result 2:", result2)
# Python program for implementation of Radix Sort# A function to do counting sort of arr[] according to# the digit represented by exp.def countingSort(arr, exp1):n = len(arr)# The output array elements that will have sorted arroutput = [0] * (n)# initialize count array as 0count = [0] * (10)# Store count of occurrences in count[]for i in range(0, n):index = (arr[i]/exp1)count[int((index)%10)] += 1# Change count[i] so that count[i] now contains actual# position of this digit in output arrayfor i in range(1,10):count[i] += count[i-1]# Build the output arrayi = n-1while i>=0:index = (arr[i]/exp1)output[ count[ int((index)%10) ] - 1] = arr[i]count[int((index)%10)] -= 1i -= 1# Copying the output array to arr[],# so that arr now contains sorted numbersi = 0for i in range(0,len(arr)):arr[i] = output[i]# Method to do Radix Sortdef radixSort(arr):# Find the maximum number to know number of digitsmax1 = max(arr)# Do counting sort for every digit. Note that instead# of passing digit number, exp is passed. exp is 10^i# where i is current digit numberexp = 1while max1/exp > 0:countingSort(arr,exp)exp *= 10# Driver code to test abovearr = [ 170, 45, 75, 90, 802, 24, 2, 66]radixSort(arr)for i in range(len(arr)):print(arr[i]),