• Nov 18, 2022 •AustinLeath
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#Python 3: Fibonacci series up to n def fib(n): a, b = 0, 1 while a < n: print(a, end=' ') a, b = b, a+b print() fib(1000)
• May 5, 2026 •CodeCatch
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0 likes • 8 views
#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
• Nov 19, 2022 •CodeCatch
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# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
• May 31, 2023 •CodeCatch
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def generate_pascals_triangle(num_rows): triangle = [] for row in range(num_rows): # Initialize the row with 1 current_row = [1] # Calculate the values for the current row if row > 0: previous_row = triangle[row - 1] for i in range(len(previous_row) - 1): current_row.append(previous_row[i] + previous_row[i + 1]) # Append 1 at the end of the row current_row.append(1) # Add the current row to the triangle triangle.append(current_row) return triangle def display_pascals_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Pascal's Triangle: ")) # Generate Pascal's Triangle pascals_triangle = generate_pascals_triangle(num_rows) # Display Pascal's Triangle display_pascals_triangle(pascals_triangle)
from functools import partial def curry(fn, *args): return partial(fn, *args) add = lambda x, y: x + y add10 = curry(add, 10) add10(20) # 30