• Nov 19, 2022 •CodeCatch
1 like • 4 views
def hex_to_rgb(hex): return tuple(int(hex[i:i+2], 16) for i in (0, 2, 4)) hex_to_rgb('FFA501') # (255, 165, 1)
• Sep 14, 2024 •rgannedo-6205
0 likes • 3 views
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
0 likes • 6 views
from collections import Counter def find_parity_outliers(nums): return [ x for x in nums if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0] ] find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]
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list_1 = [1,2,3,4,5,6,7,8,9] cubed = map(lambda x: pow(x,3), list_1) print(list(cubed)) #Results #[1, 8, 27, 64, 125, 216, 343, 512, 729]
• Nov 18, 2022 •AustinLeath
import itertools import string import time def guess_password(real): chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation attempts = 0 for password_length in range(1, 9): for guess in itertools.product(chars, repeat=password_length): startTime = time.time() attempts += 1 guess = ''.join(guess) if guess == real: return 'password is {}. found in {} guesses.'.format(guess, attempts) loopTime = (time.time() - startTime); print(guess, attempts, loopTime) print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n") val = input("Enter a password you want to crack that is 9 characters or below: ") print(guess_password(val.lower()))
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from collections import defaultdict def combine_values(*dicts): res = defaultdict(list) for d in dicts: for key in d: res[key].append(d[key]) return dict(res) d1 = {'a': 1, 'b': 'foo', 'c': 400} d2 = {'a': 3, 'b': 200, 'd': 400} combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}