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mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}# How to sort a dict by value Python 3>sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}print(sort)# How to sort a dict by key Python 3>sort = {key:mydict[key] for key in sorted(mydict.keys())}print(sort)
def Fibonacci(n):if n<0:print("Incorrect input")# First Fibonacci number is 0elif n==1:return 0# Second Fibonacci number is 1elif n==2:return 1else:return Fibonacci(n-1)+Fibonacci(n-2)# Driver Programprint(Fibonacci(9))
magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits)sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits))print("64 bit sum:", magnitude(64) * sign(64))print("32 bit sum:", magnitude(32) * sign(32))print("16 bit sum:", magnitude(16) * sign(16))
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
# function which return reverse of a stringdef isPalindrome(s):return s == s[::-1]# Driver codes = "malayalam"ans = isPalindrome(s)if ans:print("Yes")else:print("No")
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'