Skip to main content

Multiply Two Matrices

May 31, 2023CodeCatch
Loading...

More Python Posts

UNT CSCE 2100 Question 1

Nov 18, 2022AustinLeath

0 likes • 8 views

#question1.py
def rose(n) :
if n==0 :
yield []
else :
for k in range(0,n) :
for l in rose(k) :
for r in rose(n-1-k) :
yield [l]+[r]+[r]
def start(n) :
for x in rose(n) :
print(x) #basically I am printing x for each rose(n) file
print("starting program: \n")
start(2) # here is where I call the start function

return byte size

Nov 19, 2022CodeCatch

0 likes • 1 view

def byte_size(s):
return len(s.encode('utf-8'))
byte_size('😀') # 4
byte_size('Hello World') # 11

AnyTree Randomizer

Apr 15, 2021NoahEaton

0 likes • 0 views

import anytree as at
import random as rm
# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.
def random_tree(node_count):
# Generates the list of nodes
nodes = []
for i in range(node_count):
test = rm.randint(1,2)
if test == 1:
nodes.append(at.Node(str(i),color="white"))
else:
nodes.append(at.Node(str(i),color="red"))
#Creates the various main branches
for i in range(node_count):
for j in range(i, len(nodes)):
test = rm.randint(1,len(nodes))
if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):
nodes[j].parent = nodes[i]
#Collects all the main branches into a single tree with the first node being the root
for i in range(1, node_count):
if nodes[i].parent == None and (not nodes[i] == nodes[0]):
nodes[i].parent = nodes[0]
return nodes[0]

convert bytes to a string

Jun 1, 2023CodeCatch

0 likes • 2 views

bytes_data = b'Hello, World!'
string_data = bytes_data.decode('utf-8')
print("String:", string_data)

Untitled

Sep 14, 2024rgannedo-6205

0 likes • 4 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")

Dictionary Sort

Nov 18, 2022AustinLeath

0 likes • 4 views

mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}
# How to sort a dict by value Python 3>
sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}
print(sort)
# How to sort a dict by key Python 3>
sort = {key:mydict[key] for key in sorted(mydict.keys())}
print(sort)