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#question1.pydef rose(n) :if n==0 :yield []else :for k in range(0,n) :for l in rose(k) :for r in rose(n-1-k) :yield [l]+[r]+[r]def start(n) :for x in rose(n) :print(x) #basically I am printing x for each rose(n) fileprint("starting program: \n")start(2) # here is where I call the start function
def byte_size(s):return len(s.encode('utf-8'))byte_size('😀') # 4byte_size('Hello World') # 11
import anytree as atimport random as rm# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.def random_tree(node_count):# Generates the list of nodesnodes = []for i in range(node_count):test = rm.randint(1,2)if test == 1:nodes.append(at.Node(str(i),color="white"))else:nodes.append(at.Node(str(i),color="red"))#Creates the various main branchesfor i in range(node_count):for j in range(i, len(nodes)):test = rm.randint(1,len(nodes))if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):nodes[j].parent = nodes[i]#Collects all the main branches into a single tree with the first node being the rootfor i in range(1, node_count):if nodes[i].parent == None and (not nodes[i] == nodes[0]):nodes[i].parent = nodes[0]return nodes[0]
bytes_data = b'Hello, World!'string_data = bytes_data.decode('utf-8')print("String:", string_data)
# Python binary search functiondef binary_search(arr, target):left = 0right = len(arr) - 1while left <= right:mid = (left + right) // 2if arr[mid] == target:return midelif arr[mid] < target:left = mid + 1else:right = mid - 1return -1# Usagearr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]target = 7result = binary_search(arr, target)if result != -1:print(f"Element is present at index {result}")else:print("Element is not present in array")
mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}# How to sort a dict by value Python 3>sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}print(sort)# How to sort a dict by key Python 3>sort = {key:mydict[key] for key in sorted(mydict.keys())}print(sort)