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#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77# xor a list of integers to find the lonely integerres = a[0]for i in range(1,len(a)):res = res ^ a[i]
from math import pidef rads_to_degrees(rad):return (rad * 180.0) / pirads_to_degrees(pi / 2) # 90.0
import pandas as pdx = pd.read_excel(FILE_NAME)print(x)
filename = "data.txt"with open(filename, "r") as file:file_contents = file.readlines()file_contents = [line.strip() for line in file_contents]print("File contents:")for line in file_contents:print(line)
# Python code to find the URL from an input string# Using the regular expressionimport redef Find(string):# findall() has been used# with valid conditions for urls in stringregex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))"url = re.findall(regex,string)return [x[0] for x in url]# Driver Codestring = 'My Profile: https://codecatch.net'print("Urls: ", Find(string))
def max_n(lst, n = 1):return sorted(lst, reverse = True)[:n]max_n([1, 2, 3]) # [3]max_n([1, 2, 3], 2) # [3, 2]