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def get_ldap_user(member_cn, user, passwrd):'''Get an LDAP user and return the SAMAccountName'''#---- Setting up the Connection#account used for binding - Avoid putting these in version controlbindDN = str(user) + "@unt.ad.unt.edu"bindPass = passwrd#set some tuneables for the LDAP library.ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)conn = ldap.initialize('ldaps://unt.ad.unt.edu')conn.protocol_version = 3conn.set_option(ldap.OPT_REFERRALS, 0)#authenticate the connection so that you can make additional queriestry:result = conn.simple_bind_s(bindDN, bindPass)except ldap.INVALID_CREDENTIALS:result = "Invalid credentials for %s" % usersys.exit()#build query in the form of (uid=user)ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")return sAMAccountName
from time import sleepdef delay(fn, ms, *args):sleep(ms / 1000)return fn(*args)delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second
import sys# sample TuplesTuple1 = ("A", 1, "B", 2, "C", 3)Tuple2 = ("Geek1", "Raju", "Geek2", "Nikhil", "Geek3", "Deepanshu")Tuple3 = ((1, "Lion"), ( 2, "Tiger"), (3, "Fox"), (4, "Wolf"))# print the sizes of sample Tuplesprint("Size of Tuple1: " + str(sys.getsizeof(Tuple1)) + "bytes")print("Size of Tuple2: " + str(sys.getsizeof(Tuple2)) + "bytes")print("Size of Tuple3: " + str(sys.getsizeof(Tuple3)) + "bytes")
my_list = [1, 2, 3, 4, 5]removed_element = my_list.pop(2) # Remove and return element at index 2print(removed_element) # 3print(my_list) # [1, 2, 4, 5]last_element = my_list.pop() # Remove and return the last elementprint(last_element) # 5print(my_list) # [1, 2, 4]
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'
def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])sum_of_powers(10) # 385sum_of_powers(10, 3) # 3025sum_of_powers(10, 3, 5) # 2925