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radians to degrees

Nov 19, 2022CodeCatch
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get LDAP user

Nov 18, 2022AustinLeath

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def get_ldap_user(member_cn, user, passwrd):
'''
Get an LDAP user and return the SAMAccountName
'''
#---- Setting up the Connection
#account used for binding - Avoid putting these in version control
bindDN = str(user) + "@unt.ad.unt.edu"
bindPass = passwrd
#set some tuneables for the LDAP library.
ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)
#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)
conn = ldap.initialize('ldaps://unt.ad.unt.edu')
conn.protocol_version = 3
conn.set_option(ldap.OPT_REFERRALS, 0)
#authenticate the connection so that you can make additional queries
try:
result = conn.simple_bind_s(bindDN, bindPass)
except ldap.INVALID_CREDENTIALS:
result = "Invalid credentials for %s" % user
sys.exit()
#build query in the form of (uid=user)
ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'
ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)
sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")
return sAMAccountName

delay time lambda

Nov 19, 2022CodeCatch

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from time import sleep
def delay(fn, ms, *args):
sleep(ms / 1000)
return fn(*args)
delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second

Size of tuple

Nov 19, 2022CodeCatch

0 likes • 3 views

import sys
# sample Tuples
Tuple1 = ("A", 1, "B", 2, "C", 3)
Tuple2 = ("Geek1", "Raju", "Geek2", "Nikhil", "Geek3", "Deepanshu")
Tuple3 = ((1, "Lion"), ( 2, "Tiger"), (3, "Fox"), (4, "Wolf"))
# print the sizes of sample Tuples
print("Size of Tuple1: " + str(sys.getsizeof(Tuple1)) + "bytes")
print("Size of Tuple2: " + str(sys.getsizeof(Tuple2)) + "bytes")
print("Size of Tuple3: " + str(sys.getsizeof(Tuple3)) + "bytes")
my_list = [1, 2, 3, 4, 5]
removed_element = my_list.pop(2) # Remove and return element at index 2
print(removed_element) # 3
print(my_list) # [1, 2, 4, 5]
last_element = my_list.pop() # Remove and return the last element
print(last_element) # 5
print(my_list) # [1, 2, 4]

integer to roman numeral

Nov 19, 2022CodeCatch

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def to_roman_numeral(num):
lookup = [
(1000, 'M'),
(900, 'CM'),
(500, 'D'),
(400, 'CD'),
(100, 'C'),
(90, 'XC'),
(50, 'L'),
(40, 'XL'),
(10, 'X'),
(9, 'IX'),
(5, 'V'),
(4, 'IV'),
(1, 'I'),
]
res = ''
for (n, roman) in lookup:
(d, num) = divmod(num, n)
res += roman * d
return res
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

sum of powers

Nov 19, 2022CodeCatch

0 likes • 16 views

def sum_of_powers(end, power = 2, start = 1):
return sum([(i) ** power for i in range(start, end + 1)])
sum_of_powers(10) # 385
sum_of_powers(10, 3) # 3025
sum_of_powers(10, 3, 5) # 2925