• Jan 20, 2021 •Ntindle
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print(“Hello World”)
• Nov 18, 2022 •AustinLeath
0 likes • 8 views
#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
• Nov 19, 2022 •CodeCatch
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def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
• Feb 26, 2023 •wabdelh
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#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
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list_1 = [1,2,3,4,5,6,7,8,9] cubed = map(lambda x: pow(x,3), list_1) print(list(cubed)) #Results #[1, 8, 27, 64, 125, 216, 343, 512, 729]
# Python code to demonstrate # method to remove i'th character # Naive Method # Initializing String test_str = "CodeCatch" # Printing original string print ("The original string is : " + test_str) # Removing char at pos 3 # using loop new_str = "" for i in range(len(test_str)): if i != 2: new_str = new_str + test_str[i] # Printing string after removal print ("The string after removal of i'th character : " + new_str)