• Jun 1, 2023 •CodeCatch
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from colorama import init, Fore # Initialize colorama init() print(Fore.RED + "This text is in red color.") print(Fore.GREEN + "This text is in green color.") print(Fore.BLUE + "This text is in blue color.") # Reset colorama print(Fore.RESET + "This text is back to the default color.")
• Nov 19, 2022 •CodeCatch
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# Python program for implementation of Radix Sort # A function to do counting sort of arr[] according to # the digit represented by exp. def countingSort(arr, exp1): n = len(arr) # The output array elements that will have sorted arr output = [0] * (n) # initialize count array as 0 count = [0] * (10) # Store count of occurrences in count[] for i in range(0, n): index = (arr[i]/exp1) count[int((index)%10)] += 1 # Change count[i] so that count[i] now contains actual # position of this digit in output array for i in range(1,10): count[i] += count[i-1] # Build the output array i = n-1 while i>=0: index = (arr[i]/exp1) output[ count[ int((index)%10) ] - 1] = arr[i] count[int((index)%10)] -= 1 i -= 1 # Copying the output array to arr[], # so that arr now contains sorted numbers i = 0 for i in range(0,len(arr)): arr[i] = output[i] # Method to do Radix Sort def radixSort(arr): # Find the maximum number to know number of digits max1 = max(arr) # Do counting sort for every digit. Note that instead # of passing digit number, exp is passed. exp is 10^i # where i is current digit number exp = 1 while max1/exp > 0: countingSort(arr,exp) exp *= 10 # Driver code to test above arr = [ 170, 45, 75, 90, 802, 24, 2, 66] radixSort(arr) for i in range(len(arr)): print(arr[i]),
• Aug 1, 2025 •AustinLeath
0 likes • 3 views
import re _proposal_regex = r'(?:(?:(IKE|ESP):)?[\w/]+(?:/NO_EXT_SEQ)?(?:, ?(IKE|ESP):[\w/]+(?:/NO_EXT_SEQ)?)*)?' _proposals_re = rf'(?P<proposals>{_proposal_regex}|)' pattern = rf'received proposals: {_proposals_re}' match = re.match(pattern, 'received proposals: ') print(match.group('proposals') if match else "No match") # Prints "No match"
• Nov 18, 2022 •AustinLeath
mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0} # How to sort a dict by value Python 3> sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))} print(sort) # How to sort a dict by key Python 3> sort = {key:mydict[key] for key in sorted(mydict.keys())} print(sort)
• May 5, 2026 •CodeCatch
0 likes • 12 views
0 likes • 10 views