• Mar 10, 2021 •Skrome
0 likes • 3 views
color2 = (60, 74, 172) color1 = (19, 28, 87) percent = 1.0 for i in range(101): resultRed = round(color1[0] + percent * (color2[0] - color1[0])) resultGreen = round(color1[1] + percent * (color2[1] - color1[1])) resultBlue = round(color1[2] + percent * (color2[2] - color1[2])) print((resultRed, resultGreen, resultBlue)) percent -= 0.01
• Jun 1, 2023 •CodeCatch
0 likes • 4 views
bytes_data = b'Hello, World!' string_data = bytes_data.decode('utf-8') print("String:", string_data)
• May 5, 2026 •CodeCatch
0 likes • 1 view
{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}
• Oct 4, 2023 •AustinLeath
0 likes • 12 views
weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))
def binary_search(arr, target): low = 0 high = len(arr) - 1 while low <= high: mid = (low + high) // 2 if arr[mid] == target: return mid elif arr[mid] < target: low = mid + 1 else: high = mid - 1 return -1
• Nov 19, 2022 •CodeCatch
# Python code to demonstrate # method to remove i'th character # Naive Method # Initializing String test_str = "CodeCatch" # Printing original string print ("The original string is : " + test_str) # Removing char at pos 3 # using loop new_str = "" for i in range(len(test_str)): if i != 2: new_str = new_str + test_str[i] # Printing string after removal print ("The string after removal of i'th character : " + new_str)