• Feb 26, 2023 •wabdelh
0 likes • 4 views
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Jun 26, 2025 •AustinLeath
0 likes • 2 views
def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
• May 5, 2026 •CodeCatch
0 likes • 7 views
Python
0 likes • 9 views
import re def find_pattern(text, pattern): match = re.search(pattern, text) if match: return match.group() else: return 'No match found' text = 'Hello, world! This is a test.' pattern = r'world!.*test.' result = find_pattern(text, pattern) print(result)
• Nov 18, 2022 •AustinLeath
0 likes • 3 views
# List lst = [1, 2, 3, 'Alice', 'Alice'] # One-Liner indices = [i for i in range(len(lst)) if lst[i]=='Alice'] # Result print(indices) # [3, 4]
• Mar 26, 2023 •AustinLeath
0 likes • 1 view
import os # Get the current directory current_dir = os.getcwd() # Loop through each file in the current directory for filename in os.listdir(current_dir): # Check if the file name starts with a number followed by a period and a space if filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ': # Remove the number, period, and space from the file name new_filename = filename[3:] # Rename the file os.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))