""" Binary Search Algorithm 
----------------------------------------
"""
#iterative implementation of binary search in Python
def binary_search(a_list, item):
    """Performs iterative binary search to find the position of an integer in a given, sorted, list.
    a_list -- sorted list of integers
    item -- integer you are searching for the position of
    """
    first = 0
    last = len(a_list) - 1
    while first <= last:
        i = (first + last) / 2
        if a_list[i] == item:
            return ' found at position '.format(item=item, i=i)
        elif a_list[i] > item:
            last = i - 1
        elif a_list[i] < item:
            first = i + 1
        else:
            return ' not found in the list'.format(item=item)
#recursive implementation of binary search in Python
def binary_search_recursive(a_list, item):
    """Performs recursive binary search of an integer in a given, sorted, list.
    a_list -- sorted list of integers
    item -- integer you are searching for the position of
    """
    first = 0
    last = len(a_list) - 1
    if len(a_list) == 0:
        return ' was not found in the list'.format(item=item)
    else:
        i = (first + last) // 2
        if item == a_list[i]:
            return ' found'.format(item=item)
        else:
            if a_list[i] < item:
                return binary_search_recursive(a_list[i+1:], item)
            else:
                return binary_search_recursive(a_list[:i], item)

#Loop back to this point once code finishes
loop = 1
while (loop < 10):
#All the questions that the program asks the user
    noun = input("Choose a noun: ")
    p_noun = input("Choose a plural noun: ")
    noun2 = input("Choose a noun: ")
    place = input("Name a place: ")
    adjective = input("Choose an adjective (Describing word): ")
    noun3 = input("Choose a noun: ")
#Displays the story based on the users input
    print ("------------------------------------------")
    print ("Be kind to your",noun,"- footed", p_noun)
    print ("For a duck may be somebody's", noun2,",")
    print ("Be kind to your",p_noun,"in",place)
    print ("Where the weather is always",adjective,".")
    print ()
    print ("You may think that is this the",noun3,",")
    print ("Well it is.")
    print ("------------------------------------------")
#Loop back to "loop = 1"
    loop = loop + 1

primes=[]
products=[]

def prime(num):
    if num > 1:
        for i in range(2,num):
            if (num % i) == 0:
                return False
        else:
            primes.append(num)
            return True

for n in range(30,1000):
    if len(primes) >= 20:
        break;
    else:
        prime(n)

for previous, current in zip(primes[::2], primes[1::2]):
    products.append(previous * current)
    
print (products)

def get_ldap_user(member_cn, user, passwrd):
    '''
    Get an LDAP user and return the SAMAccountName
    '''
    #---- Setting up the Connection
    #account used for binding - Avoid putting these in version control
    bindDN = str(user) + "@unt.ad.unt.edu"
    bindPass = passwrd

    #set some tuneables for the LDAP library.
    ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)
    #ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)
    
    conn = ldap.initialize('ldaps://unt.ad.unt.edu')
    conn.protocol_version = 3
    conn.set_option(ldap.OPT_REFERRALS, 0)

    #authenticate the connection so that you can make additional queries
    try:
        result = conn.simple_bind_s(bindDN, bindPass) 
    except ldap.INVALID_CREDENTIALS:
        result = "Invalid credentials for %s" % user
        sys.exit()

    #build query in the form of (uid=user)
    ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'
    ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)
    sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")
    return sAMAccountName

# Python program for implementation of Bubble Sort

def bubbleSort(arr):
	n = len(arr)

	# Traverse through all array elements
	for i in range(n-1):
	# range(n) also work but outer loop will repeat one time more than needed.

		# Last i elements are already in place
		for j in range(0, n-i-1):

			# traverse the array from 0 to n-i-1
			# Swap if the element found is greater
			# than the next element
			if arr[j] > arr[j+1] :
				arr[j], arr[j+1] = arr[j+1], arr[j]

# Driver code to test above
arr = [64, 34, 25, 12, 22, 11, 90]

bubbleSort(arr)

print ("Sorted array is:")
for i in range(len(arr)):
	print ("%d" %arr[i]),

def format_timestamp(timestamp_epoch):
    """
    Convert epoch timestamp to formatted datetime string without using datetime package.
    
    Args:
        timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC)
        
    Returns:
        str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format
    """
    # Constants for time calculations
    SECONDS_PER_DAY = 86400
    SECONDS_PER_HOUR = 3600
    SECONDS_PER_MINUTE = 60
    
    # Handle negative timestamps and convert to integer
    timestamp = int(timestamp_epoch)
    
    # Calculate days since epoch and remaining seconds
    days_since_epoch = timestamp // SECONDS_PER_DAY
    remaining_seconds = timestamp % SECONDS_PER_DAY
    
    # Calculate hours, minutes, seconds
    hours = remaining_seconds // SECONDS_PER_HOUR
    remaining_seconds %= SECONDS_PER_HOUR
    minutes = remaining_seconds // SECONDS_PER_MINUTE
    seconds = remaining_seconds % SECONDS_PER_MINUTE
    
    # Calculate date (simplified, ignoring leap seconds)
    year = 1970
    days = days_since_epoch
    while days >= 365:
        is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)
        days_in_year = 366 if is_leap else 365
        if days >= days_in_year:
            days -= days_in_year
            year += 1
    
    # Month lengths (non-leap year for simplicity, adjusted later for leap years)
    month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        month_lengths[1] = 29
    
    month = 0
    while days >= month_lengths[month]:
        days -= month_lengths[month]
        month += 1
    
    # Convert to 1-based indexing for month and day
    month += 1
    day = days + 1
    
    # Format the output string
    return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}"

# Example timestamp (Unix epoch seconds)
timestamp = 1697054700
formatted_date = format_timestamp(timestamp)
print(formatted_date + " UTC")  # Output: 2023-10-11 18:45:00