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Lonely Integer

Feb 26, 2023wabdelh
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More Python Posts

Untitled

Sep 14, 2024rgannedo-6205

0 likes • 4 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")

print indices

Nov 18, 2022AustinLeath

0 likes • 0 views

# List
lst = [1, 2, 3, 'Alice', 'Alice']
# One-Liner
indices = [i for i in range(len(lst)) if lst[i]=='Alice']
# Result
print(indices)
# [3, 4]

Read Dataset from excel file

Oct 7, 2022KETRICK

0 likes • 0 views

import pandas as pd
x = pd.read_excel(FILE_NAME)
print(x)

Differentiate Between type() and instance()

May 31, 2023CodeCatch

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class Rectangle:
pass
class Square(Rectangle):
pass
rectangle = Rectangle()
square = Square()
print(isinstance(rectangle, Rectangle)) # True
print(isinstance(square, Rectangle)) # True
print(isinstance(square, Square)) # True
print(isinstance(rectangle, Square)) # False

find parity outliers

Nov 19, 2022CodeCatch

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from collections import Counter
def find_parity_outliers(nums):
return [
x for x in nums
if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]
]
find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]

Sieve of Eratosthenes

Nov 19, 2022CodeCatch

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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.
# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.
# Python program to print all primes smaller than or equal to
# n using Sieve of Eratosthenes
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and initialize
# all entries it as true. A value in prime[i] will
# finally be false if i is Not a prime, else true.
prime = [True for i in range(n + 1)]
p = 2
while (p * p <= n):
# If prime[p] is not changed, then it is a prime
if (prime[p] == True):
# Update all multiples of p
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
# Print all prime numbers
for p in range(n + 1):
if prime[p]:
print (p)
# driver program
if __name__=='__main__':
n = 30
print("Following are the prime numbers smaller")
print("than or equal to ", n)
print("than or equal to ", n)
SieveOfEratosthenes(n)