• Aug 12, 2024 •AustinLeath
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magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits) sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits)) print("64 bit sum:", magnitude(64) * sign(64)) print("32 bit sum:", magnitude(32) * sign(32)) print("16 bit sum:", magnitude(16) * sign(16))
• Dec 24, 2025 •CodeCatch
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• Nov 19, 2022 •CodeCatch
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def print_pyramid_pattern(n): # outer loop to handle number of rows # n in this case for i in range(0, n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range(0, i+1): # printing stars print("* ",end="") # ending line after each row print("\r") print_pyramid_pattern(10)
#Loop back to this point once code finishes loop = 1 while (loop < 10): #All the questions that the program asks the user noun = input("Choose a noun: ") p_noun = input("Choose a plural noun: ") noun2 = input("Choose a noun: ") place = input("Name a place: ") adjective = input("Choose an adjective (Describing word): ") noun3 = input("Choose a noun: ") #Displays the story based on the users input print ("------------------------------------------") print ("Be kind to your",noun,"- footed", p_noun) print ("For a duck may be somebody's", noun2,",") print ("Be kind to your",p_noun,"in",place) print ("Where the weather is always",adjective,".") print () print ("You may think that is this the",noun3,",") print ("Well it is.") print ("------------------------------------------") #Loop back to "loop = 1" loop = loop + 1
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()