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print colored text to IDE terminal

Jun 1, 2023CodeCatch
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Bitwise Lambda Overflow Calculations

Aug 12, 2024AustinLeath

0 likes • 5 views

magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits)
sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits))
print("64 bit sum:", magnitude(64) * sign(64))
print("32 bit sum:", magnitude(32) * sign(32))
print("16 bit sum:", magnitude(16) * sign(16))

Multiply Two Matrices

May 31, 2023CodeCatch

0 likes • 0 views

# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)

when predicate lambda

Nov 19, 2022CodeCatch

0 likes • 6 views

def when(predicate, when_true):
return lambda x: when_true(x) if predicate(x) else x
double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)
print(double_even_numbers(2)) # 4
print(double_even_numbers(1)) # 1

Sherlock Holmes Curious Lockbox Solver

Mar 12, 2021LeifMessinger

0 likes • 0 views

import copy
begining = [False,False,False,False,False,None,True,True,True,True,True]
#False = black True = white
its = [0]
def swap(layout, step):
layoutCopy = copy.deepcopy(layout)
layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]
return layoutCopy
def isSolved(layout):
for i in range(len(layout)):
if(layout[i] == False):
return (i >= (len(layout)/2))
def recurse(layout, its, steps = []):
if isSolved(layout):
its[0] += 1
print(layout,list(x[0] for x in steps))
return
step = None
for i in range(len(layout)):
if(layout[i] == None):
if(i >= 1): #If the empty space could have something to the left
if(layout[i - 1] == False):
step = [-1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i > 1): #If the empty space could have something 2 to the left
if(layout[i - 2] == False):
step = [-2,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-1)): #If the empty space could have something to the right
if(layout[i + 1] == True):
step = [1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-2)): #If the empty space could have something to the right
if(layout[i + 2] == True):
step = [2,i]
recurse(swap(layout,step), its, (steps+[step]))
its[0] += 1
#return None
recurse(begining,its,[])
print(its[0])

Compute all the Permutation of a String

May 31, 2023CodeCatch

0 likes • 2 views

import itertools
def compute_permutations(string):
# Generate all permutations of the string
permutations = itertools.permutations(string)
# Convert each permutation tuple to a string
permutations = [''.join(permutation) for permutation in permutations]
return permutations
# Prompt the user for a string
string = input("Enter a string: ")
# Compute permutations
permutations = compute_permutations(string)
# Display the permutations
print("Permutations:")
for permutation in permutations:
print(permutation)

Hello World

Sep 9, 2023AustinLeath

0 likes • 23 views

print("test")