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Size of tuple

Nov 19, 2022CodeCatch
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return multiple values from a function

Jun 1, 2023CodeCatch

0 likes • 2 views

def calculate_values():
value1 = 10
value2 = 20
return value1, value2
result1, result2 = calculate_values()
print("Result 1:", result1)
print("Result 2:", result2)

integer to roman numeral

Nov 19, 2022CodeCatch

0 likes • 1 view

def to_roman_numeral(num):
lookup = [
(1000, 'M'),
(900, 'CM'),
(500, 'D'),
(400, 'CD'),
(100, 'C'),
(90, 'XC'),
(50, 'L'),
(40, 'XL'),
(10, 'X'),
(9, 'IX'),
(5, 'V'),
(4, 'IV'),
(1, 'I'),
]
res = ''
for (n, roman) in lookup:
(d, num) = divmod(num, n)
res += roman * d
return res
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

Binary search

Sep 22, 2023AustinLeath

0 likes • 24 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")

Hello World

Sep 9, 2023AustinLeath

0 likes • 22 views

print("test")

UNT CSCE 2100 Question 1

Nov 18, 2022AustinLeath

0 likes • 8 views

#question1.py
def rose(n) :
if n==0 :
yield []
else :
for k in range(0,n) :
for l in rose(k) :
for r in rose(n-1-k) :
yield [l]+[r]+[r]
def start(n) :
for x in rose(n) :
print(x) #basically I am printing x for each rose(n) file
print("starting program: \n")
start(2) # here is where I call the start function

Compute all the Permutation of a String

May 31, 2023CodeCatch

0 likes • 2 views

import itertools
def compute_permutations(string):
# Generate all permutations of the string
permutations = itertools.permutations(string)
# Convert each permutation tuple to a string
permutations = [''.join(permutation) for permutation in permutations]
return permutations
# Prompt the user for a string
string = input("Enter a string: ")
# Compute permutations
permutations = compute_permutations(string)
# Display the permutations
print("Permutations:")
for permutation in permutations:
print(permutation)