import pandas as pd



x = pd.read_excel(FILE_NAME)

print(x)

print("hellur")

from colorama import init, Fore

# Initialize colorama
init()

print(Fore.RED + "This text is in red color.")
print(Fore.GREEN + "This text is in green color.")
print(Fore.BLUE + "This text is in blue color.")

# Reset colorama
print(Fore.RESET + "This text is back to the default color.")

def to_roman_numeral(num):
  lookup = [
    (1000, 'M'),
    (900, 'CM'),
    (500, 'D'),
    (400, 'CD'),
    (100, 'C'),
    (90, 'XC'),
    (50, 'L'),
    (40, 'XL'),
    (10, 'X'),
    (9, 'IX'),
    (5, 'V'),
    (4, 'IV'),
    (1, 'I'),
  ]
  res = ''
  for (n, roman) in lookup:
    (d, num) = divmod(num, n)
    res += roman * d
  return res

to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

""" Rock Paper Scissors
----------------------------------------
"""
import random
import os
import re
os.system('cls' if os.name=='nt' else 'clear')
while (1 < 2):
    print "\n"
    print "Rock, Paper, Scissors - Shoot!"
    userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ")
    if not re.match("[SsRrPp]", userChoice):
        print "Please choose a letter:"
        print "[R]ock, [S]cissors or [P]aper."
        continue
    // Echo the user's choice
    print "You chose: " + userChoice
    choices = ['R', 'P', 'S']
    opponenetChoice = random.choice(choices)
    print "I chose: " + opponenetChoice
    if opponenetChoice == str.upper(userChoice):
        print "Tie! "
    #if opponenetChoice == str("R") and str.upper(userChoice) == "P"
    elif opponenetChoice == 'R' and userChoice.upper() == 'S':      
        print "Scissors beats rock, I win! "
        continue
    elif opponenetChoice == 'S' and userChoice.upper() == 'P':      
        print "Scissors beats paper! I win! "
        continue
    elif opponenetChoice == 'P' and userChoice.upper() == 'R':      
        print "Paper beat rock, I win! "
        continue
    else:       
        print "You win!"

def max_n(lst, n = 1):
  return sorted(lst, reverse = True)[:n]

max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]