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print("hellur")
# Python program for Bitonic Sort. Note that this program# works only when size of input is a power of 2.# The parameter dir indicates the sorting direction, ASCENDING# or DESCENDING; if (a[i] > a[j]) agrees with the direction,# then a[i] and a[j] are interchanged.*/def compAndSwap(a, i, j, dire):if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] > a[j]):a[i],a[j] = a[j],a[i]# It recursively sorts a bitonic sequence in ascending order,# if dir = 1, and in descending order otherwise (means dir=0).# The sequence to be sorted starts at index position low,# the parameter cnt is the number of elements to be sorted.def bitonicMerge(a, low, cnt, dire):if cnt > 1:k = cnt/2for i in range(low , low+k):compAndSwap(a, i, i+k, dire)bitonicMerge(a, low, k, dire)bitonicMerge(a, low+k, k, dire)# This funcion first produces a bitonic sequence by recursively# sorting its two halves in opposite sorting orders, and then# calls bitonicMerge to make them in the same orderdef bitonicSort(a, low, cnt,dire):if cnt > 1:k = cnt/2bitonicSort(a, low, k, 1)bitonicSort(a, low+k, k, 0)bitonicMerge(a, low, cnt, dire)# Caller of bitonicSort for sorting the entire array of length N# in ASCENDING orderdef sort(a,N, up):bitonicSort(a,0, N, up)# Driver code to test abovea = [3, 7, 4, 8, 6, 2, 1, 5]n = len(a)up = 1sort(a, n, up)print ("\n\nSorted array is")for i in range(n):print("%d" %a[i]),
def generate_pascals_triangle(num_rows):triangle = []for row in range(num_rows):# Initialize the row with 1current_row = [1]# Calculate the values for the current rowif row > 0:previous_row = triangle[row - 1]for i in range(len(previous_row) - 1):current_row.append(previous_row[i] + previous_row[i + 1])# Append 1 at the end of the rowcurrent_row.append(1)# Add the current row to the triangletriangle.append(current_row)return triangledef display_pascals_triangle(triangle):for row in triangle:for number in row:print(number, end=" ")print()# Prompt the user for the number of rowsnum_rows = int(input("Enter the number of rows for Pascal's Triangle: "))# Generate Pascal's Trianglepascals_triangle = generate_pascals_triangle(num_rows)# Display Pascal's Triangledisplay_pascals_triangle(pascals_triangle)
from collections import defaultdictdef combine_values(*dicts):res = defaultdict(list)for d in dicts:for key in d:res[key].append(d[key])return dict(res)d1 = {'a': 1, 'b': 'foo', 'c': 400}d2 = {'a': 3, 'b': 200, 'd': 400}combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}
primes=[]products=[]def prime(num):if num > 1:for i in range(2,num):if (num % i) == 0:return Falseelse:primes.append(num)return Truefor n in range(30,1000):if len(primes) >= 20:break;else:prime(n)for previous, current in zip(primes[::2], primes[1::2]):products.append(previous * current)print (products)
import itertoolsimport stringimport timedef guess_password(real):chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuationattempts = 0for password_length in range(1, 9):for guess in itertools.product(chars, repeat=password_length):startTime = time.time()attempts += 1guess = ''.join(guess)if guess == real:return 'password is {}. found in {} guesses.'.format(guess, attempts)loopTime = (time.time() - startTime);print(guess, attempts, loopTime)print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n")val = input("Enter a password you want to crack that is 9 characters or below: ")print(guess_password(val.lower()))