Skip to main content

delay time lambda

0 likes • Nov 19, 2022 • 0 views
Python
Loading...

More Python Posts

get LDAP user

0 likes • Nov 18, 2022 • 0 views
Python
def get_ldap_user(member_cn, user, passwrd):
'''
Get an LDAP user and return the SAMAccountName
'''
#---- Setting up the Connection
#account used for binding - Avoid putting these in version control
bindDN = str(user) + "@unt.ad.unt.edu"
bindPass = passwrd
#set some tuneables for the LDAP library.
ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)
#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)
conn = ldap.initialize('ldaps://unt.ad.unt.edu')
conn.protocol_version = 3
conn.set_option(ldap.OPT_REFERRALS, 0)
#authenticate the connection so that you can make additional queries
try:
result = conn.simple_bind_s(bindDN, bindPass)
except ldap.INVALID_CREDENTIALS:
result = "Invalid credentials for %s" % user
sys.exit()
#build query in the form of (uid=user)
ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'
ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)
sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")
return sAMAccountName

Fibonacci Series

0 likes • Nov 18, 2022 • 5 views
Python
#Python 3: Fibonacci series up to n
def fib(n):
a, b = 0, 1
while a < n:
print(a, end=' ')
a, b = b, a+b
print()
fib(1000)

Bubble sort

0 likes • Nov 19, 2022 • 0 views
Python
# Python program for implementation of Bubble Sort
def bubbleSort(arr):
n = len(arr)
# Traverse through all array elements
for i in range(n-1):
# range(n) also work but outer loop will repeat one time more than needed.
# Last i elements are already in place
for j in range(0, n-i-1):
# traverse the array from 0 to n-i-1
# Swap if the element found is greater
# than the next element
if arr[j] > arr[j+1] :
arr[j], arr[j+1] = arr[j+1], arr[j]
# Driver code to test above
arr = [64, 34, 25, 12, 22, 11, 90]
bubbleSort(arr)
print ("Sorted array is:")
for i in range(len(arr)):
print ("%d" %arr[i]),

Plotting Fibonacci

0 likes • Nov 19, 2022 • 0 views
Python
# Python program for Plotting Fibonacci
# spiral fractal using Turtle
import turtle
import math
def fiboPlot(n):
a = 0
b = 1
square_a = a
square_b = b
# Setting the colour of the plotting pen to blue
x.pencolor("blue")
# Drawing the first square
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
# Proceeding in the Fibonacci Series
temp = square_b
square_b = square_b + square_a
square_a = temp
# Drawing the rest of the squares
for i in range(1, n):
x.backward(square_a * factor)
x.right(90)
x.forward(square_b * factor)
x.left(90)
x.forward(square_b * factor)
x.left(90)
x.forward(square_b * factor)
# Proceeding in the Fibonacci Series
temp = square_b
square_b = square_b + square_a
square_a = temp
# Bringing the pen to starting point of the spiral plot
x.penup()
x.setposition(factor, 0)
x.seth(0)
x.pendown()
# Setting the colour of the plotting pen to red
x.pencolor("red")
# Fibonacci Spiral Plot
x.left(90)
for i in range(n):
print(b)
fdwd = math.pi * b * factor / 2
fdwd /= 90
for j in range(90):
x.forward(fdwd)
x.left(1)
temp = a
a = b
b = temp + b
# Here 'factor' signifies the multiplicative
# factor which expands or shrinks the scale
# of the plot by a certain factor.
factor = 1
# Taking Input for the number of
# Iterations our Algorithm will run
n = int(input('Enter the number of iterations (must be > 1): '))
# Plotting the Fibonacci Spiral Fractal
# and printing the corresponding Fibonacci Number
if n > 0:
print("Fibonacci series for", n, "elements :")
x = turtle.Turtle()
x.speed(100)
fiboPlot(n)
turtle.done()
else:
print("Number of iterations must be > 0")

combine values

0 likes • Nov 19, 2022 • 0 views
Python
from collections import defaultdict
def combine_values(*dicts):
res = defaultdict(list)
for d in dicts:
for key in d:
res[key].append(d[key])
return dict(res)
d1 = {'a': 1, 'b': 'foo', 'c': 400}
d2 = {'a': 3, 'b': 200, 'd': 400}
combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}

check prop lambda

0 likes • Nov 19, 2022 • 0 views
Python
def check_prop(fn, prop):
return lambda obj: fn(obj[prop])
check_age = check_prop(lambda x: x >= 18, 'age')
user = {'name': 'Mark', 'age': 18}
check_age(user) # True