Reverse a linked list
0 likes • Nov 19, 2022
Python
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# question3.pyfrom itertools import productV='∀'E='∃'def tt(f,n) :xss=product((0,1),repeat=n)print('function:',f.__name__)for xs in xss : print(*xs,':',int(f(*xs)))print('')# this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r)def parta(p,q,r) :a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r)b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)c= a and breturn cdef partb(p,q,r) :a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r)b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)c= a and breturn cprint("part A:")tt(parta,3)print("part B:")tt(partb,3)
# Python Program to calculate the square rootnum = float(input('Enter a number: '))num_sqrt = num ** 0.5print('The square root of %0.3f is %0.3f'%(num ,num_sqrt))
primes=[]products=[]def prime(num):if num > 1:for i in range(2,num):if (num % i) == 0:return Falseelse:primes.append(num)return Truefor n in range(30,1000):if len(primes) >= 20:break;else:prime(n)for previous, current in zip(primes[::2], primes[1::2]):products.append(previous * current)print (products)
def max_n(lst, n = 1):return sorted(lst, reverse = True)[:n]max_n([1, 2, 3]) # [3]max_n([1, 2, 3], 2) # [3, 2]
color2 = (60, 74, 172)color1 = (19, 28, 87)percent = 1.0for i in range(101):resultRed = round(color1[0] + percent * (color2[0] - color1[0]))resultGreen = round(color1[1] + percent * (color2[1] - color1[1]))resultBlue = round(color1[2] + percent * (color2[2] - color1[2]))print((resultRed, resultGreen, resultBlue))percent -= 0.01
def get_ldap_user(member_cn, user, passwrd):'''Get an LDAP user and return the SAMAccountName'''#---- Setting up the Connection#account used for binding - Avoid putting these in version controlbindDN = str(user) + "@unt.ad.unt.edu"bindPass = passwrd#set some tuneables for the LDAP library.ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)conn = ldap.initialize('ldaps://unt.ad.unt.edu')conn.protocol_version = 3conn.set_option(ldap.OPT_REFERRALS, 0)#authenticate the connection so that you can make additional queriestry:result = conn.simple_bind_s(bindDN, bindPass)except ldap.INVALID_CREDENTIALS:result = "Invalid credentials for %s" % usersys.exit()#build query in the form of (uid=user)ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")return sAMAccountName