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Reverse a linked list

0 likes • Nov 19, 2022
Python
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CSCE 2100 Question 3

AustinLeath
0 likes • Nov 18, 2022
Python
# question3.py
from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r)
def parta(p,q,r) :
a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r)
b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)
c= a and b
return c
def partb(p,q,r) :
a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r)
b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)
c= a and b
return c
print("part A:")
tt(parta,3)
print("part B:")
tt(partb,3)

Calculate Square Root

AustinLeath
0 likes • Nov 18, 2022
Python
# Python Program to calculate the square root
num = float(input('Enter a number: '))
num_sqrt = num ** 0.5
print('The square root of %0.3f is %0.3f'%(num ,num_sqrt))

Distinct Primes Finder > 1000

AustinLeath
0 likes • Nov 18, 2022
Python
primes=[]
products=[]
def prime(num):
if num > 1:
for i in range(2,num):
if (num % i) == 0:
return False
else:
primes.append(num)
return True
for n in range(30,1000):
if len(primes) >= 20:
break;
else:
prime(n)
for previous, current in zip(primes[::2], primes[1::2]):
products.append(previous * current)
print (products)

return maximum

CodeCatch
0 likes • Nov 19, 2022
Python
def max_n(lst, n = 1):
return sorted(lst, reverse = True)[:n]
max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]

Color Gradient

Skrome
0 likes • Mar 10, 2021
Python
color2 = (60, 74, 172)
color1 = (19, 28, 87)
percent = 1.0
for i in range(101):
resultRed = round(color1[0] + percent * (color2[0] - color1[0]))
resultGreen = round(color1[1] + percent * (color2[1] - color1[1]))
resultBlue = round(color1[2] + percent * (color2[2] - color1[2]))
print((resultRed, resultGreen, resultBlue))
percent -= 0.01

get LDAP user

AustinLeath
0 likes • Nov 18, 2022
Python
def get_ldap_user(member_cn, user, passwrd):
'''
Get an LDAP user and return the SAMAccountName
'''
#---- Setting up the Connection
#account used for binding - Avoid putting these in version control
bindDN = str(user) + "@unt.ad.unt.edu"
bindPass = passwrd
#set some tuneables for the LDAP library.
ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)
#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)
conn = ldap.initialize('ldaps://unt.ad.unt.edu')
conn.protocol_version = 3
conn.set_option(ldap.OPT_REFERRALS, 0)
#authenticate the connection so that you can make additional queries
try:
result = conn.simple_bind_s(bindDN, bindPass)
except ldap.INVALID_CREDENTIALS:
result = "Invalid credentials for %s" % user
sys.exit()
#build query in the form of (uid=user)
ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'
ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)
sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")
return sAMAccountName