• May 31, 2023 •CodeCatch
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def generate_pascals_triangle(num_rows): triangle = [] for row in range(num_rows): # Initialize the row with 1 current_row = [1] # Calculate the values for the current row if row > 0: previous_row = triangle[row - 1] for i in range(len(previous_row) - 1): current_row.append(previous_row[i] + previous_row[i + 1]) # Append 1 at the end of the row current_row.append(1) # Add the current row to the triangle triangle.append(current_row) return triangle def display_pascals_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Pascal's Triangle: ")) # Generate Pascal's Triangle pascals_triangle = generate_pascals_triangle(num_rows) # Display Pascal's Triangle display_pascals_triangle(pascals_triangle)
• Nov 19, 2022 •CodeCatch
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from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number. # For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”. # Python program to print all primes smaller than or equal to # n using Sieve of Eratosthenes def SieveOfEratosthenes(n): # Create a boolean array "prime[0..n]" and initialize # all entries it as true. A value in prime[i] will # finally be false if i is Not a prime, else true. prime = [True for i in range(n + 1)] p = 2 while (p * p <= n): # If prime[p] is not changed, then it is a prime if (prime[p] == True): # Update all multiples of p for i in range(p * 2, n + 1, p): prime[i] = False p += 1 prime[0]= False prime[1]= False # Print all prime numbers for p in range(n + 1): if prime[p]: print (p) # driver program if __name__=='__main__': n = 30 print("Following are the prime numbers smaller") print("than or equal to ", n) print("than or equal to ", n) SieveOfEratosthenes(n)
• Mar 12, 2021 •mo_ak
prime_lists=[] # a list to store the prime numbers def prime(n): # define prime numbers if n <= 1: return False # divide n by 2... up to n-1 for i in range(2, n): if n % i == 0: # the remainder should'nt be a 0 return False else: prime_lists.append(n) return True for n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30 prime(n) check=0 # a var to limit the output to 10 only for n in prime_lists: for x in prime_lists: val= n *x if (val > 1000 ): check=check +1 if (check <10) : print("the num is:", val , "=",n , "* ", x ) break
• Dec 24, 2025 •CodeCatch
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def counting_sort(arr, exp): n = len(arr) output = [0] * n count = [0] * 10 for i in range(n): index = (arr[i] // exp) % 10 count[index] += 1 for i in range(1, 10): count[i] += count[i-1] i = n - 1 while i >= 0: index = (arr[i] // exp) % 10 output[count[index] - 1] = arr[i] count[index] -= 1 i -= 1 for i in range(n): arr[i] = output[i] def radix_sort(arr): max_val = max(arr) exp = 1 while max_val // exp > 0: counting_sort(arr, exp) exp *= 10 if __name__ == "__main__": arr = [170, 45, 75, 90, 802, 24, 2, 66] print("Original array:", arr) radix_sort(arr) print("Sorted array:", arr)
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# Python program for implementation of Bubble Sort def bubbleSort(arr): n = len(arr) # Traverse through all array elements for i in range(n-1): # range(n) also work but outer loop will repeat one time more than needed. # Last i elements are already in place for j in range(0, n-i-1): # traverse the array from 0 to n-i-1 # Swap if the element found is greater # than the next element if arr[j] > arr[j+1] : arr[j], arr[j+1] = arr[j+1], arr[j] # Driver code to test above arr = [64, 34, 25, 12, 22, 11, 90] bubbleSort(arr) print ("Sorted array is:") for i in range(len(arr)): print ("%d" %arr[i]),