• Nov 19, 2022 •CodeCatch
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def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
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# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()
• Jun 16, 2024 •lagiath
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print('hello, world')
from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
# Python program for implementation of Radix Sort # A function to do counting sort of arr[] according to # the digit represented by exp. def countingSort(arr, exp1): n = len(arr) # The output array elements that will have sorted arr output = [0] * (n) # initialize count array as 0 count = [0] * (10) # Store count of occurrences in count[] for i in range(0, n): index = (arr[i]/exp1) count[int((index)%10)] += 1 # Change count[i] so that count[i] now contains actual # position of this digit in output array for i in range(1,10): count[i] += count[i-1] # Build the output array i = n-1 while i>=0: index = (arr[i]/exp1) output[ count[ int((index)%10) ] - 1] = arr[i] count[int((index)%10)] -= 1 i -= 1 # Copying the output array to arr[], # so that arr now contains sorted numbers i = 0 for i in range(0,len(arr)): arr[i] = output[i] # Method to do Radix Sort def radixSort(arr): # Find the maximum number to know number of digits max1 = max(arr) # Do counting sort for every digit. Note that instead # of passing digit number, exp is passed. exp is 10^i # where i is current digit number exp = 1 while max1/exp > 0: countingSort(arr,exp) exp *= 10 # Driver code to test above arr = [ 170, 45, 75, 90, 802, 24, 2, 66] radixSort(arr) for i in range(len(arr)): print(arr[i]),