• Nov 19, 2022 •CodeCatch
0 likes • 11 views
""" Currency Converter ---------------------------------------- """ import urllib.request import json def currency_converter(currency_from, currency_to, currency_input): yql_base_url = "https://query.yahooapis.com/v1/public/yql" yql_query = 'select%20*%20from%20yahoo.finance.xchange%20where%20pair' \ '%20in%20("'+currency_from+currency_to+'")' yql_query_url = yql_base_url + "?q=" + yql_query + "&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys" try: yql_response = urllib.request.urlopen(yql_query_url) try: json_string = str(yql_response.read()) json_string = json_string[2: json_string = json_string[:-1] print(json_string) yql_json = json.loads(json_string) last_rate = yql_json['query']['results']['rate']['Rate'] currency_output = currency_input * float(last_rate) return currency_output except (ValueError, KeyError, TypeError): print(yql_query_url) return "JSON format error" except IOError as e: print(str(e)) currency_input = 1 #currency codes : http://en.wikipedia.org/wiki/ISO_4217 currency_from = "USD" currency_to = "TRY" rate = currency_converter(currency_from, currency_to, currency_input) print(rate)
• Sep 6, 2020 •C S
0 likes • 3 views
def Fibonacci(n): if n<0: print("Incorrect input") # First Fibonacci number is 0 elif n==1: return 0 # Second Fibonacci number is 1 elif n==2: return 1 else: return Fibonacci(n-1)+Fibonacci(n-2) # Driver Program print(Fibonacci(9))
• May 31, 2023 •CodeCatch
0 likes • 5 views
import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
• Oct 15, 2022 •CodeCatch
1 like • 2 views
my_list = ["blue", "red", "green"] #1- Using sort or srted directly or with specifc keys my_list.sort() #sorts alphabetically or in an ascending order for numeric data my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest. # You can use reverse=True to flip the order #2- Using locale and functools import locale from functools import cmp_to_key my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
• Nov 18, 2022 •AustinLeath
0 likes • 14 views
# question3.py from itertools import product V='∀' E='∃' def tt(f,n) : xss=product((0,1),repeat=n) print('function:',f.__name__) for xs in xss : print(*xs,':',int(f(*xs))) print('') # this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r) def parta(p,q,r) : a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c def partb(p,q,r) : a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c print("part A:") tt(parta,3) print("part B:") tt(partb,3)
0 likes • 1 view
def check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = check_prop(lambda x: x >= 18, 'age') user = {'name': 'Mark', 'age': 18} check_age(user) # True