• Nov 19, 2022 •CodeCatch
0 likes • 2 views
# Deleting all even numbers from a list a = [1,2,3,4,5] del a[1::2] print(a)
• Sep 3, 2025 •AustinLeath
0 likes • 5 views
import subprocess class CommandRunner: def run_command(self, command): command_process = subprocess.Popen(command, shell=True, stdout=subprocess.PIPE, text=True) output = command_process.communicate()[0].strip() return_code = command_process.returncode return output, return_code def main(): # Create instance of CommandRunner runner = CommandRunner() # Define the command command = 'ping -c 4 localhost' try: # Run the command and get output and return code output, return_code = runner.run_command(command) # Print the output and return code print(f"Command output:\n{output}") print(f"Return code: {return_code}") except Exception as e: print(f"An error occurred: {e}") if __name__ == "__main__": main()
• Jun 26, 2025 •AustinLeath
def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
• May 31, 2023 •CodeCatch
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my_list = [1, 2, 3, 4, 5] removed_element = my_list.pop(2) # Remove and return element at index 2 print(removed_element) # 3 print(my_list) # [1, 2, 4, 5] last_element = my_list.pop() # Remove and return the last element print(last_element) # 5 print(my_list) # [1, 2, 4]
0 likes • 4 views
def clamp_number(num, a, b): return max(min(num, max(a, b)), min(a, b)) clamp_number(2, 3, 5) # 3 clamp_number(1, -1, -5) # -1
• Jul 8, 2025 •AustinLeath
from datetime import datetime epoch_time = 1753823646 # Example epoch time (March 15, 2023 00:00:00 UTC) # Convert epoch time to a UTC datetime object utc_datetime = datetime.utcfromtimestamp(epoch_time) print(f"Epoch time: {epoch_time}") print(f"UTC datetime: {utc_datetime}") # You can also format the output string formatted_utc_time = utc_datetime.strftime('%m-%d-%Y %H:%M:%S UTC') print(f"Formatted UTC datetime: {formatted_utc_time}")