• May 31, 2023 •CodeCatch
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# Prompt user for a decimal number decimal = int(input("Enter a decimal number: ")) # Convert decimal to binary binary = bin(decimal) # Convert decimal to hexadecimal hexadecimal = hex(decimal) # Display the results print("Binary:", binary) print("Hexadecimal:", hexadecimal)
• Nov 19, 2022 •CodeCatch
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#Loop back to this point once code finishes loop = 1 while (loop < 10): #All the questions that the program asks the user noun = input("Choose a noun: ") p_noun = input("Choose a plural noun: ") noun2 = input("Choose a noun: ") place = input("Name a place: ") adjective = input("Choose an adjective (Describing word): ") noun3 = input("Choose a noun: ") #Displays the story based on the users input print ("------------------------------------------") print ("Be kind to your",noun,"- footed", p_noun) print ("For a duck may be somebody's", noun2,",") print ("Be kind to your",p_noun,"in",place) print ("Where the weather is always",adjective,".") print () print ("You may think that is this the",noun3,",") print ("Well it is.") print ("------------------------------------------") #Loop back to "loop = 1" loop = loop + 1
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import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
def print_pyramid_pattern(n): # outer loop to handle number of rows # n in this case for i in range(0, n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range(0, i+1): # printing stars print("* ",end="") # ending line after each row print("\r") print_pyramid_pattern(10)
• Nov 18, 2022 •AustinLeath
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primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)
# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))