• Nov 19, 2022 •CodeCatch
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def print_pyramid_pattern(n): # outer loop to handle number of rows # n in this case for i in range(0, n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range(0, i+1): # printing stars print("* ",end="") # ending line after each row print("\r") print_pyramid_pattern(10)
• May 5, 2026 •CodeCatch
{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}
• Jul 8, 2025 •AustinLeath
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from datetime import datetime epoch_time = 1753823646 # Example epoch time (March 15, 2023 00:00:00 UTC) # Convert epoch time to a UTC datetime object utc_datetime = datetime.utcfromtimestamp(epoch_time) print(f"Epoch time: {epoch_time}") print(f"UTC datetime: {utc_datetime}") # You can also format the output string formatted_utc_time = utc_datetime.strftime('%m-%d-%Y %H:%M:%S UTC') print(f"Formatted UTC datetime: {formatted_utc_time}")
• May 31, 2023 •CodeCatch
# Prompt user for a decimal number decimal = int(input("Enter a decimal number: ")) # Convert decimal to binary binary = bin(decimal) # Convert decimal to hexadecimal hexadecimal = hex(decimal) # Display the results print("Binary:", binary) print("Hexadecimal:", hexadecimal)
• Nov 18, 2022 •AustinLeath
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#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
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