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# question3.pyfrom itertools import productV='∀'E='∃'def tt(f,n) :xss=product((0,1),repeat=n)print('function:',f.__name__)for xs in xss : print(*xs,':',int(f(*xs)))print('')# this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r)def parta(p,q,r) :a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r)b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)c= a and breturn cdef partb(p,q,r) :a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r)b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)c= a and breturn cprint("part A:")tt(parta,3)print("part B:")tt(partb,3)
def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])sum_of_powers(10) # 385sum_of_powers(10, 3) # 3025sum_of_powers(10, 3, 5) # 2925
#Loop back to this point once code finishesloop = 1while (loop < 10):#All the questions that the program asks the usernoun = input("Choose a noun: ")p_noun = input("Choose a plural noun: ")noun2 = input("Choose a noun: ")place = input("Name a place: ")adjective = input("Choose an adjective (Describing word): ")noun3 = input("Choose a noun: ")#Displays the story based on the users inputprint ("------------------------------------------")print ("Be kind to your",noun,"- footed", p_noun)print ("For a duck may be somebody's", noun2,",")print ("Be kind to your",p_noun,"in",place)print ("Where the weather is always",adjective,".")print ()print ("You may think that is this the",noun3,",")print ("Well it is.")print ("------------------------------------------")#Loop back to "loop = 1"loop = loop + 1
def byte_size(s):return len(s.encode('utf-8'))byte_size('😀') # 4byte_size('Hello World') # 11
def print_pyramid_pattern(n):# outer loop to handle number of rows# n in this casefor i in range(0, n):# inner loop to handle number of columns# values changing acc. to outer loopfor j in range(0, i+1):# printing starsprint("* ",end="")# ending line after each rowprint("\r")print_pyramid_pattern(10)
#question1.pydef rose(n) :if n==0 :yield []else :for k in range(0,n) :for l in rose(k) :for r in rose(n-1-k) :yield [l]+[r]+[r]def start(n) :for x in rose(n) :print(x) #basically I am printing x for each rose(n) fileprint("starting program: \n")start(2) # here is where I call the start function