return multiple values from a function
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import random# Define the ranks, suits, and create a deckranks = ['Ace', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'Jack', 'Queen', 'King']suits = ['Hearts', 'Diamonds', 'Clubs', 'Spades']deck = [(rank, suit) for rank in ranks for suit in suits]# Shuffle the deckrandom.shuffle(deck)# Display the shuffled deckfor card in deck:print(card[0], "of", card[1])
def generate_pascals_triangle(num_rows):triangle = []for row in range(num_rows):# Initialize the row with 1current_row = [1]# Calculate the values for the current rowif row > 0:previous_row = triangle[row - 1]for i in range(len(previous_row) - 1):current_row.append(previous_row[i] + previous_row[i + 1])# Append 1 at the end of the rowcurrent_row.append(1)# Add the current row to the triangletriangle.append(current_row)return triangledef display_pascals_triangle(triangle):for row in triangle:for number in row:print(number, end=" ")print()# Prompt the user for the number of rowsnum_rows = int(input("Enter the number of rows for Pascal's Triangle: "))# Generate Pascal's Trianglepascals_triangle = generate_pascals_triangle(num_rows)# Display Pascal's Triangledisplay_pascals_triangle(pascals_triangle)
import stringdef caesar(text, shift, alphabets):def shift_alphabet(alphabet):return alphabet[shift:] + alphabet[:shift]shifted_alphabets = tuple(map(shift_alphabet, alphabets))final_alphabet = "".join(alphabets)final_shifted_alphabet = "".join(shifted_alphabets)table = str.maketrans(final_alphabet, final_shifted_alphabet)return text.translate(table)plain_text = "Hey Skrome, welcome to CodeCatch"print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))
#SetsU = {0,1,2,3,4,5,6,7,8,9}P = {1,2,3,4}Q = {4,5,6}R = {3,4,6,8,9}def set2bits(xs,us) :bs=[]for x in us :if x in xs :bs.append(1)else:bs.append(0)assert len(us) == len(bs)return bsdef union(set1,set2) :finalSet = set()bitList1 = set2bits(set1, U)bitList2 = set2bits(set2, U)for i in range(len(U)) :if(bitList1[i] or bitList2[i]) :finalSet.add(i)return finalSetdef intersection(set1,set2) :finalSet = set()bitList1 = set2bits(set1, U)bitList2 = set2bits(set2, U)for i in range(len(U)) :if(bitList1[i] and bitList2[i]) :finalSet.add(i)return finalSetdef compliment(set1) :finalSet = set()bitList = set2bits(set1, U)for i in range(len(U)) :if(not bitList[i]) :finalSet.add(i)return finalSetdef implication(a,b):return union(compliment(a), b)################################################################################################################# Problems 1-6 ###################################################################################################################################p \/ (q /\ r) = (p \/ q) /\ (p \/ r)def prob1():return union(P, intersection(Q,R)) == intersection(union(P,Q), union(P,R))#p /\ (q \/ r) = (p /\ q) \/ (p /\ r)def prob2():return intersection(P, union(Q,R)) == union(intersection(P,Q), intersection(P,R))#~(p /\ q) = ~p \/ ~qdef prob3():return compliment(intersection(P,R)) == union(compliment(P), compliment(R))#~(p \/ q) = ~p /\ ~qdef prob4():return compliment(union(P,Q)) == intersection(compliment(P), compliment(Q))#(p=>q) = (~q => ~p)def prob5():return implication(P,Q) == implication(compliment(Q), compliment(P))#(p => q) /\ (q => r) => (p => r)def prob6():return implication(intersection(implication(P,Q), implication(Q,R)), implication(P,R))print("Problem 1: ", prob1())print("Problem 2: ", prob2())print("Problem 3: ", prob3())print("Problem 4: ", prob4())print("Problem 5: ", prob5())print("Problem 6: ", prob6())'''Problem 1: TrueProblem 2: TrueProblem 3: TrueProblem 4: TrueProblem 5: TrueProblem 6: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}'''
def byte_size(s):return len(s.encode('utf-8'))byte_size('😀') # 4byte_size('Hello World') # 11
from time import sleepdef delay(fn, ms, *args):sleep(ms / 1000)return fn(*args)delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second