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# Python binary search functiondef binary_search(arr, target):left = 0right = len(arr) - 1while left <= right:mid = (left + right) // 2if arr[mid] == target:return midelif arr[mid] < target:left = mid + 1else:right = mid - 1return -1# Usagearr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]target = 7result = binary_search(arr, target)if result != -1:print(f"Element is present at index {result}")else:print("Element is not present in array")
my_list = [1, 2, 3, 4, 5]removed_element = my_list.pop(2) # Remove and return element at index 2print(removed_element) # 3print(my_list) # [1, 2, 4, 5]last_element = my_list.pop() # Remove and return the last elementprint(last_element) # 5print(my_list) # [1, 2, 4]
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)
#You are given a two-digit integer n. Return the sum of its digits.#Example#For n = 29 the output should be solution (n) = 11def solution(n):return (n//10 + n%10)
magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits)sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits))print("64 bit sum:", magnitude(64) * sign(64))print("32 bit sum:", magnitude(32) * sign(32))print("16 bit sum:", magnitude(16) * sign(16))
# Prompt user for a decimal numberdecimal = int(input("Enter a decimal number: "))# Convert decimal to binarybinary = bin(decimal)# Convert decimal to hexadecimalhexadecimal = hex(decimal)# Display the resultsprint("Binary:", binary)print("Hexadecimal:", hexadecimal)