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return multiple values from a function

Jun 1, 2023CodeCatch
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Calculator

Nov 19, 2022CodeCatch

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""" Calculator
----------------------------------------
"""
def addition ():
print("Addition")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 0
while n != 0:
ans = ans + n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def subtraction ():
print("Subtraction");
n = float(input("Enter the number: "))
t = 0 //Total number enter
sum = 0
while n != 0:
ans = ans - n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def multiplication ():
print("Multiplication")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 1
while n != 0:
ans = ans * n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def average():
an = []
an = addition()
t = an[1]
a = an[0]
ans = a / t
return [ans,t]
// main...
while True:
list = []
print(" My first python program!")
print(" Simple Calculator in python by Malik Umer Farooq")
print(" Enter 'a' for addition")
print(" Enter 's' for substraction")
print(" Enter 'm' for multiplication")
print(" Enter 'v' for average")
print(" Enter 'q' for quit")
c = input(" ")
if c != 'q':
if c == 'a':
list = addition()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 's':
list = subtraction()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'm':
list = multiplication()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'v':
list = average()
print("Ans = ", list[0], " total inputs ",list[1])
else:
print ("Sorry, invilid character")
else:
break

return maximum

Nov 19, 2022CodeCatch

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def max_n(lst, n = 1):
return sorted(lst, reverse = True)[:n]
max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]

Bubble sort

Nov 19, 2022CodeCatch

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# Python program for implementation of Bubble Sort
def bubbleSort(arr):
n = len(arr)
# Traverse through all array elements
for i in range(n-1):
# range(n) also work but outer loop will repeat one time more than needed.
# Last i elements are already in place
for j in range(0, n-i-1):
# traverse the array from 0 to n-i-1
# Swap if the element found is greater
# than the next element
if arr[j] > arr[j+1] :
arr[j], arr[j+1] = arr[j+1], arr[j]
# Driver code to test above
arr = [64, 34, 25, 12, 22, 11, 90]
bubbleSort(arr)
print ("Sorted array is:")
for i in range(len(arr)):
print ("%d" %arr[i]),

Read Dataset from excel file

Oct 7, 2022KETRICK

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import pandas as pd
x = pd.read_excel(FILE_NAME)
print(x)

curry function

Nov 19, 2022CodeCatch

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from functools import partial
def curry(fn, *args):
return partial(fn, *args)
add = lambda x, y: x + y
add10 = curry(add, 10)
add10(20) # 30

Lonely Integer

Feb 26, 2023wabdelh

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#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77
# xor a list of integers to find the lonely integer
res = a[0]
for i in range(1,len(a)):
res = res ^ a[i]