• Nov 19, 2022 •CodeCatch
0 likes • 18 views
def sum_of_powers(end, power = 2, start = 1): return sum([(i) ** power for i in range(start, end + 1)]) sum_of_powers(10) # 385 sum_of_powers(10, 3) # 3025 sum_of_powers(10, 3, 5) # 2925
• Feb 26, 2023 •wabdelh
0 likes • 1 view
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Jun 1, 2023 •CodeCatch
0 likes • 3 views
def calculate_values(): value1 = 10 value2 = 20 return value1, value2 result1, result2 = calculate_values() print("Result 1:", result1) print("Result 2:", result2)
• Feb 23, 2025 •hasnaoui1
0 likes • 8 views
print("hello world")
• Mar 10, 2021 •Skrome
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import string def caesar(text, shift, alphabets): def shift_alphabet(alphabet): return alphabet[shift:] + alphabet[:shift] shifted_alphabets = tuple(map(shift_alphabet, alphabets)) final_alphabet = "".join(alphabets) final_shifted_alphabet = "".join(shifted_alphabets) table = str.maketrans(final_alphabet, final_shifted_alphabet) return text.translate(table) plain_text = "Hey Skrome, welcome to CodeCatch" print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))
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def when(predicate, when_true): return lambda x: when_true(x) if predicate(x) else x double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2) print(double_even_numbers(2)) # 4 print(double_even_numbers(1)) # 1