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Jan 23, 2021asnark
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Multiply Two Matrices

May 31, 2023CodeCatch

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# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)

Remove i'th character

Nov 19, 2022CodeCatch

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# Python code to demonstrate
# method to remove i'th character
# Naive Method
# Initializing String
test_str = "CodeCatch"
# Printing original string
print ("The original string is : " + test_str)
# Removing char at pos 3
# using loop
new_str = ""
for i in range(len(test_str)):
if i != 2:
new_str = new_str + test_str[i]
# Printing string after removal
print ("The string after removal of i'th character : " + new_str)

Print "X" pattern

Nov 19, 2022CodeCatch

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def print_x_pattern(size):
i,j = 0,size - 1
while j >= 0 and i < size:
initial_spaces = ' '*min(i,j)
middle_spaces = ' '*(abs(i - j) - 1)
final_spaces = ' '*(size - 1 - max(i,j))
if j == i:
print(initial_spaces + '*' + final_spaces)
else:
print(initial_spaces + '*' + middle_spaces + '*' + final_spaces)
i += 1
j -= 1
print_x_pattern(7)

Copy file to destination

Nov 18, 2022AustinLeath

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# importing the modules
import os
import shutil
# getting the current working directory
src_dir = os.getcwd()
# printing current directory
print(src_dir)
# copying the files
shutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst
# printing the list of new files
print(os.listdir())

Mad libs generator

Nov 19, 2022CodeCatch

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#Loop back to this point once code finishes
loop = 1
while (loop < 10):
#All the questions that the program asks the user
noun = input("Choose a noun: ")
p_noun = input("Choose a plural noun: ")
noun2 = input("Choose a noun: ")
place = input("Name a place: ")
adjective = input("Choose an adjective (Describing word): ")
noun3 = input("Choose a noun: ")
#Displays the story based on the users input
print ("------------------------------------------")
print ("Be kind to your",noun,"- footed", p_noun)
print ("For a duck may be somebody's", noun2,",")
print ("Be kind to your",p_noun,"in",place)
print ("Where the weather is always",adjective,".")
print ()
print ("You may think that is this the",noun3,",")
print ("Well it is.")
print ("------------------------------------------")
#Loop back to "loop = 1"
loop = loop + 1

Propositional logic with itertools

Nov 18, 2022AustinLeath

0 likes • 5 views

from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1(p,q,r) :
x=p or (q and r)
y= (p or q) and (p or r)
return x==y
tt(prob1,3)
# p/\(q\/r)=(p/\q)\/(p/\r)
def prob2(p,q,r) :
x=p and ( q or r )
y=(p and q) or (p and r)
return x==y
tt(prob2,3)
#~(p/\q)=(~p\/~q)
def prob3(p,q) :
x=not (p and q)
y=(not p) or (not q)
return x==y
tt(prob3,2)
#(~(p\/q))=((~p)/\~q)
def prob4(p, q):
x = not(p or q)
y = not p and not q
return x == y
tt(prob4, 2)
#(p/\(p=>q)=>q)
def prob5(p,q):
x= p and ( not p or q)
return not x or q
tt(prob5,2)
# (p=>q)=((p\/q)=q)
def prob6(p,q) :
x = (not p or q)
y=((p or q) == q)
return x==y
tt(prob6,2)
#((p=>q)=(p\/q))=q
def prob7(p,q):
if ((not p or q)==(p or q))==q:
return 1
tt(prob7,2)
#(p=>q)=((p/\q)=p)
def prob8(p,q):
if (not p or q)==((p and q)==p):
return 1
tt(prob8,2)
#((p=>q)=(p/\q))=p
def prob9(p,q):
if ((not p or q)==(p and q))==p:
return '1'
tt(prob9,2)
#(p=>q)/\(q=>r)=>(p=>r)
def prob10(p,q,r) :
x = not ((not p or q) and (not q or r)) or (not p or r)
return x
tt(prob10, 3)
# (p = q) /\ (q => r) => (p => r)
#answer 1
def prob11(p,q,r) :
x = not((p is q) and (not q or r)) or (not p or r)
return x
tt(prob11, 3)
#(p=q)/\(q=>r)=>(p=>r)
#answer 2
def prob11(p,q,r):
x=(p==q) and (not q or r)
y=not p or r
return not x or y
tt(prob11,3)
#((p=>q)/\(q=r))=>(p=>r)
def prob12(p,q,r):
x=(not p or q) and ( q==r )
y=not p or r
return not x or y
tt(prob12,3)
#(p=>q)=>((p/\r)=>(q/\r))
def prob13(p,q,r):
x=not p or q
y=(not(p and r) or ( q and r))
return not x or y
tt(prob13,3)
#Question#2----------------------------------------
#(p=>q)=>r=p=>(q=>r)
def prob14(p,q,r):
x=(not(not p or q) or r)
y=(not p or (not q or r))
return x==y
tt(prob14,3)
def prob15(p, q):
x = not(p and q)
y = not p and not q
return x == y
tt(prob15, 2)
def prob16(p, q):
x = not(p or q)
y = not p or not q
return x == y
tt(prob16, 2)
def prob17(p):
x = p
y = not p
return x == y
tt(prob17, 1)