• Nov 19, 2022 •CodeCatch
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""" Number Guessing Game ---------------------------------------- """ import random attempts_list = [] def show_score(): if len(attempts_list) <= 0: print("There is currently no high score, it's yours for the taking!") else: print("The current high score is {} attempts".format(min(attempts_list))) def start_game(): random_number = int(random.randint(1, 10)) print("Hello traveler! Welcome to the game of guesses!") player_name = input("What is your name? ") wanna_play = input("Hi, {}, would you like to play the guessing game? (Enter Yes/No) ".format(player_name)) // Where the show_score function USED to be attempts = 0 show_score() while wanna_play.lower() == "yes": try: guess = input("Pick a number between 1 and 10 ") if int(guess) < 1 or int(guess) > 10: raise ValueError("Please guess a number within the given range") if int(guess) == random_number: print("Nice! You got it!") attempts += 1 attempts_list.append(attempts) print("It took you {} attempts".format(attempts)) play_again = input("Would you like to play again? (Enter Yes/No) ") attempts = 0 show_score() random_number = int(random.randint(1, 10)) if play_again.lower() == "no": print("That's cool, have a good one!") break elif int(guess) > random_number: print("It's lower") attempts += 1 elif int(guess) < random_number: print("It's higher") attempts += 1 except ValueError as err: print("Oh no!, that is not a valid value. Try again...") print("({})".format(err)) else: print("That's cool, have a good one!") if __name__ == '__main__': start_game()
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
• Jun 26, 2025 •AustinLeath
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def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
def print_x_pattern(size): i,j = 0,size - 1 while j >= 0 and i < size: initial_spaces = ' '*min(i,j) middle_spaces = ' '*(abs(i - j) - 1) final_spaces = ' '*(size - 1 - max(i,j)) if j == i: print(initial_spaces + '*' + final_spaces) else: print(initial_spaces + '*' + middle_spaces + '*' + final_spaces) i += 1 j -= 1 print_x_pattern(7)
• May 31, 2023 •CodeCatch
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class Rectangle: pass class Square(Rectangle): pass rectangle = Rectangle() square = Square() print(isinstance(rectangle, Rectangle)) # True print(isinstance(square, Rectangle)) # True print(isinstance(square, Square)) # True print(isinstance(rectangle, Square)) # False