• Nov 19, 2022 •CodeCatch
0 likes • 2 views
def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
• May 31, 2023 •CodeCatch
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# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")
def generate_floyds_triangle(num_rows): triangle = [] number = 1 for row in range(num_rows): current_row = [] for _ in range(row + 1): current_row.append(number) number += 1 triangle.append(current_row) return triangle def display_floyds_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Floyd's Triangle: ")) # Generate Floyd's Triangle floyds_triangle = generate_floyds_triangle(num_rows) # Display Floyd's Triangle display_floyds_triangle(floyds_triangle)
• Feb 26, 2023 •wabdelh
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#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Dec 24, 2025 •CodeCatch
string
• Nov 18, 2022 •AustinLeath
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#Python 3: Fibonacci series up to n def fib(n): a, b = 0, 1 while a < n: print(a, end=' ') a, b = b, a+b print() fib(1000)