from collections import defaultdict

def collect_dictionary(obj):
  inv_obj = defaultdict(list)
  for key, value in obj.items():
    inv_obj[value].append(key)
  return dict(inv_obj)
  
ages = {
  'Peter': 10,
  'Isabel': 10,
  'Anna': 9,
}
collect_dictionary(ages) # { 10: ['Peter', 'Isabel'], 9: ['Anna'] }

# Python Program to calculate the square root

num = float(input('Enter a number: '))

num_sqrt = num ** 0.5
print('The square root of %0.3f is %0.3f'%(num ,num_sqrt))

def when(predicate, when_true):
  return lambda x: when_true(x) if predicate(x) else x

double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)
print(double_even_numbers(2)) # 4
print(double_even_numbers(1)) # 1

from datetime import datetime

epoch_time = 1753823646  # Example epoch time (March 15, 2023 00:00:00 UTC)

# Convert epoch time to a UTC datetime object
utc_datetime = datetime.utcfromtimestamp(epoch_time)

print(f"Epoch time: {epoch_time}")
print(f"UTC datetime: {utc_datetime}")

# You can also format the output string
formatted_utc_time = utc_datetime.strftime('%m-%d-%Y %H:%M:%S UTC')
print(f"Formatted UTC datetime: {formatted_utc_time}")

#You are given a two-digit integer n. Return the sum of its digits.
#Example
#For n = 29 the output should be solution (n) = 11
def solution(n):
    return (n//10 + n%10)

# List
lst = [1, 2, 3, 'Alice', 'Alice']

# One-Liner
indices = [i for i in range(len(lst)) if lst[i]=='Alice']

# Result
print(indices)
# [3, 4]