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import os# Get the current directorycurrent_dir = os.getcwd()# Loop through each file in the current directoryfor filename in os.listdir(current_dir):# Check if the file name starts with a number followed by a period and a spaceif filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ':# Remove the number, period, and space from the file namenew_filename = filename[3:]# Rename the fileos.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))
from time import sleepdef delay(fn, ms, *args):sleep(ms / 1000)return fn(*args)delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second
print("hellur")
# Python program for Bitonic Sort. Note that this program# works only when size of input is a power of 2.# The parameter dir indicates the sorting direction, ASCENDING# or DESCENDING; if (a[i] > a[j]) agrees with the direction,# then a[i] and a[j] are interchanged.*/def compAndSwap(a, i, j, dire):if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] > a[j]):a[i],a[j] = a[j],a[i]# It recursively sorts a bitonic sequence in ascending order,# if dir = 1, and in descending order otherwise (means dir=0).# The sequence to be sorted starts at index position low,# the parameter cnt is the number of elements to be sorted.def bitonicMerge(a, low, cnt, dire):if cnt > 1:k = cnt/2for i in range(low , low+k):compAndSwap(a, i, i+k, dire)bitonicMerge(a, low, k, dire)bitonicMerge(a, low+k, k, dire)# This funcion first produces a bitonic sequence by recursively# sorting its two halves in opposite sorting orders, and then# calls bitonicMerge to make them in the same orderdef bitonicSort(a, low, cnt,dire):if cnt > 1:k = cnt/2bitonicSort(a, low, k, 1)bitonicSort(a, low+k, k, 0)bitonicMerge(a, low, cnt, dire)# Caller of bitonicSort for sorting the entire array of length N# in ASCENDING orderdef sort(a,N, up):bitonicSort(a,0, N, up)# Driver code to test abovea = [3, 7, 4, 8, 6, 2, 1, 5]n = len(a)up = 1sort(a, n, up)print ("\n\nSorted array is")for i in range(n):print("%d" %a[i]),
def key_of_min(d):return min(d, key = d.get)key_of_min({'a':4, 'b':0, 'c':13}) # b
def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])sum_of_powers(10) # 385sum_of_powers(10, 3) # 3025sum_of_powers(10, 3, 5) # 2925