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Print "X" pattern

Nov 19, 2022CodeCatch
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key of minimum value

Nov 19, 2022CodeCatch

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def key_of_min(d):
return min(d, key = d.get)
key_of_min({'a':4, 'b':0, 'c':13}) # b
my_list = [1, 2, 3, 4, 5]
removed_element = my_list.pop(2) # Remove and return element at index 2
print(removed_element) # 3
print(my_list) # [1, 2, 4, 5]
last_element = my_list.pop() # Remove and return the last element
print(last_element) # 5
print(my_list) # [1, 2, 4]

return maximum

Nov 19, 2022CodeCatch

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def max_n(lst, n = 1):
return sorted(lst, reverse = True)[:n]
max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]

Return Letter Combinations

Nov 18, 2022AustinLeath

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# @return a list of strings, [s1, s2]
def letterCombinations(self, digits):
if '' == digits: return []
kvmaps = {
'2': 'abc',
'3': 'def',
'4': 'ghi',
'5': 'jkl',
'6': 'mno',
'7': 'pqrs',
'8': 'tuv',
'9': 'wxyz'
}
return reduce(lambda acc, digit: [x + y for x in acc for y in kvmaps[digit]], digits, [''])

Sieve of Eratosthenes

Nov 19, 2022CodeCatch

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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.
# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.
# Python program to print all primes smaller than or equal to
# n using Sieve of Eratosthenes
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and initialize
# all entries it as true. A value in prime[i] will
# finally be false if i is Not a prime, else true.
prime = [True for i in range(n + 1)]
p = 2
while (p * p <= n):
# If prime[p] is not changed, then it is a prime
if (prime[p] == True):
# Update all multiples of p
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
# Print all prime numbers
for p in range(n + 1):
if prime[p]:
print (p)
# driver program
if __name__=='__main__':
n = 30
print("Following are the prime numbers smaller")
print("than or equal to ", n)
print("than or equal to ", n)
SieveOfEratosthenes(n)

print indices

Nov 18, 2022AustinLeath

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# List
lst = [1, 2, 3, 'Alice', 'Alice']
# One-Liner
indices = [i for i in range(len(lst)) if lst[i]=='Alice']
# Result
print(indices)
# [3, 4]