import string

def caesar(text, shift, alphabets):
	def shift_alphabet(alphabet):
	    return alphabet[shift:] + alphabet[:shift]
	
	shifted_alphabets = tuple(map(shift_alphabet, alphabets))
	final_alphabet = "".join(alphabets)
	final_shifted_alphabet = "".join(shifted_alphabets)
	table = str.maketrans(final_alphabet, final_shifted_alphabet)
	return text.translate(table)

plain_text = "Hey Skrome, welcome to CodeCatch"
print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))

def calculate_values():
    value1 = 10
    value2 = 20
    return value1, value2

result1, result2 = calculate_values()
print("Result 1:", result1)
print("Result 2:", result2)

# Python code to demonstrate
# method to remove i'th character
# Naive Method

# Initializing String
test_str = "CodeCatch"

# Printing original string
print ("The original string is : " + test_str)

# Removing char at pos 3
# using loop
new_str = ""

for i in range(len(test_str)):
	if i != 2:
		new_str = new_str + test_str[i]

# Printing string after removal
print ("The string after removal of i'th character : " + new_str)

# Python program for implementation of Bogo Sort
import random

# Sorts array a[0..n-1] using Bogo sort
def bogoSort(a):
	n = len(a)
	while (is_sorted(a)== False):
		shuffle(a)

# To check if array is sorted or not
def is_sorted(a):
	n = len(a)
	for i in range(0, n-1):
		if (a[i] > a[i+1] ):
			return False
	return True

# To generate permuatation of the array
def shuffle(a):
	n = len(a)
	for i in range (0,n):
		r = random.randint(0,n-1)
		a[i], a[r] = a[r], a[i]

# Driver code to test above
a = [3, 2, 4, 1, 0, 5]
bogoSort(a)
print("Sorted array :")
for i in range(len(a)):
	print ("%d" %a[i]),

import calendar
from datetime import datetime

# Get the UTC timestamp
a = calendar.timegm(datetime.utcnow().utctimetuple())

print(a)

import pandas as pd



x = pd.read_excel(FILE_NAME)

print(x)