• May 31, 2023 •CodeCatch
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def generate_pascals_triangle(num_rows): triangle = [] for row in range(num_rows): # Initialize the row with 1 current_row = [1] # Calculate the values for the current row if row > 0: previous_row = triangle[row - 1] for i in range(len(previous_row) - 1): current_row.append(previous_row[i] + previous_row[i + 1]) # Append 1 at the end of the row current_row.append(1) # Add the current row to the triangle triangle.append(current_row) return triangle def display_pascals_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Pascal's Triangle: ")) # Generate Pascal's Triangle pascals_triangle = generate_pascals_triangle(num_rows) # Display Pascal's Triangle display_pascals_triangle(pascals_triangle)
• Sep 6, 2020 •C S
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def Fibonacci(n): if n<0: print("Incorrect input") # First Fibonacci number is 0 elif n==1: return 0 # Second Fibonacci number is 1 elif n==2: return 1 else: return Fibonacci(n-1)+Fibonacci(n-2) # Driver Program print(Fibonacci(9))
• Nov 19, 2022 •CodeCatch
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def when(predicate, when_true): return lambda x: when_true(x) if predicate(x) else x double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2) print(double_even_numbers(2)) # 4 print(double_even_numbers(1)) # 1
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# Python program for implementation of Bubble Sort def bubbleSort(arr): n = len(arr) # Traverse through all array elements for i in range(n-1): # range(n) also work but outer loop will repeat one time more than needed. # Last i elements are already in place for j in range(0, n-i-1): # traverse the array from 0 to n-i-1 # Swap if the element found is greater # than the next element if arr[j] > arr[j+1] : arr[j], arr[j+1] = arr[j+1], arr[j] # Driver code to test above arr = [64, 34, 25, 12, 22, 11, 90] bubbleSort(arr) print ("Sorted array is:") for i in range(len(arr)): print ("%d" %arr[i]),
• Nov 18, 2022 •AustinLeath
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mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0} # How to sort a dict by value Python 3> sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))} print(sort) # How to sort a dict by key Python 3> sort = {key:mydict[key] for key in sorted(mydict.keys())} print(sort)
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# question3.py from itertools import product V='∀' E='∃' def tt(f,n) : xss=product((0,1),repeat=n) print('function:',f.__name__) for xs in xss : print(*xs,':',int(f(*xs))) print('') # this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r) def parta(p,q,r) : a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c def partb(p,q,r) : a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c print("part A:") tt(parta,3) print("part B:") tt(partb,3)