• Nov 18, 2022 •AustinLeath
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def get_ldap_user(member_cn, user, passwrd): ''' Get an LDAP user and return the SAMAccountName ''' #---- Setting up the Connection #account used for binding - Avoid putting these in version control bindDN = str(user) + "@unt.ad.unt.edu" bindPass = passwrd #set some tuneables for the LDAP library. ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW) #ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE) conn = ldap.initialize('ldaps://unt.ad.unt.edu') conn.protocol_version = 3 conn.set_option(ldap.OPT_REFERRALS, 0) #authenticate the connection so that you can make additional queries try: result = conn.simple_bind_s(bindDN, bindPass) except ldap.INVALID_CREDENTIALS: result = "Invalid credentials for %s" % user sys.exit() #build query in the form of (uid=user) ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))' ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query) sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","") return sAMAccountName
• May 31, 2023 •CodeCatch
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import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
• Nov 19, 2022 •CodeCatch
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import mysql.connector mydb = mysql.connector.connect( host="localhost", user="yourusername", password="yourpassword" ) mycursor = mydb.cursor() mycursor.execute("CREATE DATABASE mydatabase")
• Feb 26, 2023 •wabdelh
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#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Oct 15, 2022 •CodeCatch
class Solution(object): def floodFill(self, image, sr, sc, newColor): R, C = len(image), len(image[0]) color = image[sr][sc] if color == newColor: return image def dfs(r, c): if image[r][c] == color: image[r][c] = newColor if r >= 1: dfs(r-1, c) if r+1 < R: dfs(r+1, c) if c >= 1: dfs(r, c-1) if c+1 < C: dfs(r, c+1) dfs(sr, sc) return image
• Mar 26, 2023 •AustinLeath
import os # Get the current directory current_dir = os.getcwd() # Loop through each file in the current directory for filename in os.listdir(current_dir): # Check if the file name starts with a number followed by a period and a space if filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ': # Remove the number, period, and space from the file name new_filename = filename[3:] # Rename the file os.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))