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bruteforce password cracker

0 likes • Nov 18, 2022
Python
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LeetCode Flood Fill

CodeCatch
0 likes • Oct 15, 2022
Python
class Solution(object):
def floodFill(self, image, sr, sc, newColor):
R, C = len(image), len(image[0])
color = image[sr][sc]
if color == newColor: return image
def dfs(r, c):
if image[r][c] == color:
image[r][c] = newColor
if r >= 1: dfs(r-1, c)
if r+1 < R: dfs(r+1, c)
if c >= 1: dfs(r, c-1)
if c+1 < C: dfs(r, c+1)
dfs(sr, sc)
return image

Copy file to destination

AustinLeath
0 likes • Nov 18, 2022
Python
# importing the modules
import os
import shutil
# getting the current working directory
src_dir = os.getcwd()
# printing current directory
print(src_dir)
# copying the files
shutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst
# printing the list of new files
print(os.listdir())

Finding NULL values within set

KETRICK
0 likes • Oct 7, 2022
Python
x[cat_var].isnull().sum().sort_values(ascending=False)

Check Armstrong Number

CodeCatch
0 likes • May 31, 2023
Python
# Function to check Armstrong number
def is_armstrong_number(number):
# Convert number to string to iterate over its digits
num_str = str(number)
# Calculate the sum of the cubes of each digit
digit_sum = sum(int(digit) ** len(num_str) for digit in num_str)
# Compare the sum with the original number
if digit_sum == number:
return True
else:
return False
# Prompt user for a number
number = int(input("Enter a number: "))
# Check if the number is an Armstrong number
if is_armstrong_number(number):
print(number, "is an Armstrong number.")
else:
print(number, "is not an Armstrong number.")

Print pyramid pattern

CodeCatch
0 likes • Nov 19, 2022
Python
def print_pyramid_pattern(n):
# outer loop to handle number of rows
# n in this case
for i in range(0, n):
# inner loop to handle number of columns
# values changing acc. to outer loop
for j in range(0, i+1):
# printing stars
print("* ",end="")
# ending line after each row
print("\r")
print_pyramid_pattern(10)

Multiply Two Matrices

CodeCatch
0 likes • May 31, 2023
Python
# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)