• Dec 18, 2025 •CodeCatch
0 likes • 3 views
def insertion_sort(arr): # Traverse through 1 to len(arr) for i in range(1, len(arr)): key = arr[i] # Move elements of arr[0..i-1], that are greater than key, # to one position ahead of their current position j = i - 1 while j >= 0 and key < arr[j]: arr[j + 1] = arr[j] j -= 1 arr[j + 1] = key # Example usage: arr = [12, 11, 13, 5, 6, 7, 8, 10] insertion_sort(arr) print("Sorted array is:", arr)
• Jan 23, 2021 •asnark
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""" Take screenshots at x interval - make a movie of doings on a computer. """ import time from datetime import datetime import ffmpeg import pyautogui while True: epoch_time = int(time.time()) today = datetime.now().strftime("%Y_%m_%d") filename = str(epoch_time) + ".png" print("taking screenshot: {0}".format(filename)) myScreenshot = pyautogui.screenshot() myScreenshot.save(today + "/" + filename) time.sleep(5) # # and then tie it together with: https://github.com/kkroening/ffmpeg-python/blob/master/examples/README.md#assemble-video-from-sequence-of-frames # """ import ffmpeg ( ffmpeg .input('./2021_01_22/*.png', pattern_type='glob', framerate=25) .filter('deflicker', mode='pm', size=10) .filter('scale', size='hd1080', force_original_aspect_ratio='increase') .output('movie.mp4', crf=20, preset='slower', movflags='faststart', pix_fmt='yuv420p') .run() ) """
• Jun 26, 2025 •AustinLeath
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def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
• Nov 19, 2022 •CodeCatch
0 likes • 4 views
def clamp_number(num, a, b): return max(min(num, max(a, b)), min(a, b)) clamp_number(2, 3, 5) # 3 clamp_number(1, -1, -5) # -1
• May 31, 2023 •CodeCatch
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# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")
from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0