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Jan 20, 2021Ntindle
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Bitonic sort

Nov 19, 2022CodeCatch

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# Python program for Bitonic Sort. Note that this program
# works only when size of input is a power of 2.
# The parameter dir indicates the sorting direction, ASCENDING
# or DESCENDING; if (a[i] > a[j]) agrees with the direction,
# then a[i] and a[j] are interchanged.*/
def compAndSwap(a, i, j, dire):
if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] > a[j]):
a[i],a[j] = a[j],a[i]
# It recursively sorts a bitonic sequence in ascending order,
# if dir = 1, and in descending order otherwise (means dir=0).
# The sequence to be sorted starts at index position low,
# the parameter cnt is the number of elements to be sorted.
def bitonicMerge(a, low, cnt, dire):
if cnt > 1:
k = cnt/2
for i in range(low , low+k):
compAndSwap(a, i, i+k, dire)
bitonicMerge(a, low, k, dire)
bitonicMerge(a, low+k, k, dire)
# This funcion first produces a bitonic sequence by recursively
# sorting its two halves in opposite sorting orders, and then
# calls bitonicMerge to make them in the same order
def bitonicSort(a, low, cnt,dire):
if cnt > 1:
k = cnt/2
bitonicSort(a, low, k, 1)
bitonicSort(a, low+k, k, 0)
bitonicMerge(a, low, cnt, dire)
# Caller of bitonicSort for sorting the entire array of length N
# in ASCENDING order
def sort(a,N, up):
bitonicSort(a,0, N, up)
# Driver code to test above
a = [3, 7, 4, 8, 6, 2, 1, 5]
n = len(a)
up = 1
sort(a, n, up)
print ("\n\nSorted array is")
for i in range(n):
print("%d" %a[i]),

read file contents into a list

Jun 1, 2023CodeCatch

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filename = "data.txt"
with open(filename, "r") as file:
file_contents = file.readlines()
file_contents = [line.strip() for line in file_contents]
print("File contents:")
for line in file_contents:
print(line)

return maximum

Nov 19, 2022CodeCatch

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def max_n(lst, n = 1):
return sorted(lst, reverse = True)[:n]
max_n([1, 2, 3]) # [3]
max_n([1, 2, 3], 2) # [3, 2]

Propositional logic with itertools

Nov 18, 2022AustinLeath

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from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1(p,q,r) :
x=p or (q and r)
y= (p or q) and (p or r)
return x==y
tt(prob1,3)
# p/\(q\/r)=(p/\q)\/(p/\r)
def prob2(p,q,r) :
x=p and ( q or r )
y=(p and q) or (p and r)
return x==y
tt(prob2,3)
#~(p/\q)=(~p\/~q)
def prob3(p,q) :
x=not (p and q)
y=(not p) or (not q)
return x==y
tt(prob3,2)
#(~(p\/q))=((~p)/\~q)
def prob4(p, q):
x = not(p or q)
y = not p and not q
return x == y
tt(prob4, 2)
#(p/\(p=>q)=>q)
def prob5(p,q):
x= p and ( not p or q)
return not x or q
tt(prob5,2)
# (p=>q)=((p\/q)=q)
def prob6(p,q) :
x = (not p or q)
y=((p or q) == q)
return x==y
tt(prob6,2)
#((p=>q)=(p\/q))=q
def prob7(p,q):
if ((not p or q)==(p or q))==q:
return 1
tt(prob7,2)
#(p=>q)=((p/\q)=p)
def prob8(p,q):
if (not p or q)==((p and q)==p):
return 1
tt(prob8,2)
#((p=>q)=(p/\q))=p
def prob9(p,q):
if ((not p or q)==(p and q))==p:
return '1'
tt(prob9,2)
#(p=>q)/\(q=>r)=>(p=>r)
def prob10(p,q,r) :
x = not ((not p or q) and (not q or r)) or (not p or r)
return x
tt(prob10, 3)
# (p = q) /\ (q => r) => (p => r)
#answer 1
def prob11(p,q,r) :
x = not((p is q) and (not q or r)) or (not p or r)
return x
tt(prob11, 3)
#(p=q)/\(q=>r)=>(p=>r)
#answer 2
def prob11(p,q,r):
x=(p==q) and (not q or r)
y=not p or r
return not x or y
tt(prob11,3)
#((p=>q)/\(q=r))=>(p=>r)
def prob12(p,q,r):
x=(not p or q) and ( q==r )
y=not p or r
return not x or y
tt(prob12,3)
#(p=>q)=>((p/\r)=>(q/\r))
def prob13(p,q,r):
x=not p or q
y=(not(p and r) or ( q and r))
return not x or y
tt(prob13,3)
#Question#2----------------------------------------
#(p=>q)=>r=p=>(q=>r)
def prob14(p,q,r):
x=(not(not p or q) or r)
y=(not p or (not q or r))
return x==y
tt(prob14,3)
def prob15(p, q):
x = not(p and q)
y = not p and not q
return x == y
tt(prob15, 2)
def prob16(p, q):
x = not(p or q)
y = not p or not q
return x == y
tt(prob16, 2)
def prob17(p):
x = p
y = not p
return x == y
tt(prob17, 1)

bruteforce password cracker

Nov 18, 2022AustinLeath

0 likes • 3 views

import itertools
import string
import time
def guess_password(real):
chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation
attempts = 0
for password_length in range(1, 9):
for guess in itertools.product(chars, repeat=password_length):
startTime = time.time()
attempts += 1
guess = ''.join(guess)
if guess == real:
return 'password is {}. found in {} guesses.'.format(guess, attempts)
loopTime = (time.time() - startTime);
print(guess, attempts, loopTime)
print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n")
val = input("Enter a password you want to crack that is 9 characters or below: ")
print(guess_password(val.lower()))

Number guessing game

Nov 19, 2022CodeCatch

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""" Number Guessing Game
----------------------------------------
"""
import random
attempts_list = []
def show_score():
if len(attempts_list) <= 0:
print("There is currently no high score, it's yours for the taking!")
else:
print("The current high score is {} attempts".format(min(attempts_list)))
def start_game():
random_number = int(random.randint(1, 10))
print("Hello traveler! Welcome to the game of guesses!")
player_name = input("What is your name? ")
wanna_play = input("Hi, {}, would you like to play the guessing game? (Enter Yes/No) ".format(player_name))
// Where the show_score function USED to be
attempts = 0
show_score()
while wanna_play.lower() == "yes":
try:
guess = input("Pick a number between 1 and 10 ")
if int(guess) < 1 or int(guess) > 10:
raise ValueError("Please guess a number within the given range")
if int(guess) == random_number:
print("Nice! You got it!")
attempts += 1
attempts_list.append(attempts)
print("It took you {} attempts".format(attempts))
play_again = input("Would you like to play again? (Enter Yes/No) ")
attempts = 0
show_score()
random_number = int(random.randint(1, 10))
if play_again.lower() == "no":
print("That's cool, have a good one!")
break
elif int(guess) > random_number:
print("It's lower")
attempts += 1
elif int(guess) < random_number:
print("It's higher")
attempts += 1
except ValueError as err:
print("Oh no!, that is not a valid value. Try again...")
print("({})".format(err))
else:
print("That's cool, have a good one!")
if __name__ == '__main__':
start_game()