def to_roman_numeral(num):
  lookup = [
    (1000, 'M'),
    (900, 'CM'),
    (500, 'D'),
    (400, 'CD'),
    (100, 'C'),
    (90, 'XC'),
    (50, 'L'),
    (40, 'XL'),
    (10, 'X'),
    (9, 'IX'),
    (5, 'V'),
    (4, 'IV'),
    (1, 'I'),
  ]
  res = ''
  for (n, roman) in lookup:
    (d, num) = divmod(num, n)
    res += roman * d
  return res

to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77
# xor a list of integers to find the lonely integer
res = a[0]
    for i in range(1,len(a)):
        res = res ^ a[i]

def generate_floyds_triangle(num_rows):
    triangle = []
    number = 1
    for row in range(num_rows):
        current_row = []
        for _ in range(row + 1):
            current_row.append(number)
            number += 1
        triangle.append(current_row)
    return triangle


def display_floyds_triangle(triangle):
    for row in triangle:
        for number in row:
            print(number, end=" ")
        print()


# Prompt the user for the number of rows
num_rows = int(input("Enter the number of rows for Floyd's Triangle: "))

# Generate Floyd's Triangle
floyds_triangle = generate_floyds_triangle(num_rows)

# Display Floyd's Triangle
display_floyds_triangle(floyds_triangle)

import calendar

# Prompt user for year and month
year = int(input("Enter the year: "))
month = int(input("Enter the month: "))

# Create a calendar object
cal = calendar.monthcalendar(year, month)

# Display the calendar
print(calendar.month_name[month], year)
print("Mon  Tue  Wed  Thu  Fri  Sat  Sun")

for week in cal:
    for day in week:
        if day == 0:
            print("     ", end="")
        else:
            print(str(day).rjust(2), "  ", end="")
    print()

#Loop back to this point once code finishes
loop = 1
while (loop < 10):
#All the questions that the program asks the user
    noun = input("Choose a noun: ")
    p_noun = input("Choose a plural noun: ")
    noun2 = input("Choose a noun: ")
    place = input("Name a place: ")
    adjective = input("Choose an adjective (Describing word): ")
    noun3 = input("Choose a noun: ")
#Displays the story based on the users input
    print ("------------------------------------------")
    print ("Be kind to your",noun,"- footed", p_noun)
    print ("For a duck may be somebody's", noun2,",")
    print ("Be kind to your",p_noun,"in",place)
    print ("Where the weather is always",adjective,".")
    print ()
    print ("You may think that is this the",noun3,",")
    print ("Well it is.")
    print ("------------------------------------------")
#Loop back to "loop = 1"
    loop = loop + 1

# question3.py
from itertools import product
V='∀'
E='∃'

def tt(f,n) :
  xss=product((0,1),repeat=n)
  print('function:',f.__name__)
  for xs in xss : print(*xs,':',int(f(*xs)))
  print('')

# this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r)

def parta(p,q,r) :
  
  a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or  not r)
  b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)
  c= a and b
  return c

def partb(p,q,r) :
  a=(p or q and r) and (p or not q or not r) and (p or not q or not  r)and (p or q or  not r)
  b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r)
  c= a and b
  return c

print("part A:")
tt(parta,3)

print("part B:")
tt(partb,3)