• Jun 1, 2023 •CodeCatch
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filename = "data.txt" with open(filename, "r") as file: file_contents = file.readlines() file_contents = [line.strip() for line in file_contents] print("File contents:") for line in file_contents: print(line)
• Mar 26, 2023 •AustinLeath
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import os # Get the current directory current_dir = os.getcwd() # Loop through each file in the current directory for filename in os.listdir(current_dir): # Check if the file name starts with a number followed by a period and a space if filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ': # Remove the number, period, and space from the file name new_filename = filename[3:] # Rename the file os.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))
• May 31, 2023 •CodeCatch
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# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")
• Nov 19, 2022 •CodeCatch
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from collections import Counter def find_parity_outliers(nums): return [ x for x in nums if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0] ] find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]
def print_x_pattern(size): i,j = 0,size - 1 while j >= 0 and i < size: initial_spaces = ' '*min(i,j) middle_spaces = ' '*(abs(i - j) - 1) final_spaces = ' '*(size - 1 - max(i,j)) if j == i: print(initial_spaces + '*' + final_spaces) else: print(initial_spaces + '*' + middle_spaces + '*' + final_spaces) i += 1 j -= 1 print_x_pattern(7)
• Nov 18, 2022 •AustinLeath
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primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)