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Bubble sort

Nov 19, 2022CodeCatch
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Nodes and Trees

Nov 18, 2022AustinLeath

0 likes • 1 view

import random
class Node:
def __init__(self, c):
self.left = None
self.right = None
self.color = c
def SetColor(self,c) :
self.color = c
def PrintNode(self) :
print(self.color)
def insert(s, root, i, n):
if i < n:
temp = Node(s[i])
root = temp
root.left = insert(s, root.left,2 * i + 1, n)
root.right = insert(s, root.right,2 * i + 2, n)
return root
def MakeTree(s) :
list = insert(s,None,0,len(s))
return list
def MakeSet() :
s = []
count = random.randint(7,12)
for _ in range(count) :
color = random.randint(0,1) == 0 and "Red" or "White"
s.append(color)
return s
def ChangeColor(root) :
if (root != None) :
if (root.color == "White") :
root.SetColor("Red")
ChangeColor(root.left)
ChangeColor(root.right)
def PrintList(root) :
if root.left != None :
PrintList(root.left)
else :
root.PrintNode()
if root.right != None :
PrintList(root.right)
else :
root.PrintNode()
t1 = MakeTree(MakeSet())
print("Original Colors For Tree 1:\n")
PrintList(t1)
ChangeColor(t1)
print("New Colors For Tree 1:\n")
PrintList(t1)
t2 = MakeTree(MakeSet())
print("Original Colors For Tree 2:\n")
PrintList(t2)
ChangeColor(t2)
print("New Colors For Tree 2:\n")
PrintList(t2)
t3 = MakeTree(MakeSet())
print("Original Colors For Tree 3:\n")
PrintList(t3)
ChangeColor(t3)
print("New Colors For Tree 3:\n")
PrintList(t3)

two-digit integer

Feb 26, 2023wabdelh

0 likes • 0 views

#You are given a two-digit integer n. Return the sum of its digits.
#Example
#For n = 29 the output should be solution (n) = 11
def solution(n):
return (n//10 + n%10)

AnyTree Randomizer

Apr 15, 2021NoahEaton

0 likes • 0 views

import anytree as at
import random as rm
# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.
def random_tree(node_count):
# Generates the list of nodes
nodes = []
for i in range(node_count):
test = rm.randint(1,2)
if test == 1:
nodes.append(at.Node(str(i),color="white"))
else:
nodes.append(at.Node(str(i),color="red"))
#Creates the various main branches
for i in range(node_count):
for j in range(i, len(nodes)):
test = rm.randint(1,len(nodes))
if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):
nodes[j].parent = nodes[i]
#Collects all the main branches into a single tree with the first node being the root
for i in range(1, node_count):
if nodes[i].parent == None and (not nodes[i] == nodes[0]):
nodes[i].parent = nodes[0]
return nodes[0]

Remove numbers from files

Mar 26, 2023AustinLeath

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import os
# Get the current directory
current_dir = os.getcwd()
# Loop through each file in the current directory
for filename in os.listdir(current_dir):
# Check if the file name starts with a number followed by a period and a space
if filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ':
# Remove the number, period, and space from the file name
new_filename = filename[3:]
# Rename the file
os.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))

Sherlock Holmes Curious Lockbox Solver

Mar 12, 2021LeifMessinger

0 likes • 0 views

import copy
begining = [False,False,False,False,False,None,True,True,True,True,True]
#False = black True = white
its = [0]
def swap(layout, step):
layoutCopy = copy.deepcopy(layout)
layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]
return layoutCopy
def isSolved(layout):
for i in range(len(layout)):
if(layout[i] == False):
return (i >= (len(layout)/2))
def recurse(layout, its, steps = []):
if isSolved(layout):
its[0] += 1
print(layout,list(x[0] for x in steps))
return
step = None
for i in range(len(layout)):
if(layout[i] == None):
if(i >= 1): #If the empty space could have something to the left
if(layout[i - 1] == False):
step = [-1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i > 1): #If the empty space could have something 2 to the left
if(layout[i - 2] == False):
step = [-2,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-1)): #If the empty space could have something to the right
if(layout[i + 1] == True):
step = [1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-2)): #If the empty space could have something to the right
if(layout[i + 2] == True):
step = [2,i]
recurse(swap(layout,step), its, (steps+[step]))
its[0] += 1
#return None
recurse(begining,its,[])
print(its[0])

collect dictionary

Nov 19, 2022CodeCatch

0 likes • 1 view

from collections import defaultdict
def collect_dictionary(obj):
inv_obj = defaultdict(list)
for key, value in obj.items():
inv_obj[value].append(key)
return dict(inv_obj)
ages = {
'Peter': 10,
'Isabel': 10,
'Anna': 9,
}
collect_dictionary(ages) # { 10: ['Peter', 'Isabel'], 9: ['Anna'] }