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my_list = ["blue", "red", "green"]#1- Using sort or srted directly or with specifc keysmy_list.sort() #sorts alphabetically or in an ascending order for numeric datamy_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.# You can use reverse=True to flip the order#2- Using locale and functoolsimport localefrom functools import cmp_to_keymy_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
# Function to multiply two matricesdef multiply_matrices(matrix1, matrix2):# Check if the matrices can be multipliedif len(matrix1[0]) != len(matrix2):print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")return None# Create the result matrix filled with zerosresult = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]# Perform matrix multiplicationfor i in range(len(matrix1)):for j in range(len(matrix2[0])):for k in range(len(matrix2)):result[i][j] += matrix1[i][k] * matrix2[k][j]return result# Example matricesmatrix1 = [[1, 2, 3],[4, 5, 6],[7, 8, 9]]matrix2 = [[10, 11],[12, 13],[14, 15]]# Multiply the matricesresult_matrix = multiply_matrices(matrix1, matrix2)# Display the resultif result_matrix is not None:print("Result:")for row in result_matrix:print(row)
import calendar# Prompt user for year and monthyear = int(input("Enter the year: "))month = int(input("Enter the month: "))# Create a calendar objectcal = calendar.monthcalendar(year, month)# Display the calendarprint(calendar.month_name[month], year)print("Mon Tue Wed Thu Fri Sat Sun")for week in cal:for day in week:if day == 0:print(" ", end="")else:print(str(day).rjust(2), " ", end="")print()
# Python program to reverse a linked list# Time Complexity : O(n)# Space Complexity : O(n) as 'next'#variable is getting created in each loop.# Node classclass Node:# Constructor to initialize the node objectdef __init__(self, data):self.data = dataself.next = Noneclass LinkedList:# Function to initialize headdef __init__(self):self.head = None# Function to reverse the linked listdef reverse(self):prev = Nonecurrent = self.headwhile(current is not None):next = current.nextcurrent.next = prevprev = currentcurrent = nextself.head = prev# Function to insert a new node at the beginningdef push(self, new_data):new_node = Node(new_data)new_node.next = self.headself.head = new_node# Utility function to print the linked LinkedListdef printList(self):temp = self.headwhile(temp):print temp.data,temp = temp.next# Driver program to test above functionsllist = LinkedList()llist.push(20)llist.push(4)llist.push(15)llist.push(85)print "Given Linked List"llist.printList()llist.reverse()print "\nReversed Linked List"llist.printList()
import random# Define the ranks, suits, and create a deckranks = ['Ace', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'Jack', 'Queen', 'King']suits = ['Hearts', 'Diamonds', 'Clubs', 'Spades']deck = [(rank, suit) for rank in ranks for suit in suits]# Shuffle the deckrandom.shuffle(deck)# Display the shuffled deckfor card in deck:print(card[0], "of", card[1])
import copybegining = [False,False,False,False,False,None,True,True,True,True,True]#False = black True = whiteits = [0]def swap(layout, step):layoutCopy = copy.deepcopy(layout)layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]return layoutCopydef isSolved(layout):for i in range(len(layout)):if(layout[i] == False):return (i >= (len(layout)/2))def recurse(layout, its, steps = []):if isSolved(layout):its[0] += 1print(layout,list(x[0] for x in steps))returnstep = Nonefor i in range(len(layout)):if(layout[i] == None):if(i >= 1): #If the empty space could have something to the leftif(layout[i - 1] == False):step = [-1,i]recurse(swap(layout,step), its, (steps+[step]))if(i > 1): #If the empty space could have something 2 to the leftif(layout[i - 2] == False):step = [-2,i]recurse(swap(layout,step), its, (steps+[step]))if(i < (len(layout)-1)): #If the empty space could have something to the rightif(layout[i + 1] == True):step = [1,i]recurse(swap(layout,step), its, (steps+[step]))if(i < (len(layout)-2)): #If the empty space could have something to the rightif(layout[i + 2] == True):step = [2,i]recurse(swap(layout,step), its, (steps+[step]))its[0] += 1#return Nonerecurse(begining,its,[])print(its[0])