• May 5, 2026 •CodeCatch
0 likes • 9 views
• Apr 15, 2021 •NoahEaton
0 likes • 3 views
import anytree as at import random as rm # Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white. def random_tree(node_count): # Generates the list of nodes nodes = [] for i in range(node_count): test = rm.randint(1,2) if test == 1: nodes.append(at.Node(str(i),color="white")) else: nodes.append(at.Node(str(i),color="red")) #Creates the various main branches for i in range(node_count): for j in range(i, len(nodes)): test = rm.randint(1,len(nodes)) if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]): nodes[j].parent = nodes[i] #Collects all the main branches into a single tree with the first node being the root for i in range(1, node_count): if nodes[i].parent == None and (not nodes[i] == nodes[0]): nodes[i].parent = nodes[0] return nodes[0]
• Jun 1, 2023 •CodeCatch
0 likes • 5 views
filename = "data.txt" with open(filename, "r") as file: file_contents = file.readlines() file_contents = [line.strip() for line in file_contents] print("File contents:") for line in file_contents: print(line)
import re def find_pattern(text, pattern): match = re.search(pattern, text) if match: return match.group() else: return 'No match found' text = 'Hello, world! This is a test.' pattern = r'world!.*test.' result = find_pattern(text, pattern) print(result)
• Nov 19, 2022 •CodeCatch
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
• Jul 24, 2024 •AustinLeath
0 likes • 8 views
from statistics import median, mean, mode def print_stats(array): print(array) print("median =", median(array)) print("mean =", mean(array)) print("mode =", mode(array)) print() print_stats([1, 2, 3, 3, 4]) print_stats([1, 2, 3, 3])