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Print pyramid pattern

Nov 19, 2022CodeCatch
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Sort a List of Strings

Oct 15, 2022CodeCatch

1 like • 2 views

my_list = ["blue", "red", "green"]
#1- Using sort or srted directly or with specifc keys
my_list.sort() #sorts alphabetically or in an ascending order for numeric data
my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.
# You can use reverse=True to flip the order
#2- Using locale and functools
import locale
from functools import cmp_to_key
my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))

Multiply Two Matrices

May 31, 2023CodeCatch

0 likes • 0 views

# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)

Display Calendar

May 31, 2023CodeCatch

0 likes • 0 views

import calendar
# Prompt user for year and month
year = int(input("Enter the year: "))
month = int(input("Enter the month: "))
# Create a calendar object
cal = calendar.monthcalendar(year, month)
# Display the calendar
print(calendar.month_name[month], year)
print("Mon Tue Wed Thu Fri Sat Sun")
for week in cal:
for day in week:
if day == 0:
print(" ", end="")
else:
print(str(day).rjust(2), " ", end="")
print()

Reverse a linked list

Nov 19, 2022CodeCatch

0 likes • 0 views

# Python program to reverse a linked list
# Time Complexity : O(n)
# Space Complexity : O(n) as 'next'
#variable is getting created in each loop.
# Node class
class Node:
# Constructor to initialize the node object
def __init__(self, data):
self.data = data
self.next = None
class LinkedList:
# Function to initialize head
def __init__(self):
self.head = None
# Function to reverse the linked list
def reverse(self):
prev = None
current = self.head
while(current is not None):
next = current.next
current.next = prev
prev = current
current = next
self.head = prev
# Function to insert a new node at the beginning
def push(self, new_data):
new_node = Node(new_data)
new_node.next = self.head
self.head = new_node
# Utility function to print the linked LinkedList
def printList(self):
temp = self.head
while(temp):
print temp.data,
temp = temp.next
# Driver program to test above functions
llist = LinkedList()
llist.push(20)
llist.push(4)
llist.push(15)
llist.push(85)
print "Given Linked List"
llist.printList()
llist.reverse()
print "\nReversed Linked List"
llist.printList()

Shuffle Deck of Cards

May 31, 2023CodeCatch

0 likes • 1 view

import random
# Define the ranks, suits, and create a deck
ranks = ['Ace', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'Jack', 'Queen', 'King']
suits = ['Hearts', 'Diamonds', 'Clubs', 'Spades']
deck = [(rank, suit) for rank in ranks for suit in suits]
# Shuffle the deck
random.shuffle(deck)
# Display the shuffled deck
for card in deck:
print(card[0], "of", card[1])

Sherlock Holmes Curious Lockbox Solver

Mar 12, 2021LeifMessinger

0 likes • 0 views

import copy
begining = [False,False,False,False,False,None,True,True,True,True,True]
#False = black True = white
its = [0]
def swap(layout, step):
layoutCopy = copy.deepcopy(layout)
layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]
return layoutCopy
def isSolved(layout):
for i in range(len(layout)):
if(layout[i] == False):
return (i >= (len(layout)/2))
def recurse(layout, its, steps = []):
if isSolved(layout):
its[0] += 1
print(layout,list(x[0] for x in steps))
return
step = None
for i in range(len(layout)):
if(layout[i] == None):
if(i >= 1): #If the empty space could have something to the left
if(layout[i - 1] == False):
step = [-1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i > 1): #If the empty space could have something 2 to the left
if(layout[i - 2] == False):
step = [-2,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-1)): #If the empty space could have something to the right
if(layout[i + 1] == True):
step = [1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-2)): #If the empty space could have something to the right
if(layout[i + 2] == True):
step = [2,i]
recurse(swap(layout,step), its, (steps+[step]))
its[0] += 1
#return None
recurse(begining,its,[])
print(its[0])