• Sep 14, 2024 •rgannedo-6205
0 likes • 3 views
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
• May 31, 2023 •CodeCatch
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# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")
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import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
• Nov 18, 2022 •AustinLeath
import itertools import string import time def guess_password(real): chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation attempts = 0 for password_length in range(1, 9): for guess in itertools.product(chars, repeat=password_length): startTime = time.time() attempts += 1 guess = ''.join(guess) if guess == real: return 'password is {}. found in {} guesses.'.format(guess, attempts) loopTime = (time.time() - startTime); print(guess, attempts, loopTime) print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n") val = input("Enter a password you want to crack that is 9 characters or below: ") print(guess_password(val.lower()))
• Nov 19, 2022 •CodeCatch
# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()
• Feb 23, 2025 •hasnaoui1
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print("hello world")