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def byte_size(s):return len(s.encode('utf-8'))byte_size('😀') # 4byte_size('Hello World') # 11
# Python Program to calculate the square rootnum = float(input('Enter a number: '))num_sqrt = num ** 0.5print('The square root of %0.3f is %0.3f'%(num ,num_sqrt))
# Input for row and columnR = int(input())C = int(input())# Using list comprehension for inputmatrix = [[int(input()) for x in range (C)] for y in range(R)]
def get_ldap_user(member_cn, user, passwrd):'''Get an LDAP user and return the SAMAccountName'''#---- Setting up the Connection#account used for binding - Avoid putting these in version controlbindDN = str(user) + "@unt.ad.unt.edu"bindPass = passwrd#set some tuneables for the LDAP library.ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)conn = ldap.initialize('ldaps://unt.ad.unt.edu')conn.protocol_version = 3conn.set_option(ldap.OPT_REFERRALS, 0)#authenticate the connection so that you can make additional queriestry:result = conn.simple_bind_s(bindDN, bindPass)except ldap.INVALID_CREDENTIALS:result = "Invalid credentials for %s" % usersys.exit()#build query in the form of (uid=user)ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")return sAMAccountName
# Python program for implementation of Selection# Sortimport sysA = [64, 25, 12, 22, 11]# Traverse through all array elementsfor i in range(len(A)):# Find the minimum element in remaining# unsorted arraymin_idx = ifor j in range(i+1, len(A)):if A[min_idx] > A[j]:min_idx = j# Swap the found minimum element with# the first elementA[i], A[min_idx] = A[min_idx], A[i]# Driver code to test aboveprint ("Sorted array")for i in range(len(A)):print("%d" %A[i]),
from functools import partialdef curry(fn, *args):return partial(fn, *args)add = lambda x, y: x + yadd10 = curry(add, 10)add10(20) # 30