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def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'
import stringdef caesar(text, shift, alphabets):def shift_alphabet(alphabet):return alphabet[shift:] + alphabet[:shift]shifted_alphabets = tuple(map(shift_alphabet, alphabets))final_alphabet = "".join(alphabets)final_shifted_alphabet = "".join(shifted_alphabets)table = str.maketrans(final_alphabet, final_shifted_alphabet)return text.translate(table)plain_text = "Hey Skrome, welcome to CodeCatch"print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))
def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])sum_of_powers(10) # 385sum_of_powers(10, 3) # 3025sum_of_powers(10, 3, 5) # 2925
mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}# How to sort a dict by value Python 3>sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}print(sort)# How to sort a dict by key Python 3>sort = {key:mydict[key] for key in sorted(mydict.keys())}print(sort)
my_list = ["blue", "red", "green"]#1- Using sort or srted directly or with specifc keysmy_list.sort() #sorts alphabetically or in an ascending order for numeric datamy_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.# You can use reverse=True to flip the order#2- Using locale and functoolsimport localefrom functools import cmp_to_keymy_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
def Fibonacci(n):if n<0:print("Incorrect input")# First Fibonacci number is 0elif n==1:return 0# Second Fibonacci number is 1elif n==2:return 1else:return Fibonacci(n-1)+Fibonacci(n-2)# Driver Programprint(Fibonacci(9))