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Remove i'th character

Nov 19, 2022CodeCatch
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Rock paper scissors

Nov 19, 2022CodeCatch

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""" Rock Paper Scissors
----------------------------------------
"""
import random
import os
import re
os.system('cls' if os.name=='nt' else 'clear')
while (1 < 2):
print "\n"
print "Rock, Paper, Scissors - Shoot!"
userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ")
if not re.match("[SsRrPp]", userChoice):
print "Please choose a letter:"
print "[R]ock, [S]cissors or [P]aper."
continue
// Echo the user's choice
print "You chose: " + userChoice
choices = ['R', 'P', 'S']
opponenetChoice = random.choice(choices)
print "I chose: " + opponenetChoice
if opponenetChoice == str.upper(userChoice):
print "Tie! "
#if opponenetChoice == str("R") and str.upper(userChoice) == "P"
elif opponenetChoice == 'R' and userChoice.upper() == 'S':
print "Scissors beats rock, I win! "
continue
elif opponenetChoice == 'S' and userChoice.upper() == 'P':
print "Scissors beats paper! I win! "
continue
elif opponenetChoice == 'P' and userChoice.upper() == 'R':
print "Paper beat rock, I win! "
continue
else:
print "You win!"

Read Dataset from excel file

Oct 7, 2022KETRICK

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import pandas as pd
x = pd.read_excel(FILE_NAME)
print(x)

Palindrome checker

Nov 19, 2022CodeCatch

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# function which return reverse of a string
def isPalindrome(s):
return s == s[::-1]
# Driver code
s = "malayalam"
ans = isPalindrome(s)
if ans:
print("Yes")
else:
print("No")

lambda example

Nov 19, 2022CodeCatch

0 likes • 3 views

list_1 = [1,2,3,4,5,6,7,8,9]
cubed = map(lambda x: pow(x,3), list_1)
print(list(cubed))
#Results
#[1, 8, 27, 64, 125, 216, 343, 512, 729]

Plotting Fibonacci

Nov 19, 2022CodeCatch

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# Python program for Plotting Fibonacci
# spiral fractal using Turtle
import turtle
import math
def fiboPlot(n):
a = 0
b = 1
square_a = a
square_b = b
# Setting the colour of the plotting pen to blue
x.pencolor("blue")
# Drawing the first square
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
x.left(90)
x.forward(b * factor)
# Proceeding in the Fibonacci Series
temp = square_b
square_b = square_b + square_a
square_a = temp
# Drawing the rest of the squares
for i in range(1, n):
x.backward(square_a * factor)
x.right(90)
x.forward(square_b * factor)
x.left(90)
x.forward(square_b * factor)
x.left(90)
x.forward(square_b * factor)
# Proceeding in the Fibonacci Series
temp = square_b
square_b = square_b + square_a
square_a = temp
# Bringing the pen to starting point of the spiral plot
x.penup()
x.setposition(factor, 0)
x.seth(0)
x.pendown()
# Setting the colour of the plotting pen to red
x.pencolor("red")
# Fibonacci Spiral Plot
x.left(90)
for i in range(n):
print(b)
fdwd = math.pi * b * factor / 2
fdwd /= 90
for j in range(90):
x.forward(fdwd)
x.left(1)
temp = a
a = b
b = temp + b
# Here 'factor' signifies the multiplicative
# factor which expands or shrinks the scale
# of the plot by a certain factor.
factor = 1
# Taking Input for the number of
# Iterations our Algorithm will run
n = int(input('Enter the number of iterations (must be > 1): '))
# Plotting the Fibonacci Spiral Fractal
# and printing the corresponding Fibonacci Number
if n > 0:
print("Fibonacci series for", n, "elements :")
x = turtle.Turtle()
x.speed(100)
fiboPlot(n)
turtle.done()
else:
print("Number of iterations must be > 0")

Untitled

Sep 14, 2024rgannedo-6205

0 likes • 4 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")