Loading...
More Python Posts
class Solution(object):def floodFill(self, image, sr, sc, newColor):R, C = len(image), len(image[0])color = image[sr][sc]if color == newColor: return imagedef dfs(r, c):if image[r][c] == color:image[r][c] = newColorif r >= 1: dfs(r-1, c)if r+1 < R: dfs(r+1, c)if c >= 1: dfs(r, c-1)if c+1 < C: dfs(r, c+1)dfs(sr, sc)return image
#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77# xor a list of integers to find the lonely integerres = a[0]for i in range(1,len(a)):res = res ^ a[i]
list_1 = [1,2,3,4,5,6,7,8,9]cubed = map(lambda x: pow(x,3), list_1)print(list(cubed))#Results#[1, 8, 27, 64, 125, 216, 343, 512, 729]
# Python program for implementation of Selection# Sortimport sysA = [64, 25, 12, 22, 11]# Traverse through all array elementsfor i in range(len(A)):# Find the minimum element in remaining# unsorted arraymin_idx = ifor j in range(i+1, len(A)):if A[min_idx] > A[j]:min_idx = j# Swap the found minimum element with# the first elementA[i], A[min_idx] = A[min_idx], A[i]# Driver code to test aboveprint ("Sorted array")for i in range(len(A)):print("%d" %A[i]),
mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}# How to sort a dict by value Python 3>sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}print(sort)# How to sort a dict by key Python 3>sort = {key:mydict[key] for key in sorted(mydict.keys())}print(sort)
print("hellur")