Dictionary Sort
0 likes • Nov 18, 2022
Python
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my_list = ["blue", "red", "green"]#1- Using sort or srted directly or with specifc keysmy_list.sort() #sorts alphabetically or in an ascending order for numeric datamy_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.# You can use reverse=True to flip the order#2- Using locale and functoolsimport localefrom functools import cmp_to_keymy_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
import copybegining = [False,False,False,False,False,None,True,True,True,True,True]#False = black True = whiteits = [0]def swap(layout, step):layoutCopy = copy.deepcopy(layout)layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]return layoutCopydef isSolved(layout):for i in range(len(layout)):if(layout[i] == False):return (i >= (len(layout)/2))def recurse(layout, its, steps = []):if isSolved(layout):its[0] += 1print(layout,list(x[0] for x in steps))returnstep = Nonefor i in range(len(layout)):if(layout[i] == None):if(i >= 1): #If the empty space could have something to the leftif(layout[i - 1] == False):step = [-1,i]recurse(swap(layout,step), its, (steps+[step]))if(i > 1): #If the empty space could have something 2 to the leftif(layout[i - 2] == False):step = [-2,i]recurse(swap(layout,step), its, (steps+[step]))if(i < (len(layout)-1)): #If the empty space could have something to the rightif(layout[i + 1] == True):step = [1,i]recurse(swap(layout,step), its, (steps+[step]))if(i < (len(layout)-2)): #If the empty space could have something to the rightif(layout[i + 2] == True):step = [2,i]recurse(swap(layout,step), its, (steps+[step]))its[0] += 1#return Nonerecurse(begining,its,[])print(its[0])
# Python program to reverse a linked list# Time Complexity : O(n)# Space Complexity : O(n) as 'next'#variable is getting created in each loop.# Node classclass Node:# Constructor to initialize the node objectdef __init__(self, data):self.data = dataself.next = Noneclass LinkedList:# Function to initialize headdef __init__(self):self.head = None# Function to reverse the linked listdef reverse(self):prev = Nonecurrent = self.headwhile(current is not None):next = current.nextcurrent.next = prevprev = currentcurrent = nextself.head = prev# Function to insert a new node at the beginningdef push(self, new_data):new_node = Node(new_data)new_node.next = self.headself.head = new_node# Utility function to print the linked LinkedListdef printList(self):temp = self.headwhile(temp):print temp.data,temp = temp.next# Driver program to test above functionsllist = LinkedList()llist.push(20)llist.push(4)llist.push(15)llist.push(85)print "Given Linked List"llist.printList()llist.reverse()print "\nReversed Linked List"llist.printList()
# Deleting all even numbers from a lista = [1,2,3,4,5]del a[1::2]print(a)
# Function to check Armstrong numberdef is_armstrong_number(number):# Convert number to string to iterate over its digitsnum_str = str(number)# Calculate the sum of the cubes of each digitdigit_sum = sum(int(digit) ** len(num_str) for digit in num_str)# Compare the sum with the original numberif digit_sum == number:return Trueelse:return False# Prompt user for a numbernumber = int(input("Enter a number: "))# Check if the number is an Armstrong numberif is_armstrong_number(number):print(number, "is an Armstrong number.")else:print(number, "is not an Armstrong number.")
primes=[]products=[]def prime(num):if num > 1:for i in range(2,num):if (num % i) == 0:return Falseelse:primes.append(num)return Truefor n in range(30,1000):if len(primes) >= 20:break;else:prime(n)for previous, current in zip(primes[::2], primes[1::2]):products.append(previous * current)print (products)