• Nov 19, 2022 •CodeCatch
0 likes • 7 views
# function which return reverse of a string def isPalindrome(s): return s == s[::-1] # Driver code s = "malayalam" ans = isPalindrome(s) if ans: print("Yes") else: print("No")
• Dec 29, 2025 •CodeCatch
0 likes • 6 views
def bitonic_sort(arr, low, cnt, direction): ...
• May 5, 2026 •CodeCatch
0 likes • 4 views
{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}
• Jun 1, 2023 •CodeCatch
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filename = "data.txt" data = "Hello, World!" with open(filename, "a") as file: file.write(data)
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Apr 15, 2021 •NoahEaton
import anytree as at import random as rm # Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white. def random_tree(node_count): # Generates the list of nodes nodes = [] for i in range(node_count): test = rm.randint(1,2) if test == 1: nodes.append(at.Node(str(i),color="white")) else: nodes.append(at.Node(str(i),color="red")) #Creates the various main branches for i in range(node_count): for j in range(i, len(nodes)): test = rm.randint(1,len(nodes)) if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]): nodes[j].parent = nodes[i] #Collects all the main branches into a single tree with the first node being the root for i in range(1, node_count): if nodes[i].parent == None and (not nodes[i] == nodes[0]): nodes[i].parent = nodes[0] return nodes[0]