• Nov 19, 2022 •CodeCatch
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def sum_of_powers(end, power = 2, start = 1): return sum([(i) ** power for i in range(start, end + 1)]) sum_of_powers(10) # 385 sum_of_powers(10, 3) # 3025 sum_of_powers(10, 3, 5) # 2925
• Jun 1, 2023 •CodeCatch
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def calculate_values(): value1 = 10 value2 = 20 return value1, value2 result1, result2 = calculate_values() print("Result 1:", result1) print("Result 2:", result2)
• May 31, 2023 •CodeCatch
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# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")
• Aug 12, 2024 •AustinLeath
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magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits) sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits)) print("64 bit sum:", magnitude(64) * sign(64)) print("32 bit sum:", magnitude(32) * sign(32)) print("16 bit sum:", magnitude(16) * sign(16))
from collections import defaultdict def combine_values(*dicts): res = defaultdict(list) for d in dicts: for key in d: res[key].append(d[key]) return dict(res) d1 = {'a': 1, 'b': 'foo', 'c': 400} d2 = {'a': 3, 'b': 200, 'd': 400} combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}
• Feb 26, 2023 •wabdelh
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#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77 # xor a list of integers to find the lonely integer res = a[0] for i in range(1,len(a)): res = res ^ a[i]