• Nov 19, 2022 •CodeCatch
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# Python program for Plotting Fibonacci # spiral fractal using Turtle import turtle import math def fiboPlot(n): a = 0 b = 1 square_a = a square_b = b # Setting the colour of the plotting pen to blue x.pencolor("blue") # Drawing the first square x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Drawing the rest of the squares for i in range(1, n): x.backward(square_a * factor) x.right(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Bringing the pen to starting point of the spiral plot x.penup() x.setposition(factor, 0) x.seth(0) x.pendown() # Setting the colour of the plotting pen to red x.pencolor("red") # Fibonacci Spiral Plot x.left(90) for i in range(n): print(b) fdwd = math.pi * b * factor / 2 fdwd /= 90 for j in range(90): x.forward(fdwd) x.left(1) temp = a a = b b = temp + b # Here 'factor' signifies the multiplicative # factor which expands or shrinks the scale # of the plot by a certain factor. factor = 1 # Taking Input for the number of # Iterations our Algorithm will run n = int(input('Enter the number of iterations (must be > 1): ')) # Plotting the Fibonacci Spiral Fractal # and printing the corresponding Fibonacci Number if n > 0: print("Fibonacci series for", n, "elements :") x = turtle.Turtle() x.speed(100) fiboPlot(n) turtle.done() else: print("Number of iterations must be > 0")
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def clamp_number(num, a, b): return max(min(num, max(a, b)), min(a, b)) clamp_number(2, 3, 5) # 3 clamp_number(1, -1, -5) # -1
• Nov 18, 2022 •AustinLeath
# importing the modules import os import shutil # getting the current working directory src_dir = os.getcwd() # printing current directory print(src_dir) # copying the files shutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst # printing the list of new files print(os.listdir())
• May 31, 2023 •CodeCatch
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def generate_pascals_triangle(num_rows): triangle = [] for row in range(num_rows): # Initialize the row with 1 current_row = [1] # Calculate the values for the current row if row > 0: previous_row = triangle[row - 1] for i in range(len(previous_row) - 1): current_row.append(previous_row[i] + previous_row[i + 1]) # Append 1 at the end of the row current_row.append(1) # Add the current row to the triangle triangle.append(current_row) return triangle def display_pascals_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Pascal's Triangle: ")) # Generate Pascal's Triangle pascals_triangle = generate_pascals_triangle(num_rows) # Display Pascal's Triangle display_pascals_triangle(pascals_triangle)
# Python code to demonstrate # method to remove i'th character # Naive Method # Initializing String test_str = "CodeCatch" # Printing original string print ("The original string is : " + test_str) # Removing char at pos 3 # using loop new_str = "" for i in range(len(test_str)): if i != 2: new_str = new_str + test_str[i] # Printing string after removal print ("The string after removal of i'th character : " + new_str)
• May 5, 2026 •CodeCatch
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{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}