• Nov 19, 2022 •CodeCatch
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from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
• Oct 4, 2023 •AustinLeath
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weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))
• Feb 26, 2023 •wabdelh
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#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• Jul 24, 2024 •AustinLeath
from statistics import median, mean, mode def print_stats(array): print(array) print("median =", median(array)) print("mean =", mean(array)) print("mode =", mode(array)) print() print_stats([1, 2, 3, 3, 4]) print_stats([1, 2, 3, 3])
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def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
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# Python program for implementation of Bogo Sort import random # Sorts array a[0..n-1] using Bogo sort def bogoSort(a): n = len(a) while (is_sorted(a)== False): shuffle(a) # To check if array is sorted or not def is_sorted(a): n = len(a) for i in range(0, n-1): if (a[i] > a[i+1] ): return False return True # To generate permuatation of the array def shuffle(a): n = len(a) for i in range (0,n): r = random.randint(0,n-1) a[i], a[r] = a[r], a[i] # Driver code to test above a = [3, 2, 4, 1, 0, 5] bogoSort(a) print("Sorted array :") for i in range(len(a)): print ("%d" %a[i]),