• Nov 18, 2022 •AustinLeath
0 likes • 4 views
primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)
• Nov 19, 2022 •CodeCatch
0 likes • 1 view
def print_x_pattern(size): i,j = 0,size - 1 while j >= 0 and i < size: initial_spaces = ' '*min(i,j) middle_spaces = ' '*(abs(i - j) - 1) final_spaces = ' '*(size - 1 - max(i,j)) if j == i: print(initial_spaces + '*' + final_spaces) else: print(initial_spaces + '*' + middle_spaces + '*' + final_spaces) i += 1 j -= 1 print_x_pattern(7)
0 likes • 2 views
from functools import partial def curry(fn, *args): return partial(fn, *args) add = lambda x, y: x + y add10 = curry(add, 10) add10(20) # 30
• Sep 20, 2025 •cntt.dsc-f4b6
1 like • 2 views
print(123)
• May 31, 2023 •CodeCatch
0 likes • 0 views
# Prompt user for a decimal number decimal = int(input("Enter a decimal number: ")) # Convert decimal to binary binary = bin(decimal) # Convert decimal to hexadecimal hexadecimal = hex(decimal) # Display the results print("Binary:", binary) print("Hexadecimal:", hexadecimal)
• Apr 15, 2021 •NoahEaton
import anytree as at import random as rm # Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white. def random_tree(node_count): # Generates the list of nodes nodes = [] for i in range(node_count): test = rm.randint(1,2) if test == 1: nodes.append(at.Node(str(i),color="white")) else: nodes.append(at.Node(str(i),color="red")) #Creates the various main branches for i in range(node_count): for j in range(i, len(nodes)): test = rm.randint(1,len(nodes)) if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]): nodes[j].parent = nodes[i] #Collects all the main branches into a single tree with the first node being the root for i in range(1, node_count): if nodes[i].parent == None and (not nodes[i] == nodes[0]): nodes[i].parent = nodes[0] return nodes[0]