• Nov 18, 2022 •AustinLeath
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# @return a list of strings, [s1, s2] def letterCombinations(self, digits): if '' == digits: return [] kvmaps = { '2': 'abc', '3': 'def', '4': 'ghi', '5': 'jkl', '6': 'mno', '7': 'pqrs', '8': 'tuv', '9': 'wxyz' } return reduce(lambda acc, digit: [x + y for x in acc for y in kvmaps[digit]], digits, [''])
• Oct 15, 2022 •CodeCatch
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my_list = ["blue", "red", "green"] #1- Using sort or srted directly or with specifc keys my_list.sort() #sorts alphabetically or in an ascending order for numeric data my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest. # You can use reverse=True to flip the order #2- Using locale and functools import locale from functools import cmp_to_key my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
• Nov 19, 2022 •CodeCatch
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from collections import defaultdict def combine_values(*dicts): res = defaultdict(list) for d in dicts: for key in d: res[key].append(d[key]) return dict(res) d1 = {'a': 1, 'b': 'foo', 'c': 400} d2 = {'a': 3, 'b': 200, 'd': 400} combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• May 5, 2026 •CodeCatch
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def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11