• Dec 29, 2025 •CodeCatch
0 likes • 2 views
def bitonic_sort(arr, low, cnt, direction): ...
• Nov 19, 2022 •CodeCatch
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# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()
• Dec 24, 2025 •CodeCatch
1 like • 4 views
def counting_sort(arr, exp): n = len(arr) output = [0] * n count = [0] * 10 for i in range(n): index = (arr[i] // exp) % 10 count[index] += 1 for i in range(1, 10): count[i] += count[i-1] i = n - 1 while i >= 0: index = (arr[i] // exp) % 10 output[count[index] - 1] = arr[i] count[index] -= 1 i -= 1 for i in range(n): arr[i] = output[i] def radix_sort(arr): max_val = max(arr) exp = 1 while max_val // exp > 0: counting_sort(arr, exp) exp *= 10 if __name__ == "__main__": arr = [170, 45, 75, 90, 802, 24, 2, 66] print("Original array:", arr) radix_sort(arr) print("Sorted array:", arr)
• Nov 18, 2022 •AustinLeath
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# question3.py from itertools import product V='∀' E='∃' def tt(f,n) : xss=product((0,1),repeat=n) print('function:',f.__name__) for xs in xss : print(*xs,':',int(f(*xs))) print('') # this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r) def parta(p,q,r) : a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c def partb(p,q,r) : a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c print("part A:") tt(parta,3) print("part B:") tt(partb,3)
• May 31, 2023 •CodeCatch
import calendar # Prompt user for year and month year = int(input("Enter the year: ")) month = int(input("Enter the month: ")) # Create a calendar object cal = calendar.monthcalendar(year, month) # Display the calendar print(calendar.month_name[month], year) print("Mon Tue Wed Thu Fri Sat Sun") for week in cal: for day in week: if day == 0: print(" ", end="") else: print(str(day).rjust(2), " ", end="") print()
• Sep 14, 2024 •rgannedo-6205
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# Python binary search function def binary_search(arr, target): left = 0 right = len(arr) - 1 while left <= right: mid = (left + right) // 2 if arr[mid] == target: return mid elif arr[mid] < target: left = mid + 1 else: right = mid - 1 return -1 # Usage arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] target = 7 result = binary_search(arr, target) if result != -1: print(f"Element is present at index {result}") else: print("Element is not present in array")