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my_list = [1, 2, 3, 4, 5]removed_element = my_list.pop(2) # Remove and return element at index 2print(removed_element) # 3print(my_list) # [1, 2, 4, 5]last_element = my_list.pop() # Remove and return the last elementprint(last_element) # 5print(my_list) # [1, 2, 4]
def generate_pascals_triangle(num_rows):triangle = []for row in range(num_rows):# Initialize the row with 1current_row = [1]# Calculate the values for the current rowif row > 0:previous_row = triangle[row - 1]for i in range(len(previous_row) - 1):current_row.append(previous_row[i] + previous_row[i + 1])# Append 1 at the end of the rowcurrent_row.append(1)# Add the current row to the triangletriangle.append(current_row)return triangledef display_pascals_triangle(triangle):for row in triangle:for number in row:print(number, end=" ")print()# Prompt the user for the number of rowsnum_rows = int(input("Enter the number of rows for Pascal's Triangle: "))# Generate Pascal's Trianglepascals_triangle = generate_pascals_triangle(num_rows)# Display Pascal's Triangledisplay_pascals_triangle(pascals_triangle)
my_list = ["blue", "red", "green"]#1- Using sort or srted directly or with specifc keysmy_list.sort() #sorts alphabetically or in an ascending order for numeric datamy_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.# You can use reverse=True to flip the order#2- Using locale and functoolsimport localefrom functools import cmp_to_keymy_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
import sys# sample TuplesTuple1 = ("A", 1, "B", 2, "C", 3)Tuple2 = ("Geek1", "Raju", "Geek2", "Nikhil", "Geek3", "Deepanshu")Tuple3 = ((1, "Lion"), ( 2, "Tiger"), (3, "Fox"), (4, "Wolf"))# print the sizes of sample Tuplesprint("Size of Tuple1: " + str(sys.getsizeof(Tuple1)) + "bytes")print("Size of Tuple2: " + str(sys.getsizeof(Tuple2)) + "bytes")print("Size of Tuple3: " + str(sys.getsizeof(Tuple3)) + "bytes")
# Function to check Armstrong numberdef is_armstrong_number(number):# Convert number to string to iterate over its digitsnum_str = str(number)# Calculate the sum of the cubes of each digitdigit_sum = sum(int(digit) ** len(num_str) for digit in num_str)# Compare the sum with the original numberif digit_sum == number:return Trueelse:return False# Prompt user for a numbernumber = int(input("Enter a number: "))# Check if the number is an Armstrong numberif is_armstrong_number(number):print(number, "is an Armstrong number.")else:print(number, "is not an Armstrong number.")
weigh = lambda a,b: sum(b)-sum(a)FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)])print(FindCoin([1,1,1,1,1,1,1,2,1]))