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prime_lists=[] # a list to store the prime numbersdef prime(n): # define prime numbersif n <= 1:return False# divide n by 2... up to n-1for i in range(2, n):if n % i == 0: # the remainder should'nt be a 0return Falseelse:prime_lists.append(n)return Truefor n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30prime(n)check=0 # a var to limit the output to 10 onlyfor n in prime_lists:for x in prime_lists:val= n *xif (val > 1000 ):check=check +1if (check <10) :print("the num is:", val , "=",n , "* ", x )break
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)
import anytree as atimport random as rm# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.def random_tree(node_count):# Generates the list of nodesnodes = []for i in range(node_count):test = rm.randint(1,2)if test == 1:nodes.append(at.Node(str(i),color="white"))else:nodes.append(at.Node(str(i),color="red"))#Creates the various main branchesfor i in range(node_count):for j in range(i, len(nodes)):test = rm.randint(1,len(nodes))if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):nodes[j].parent = nodes[i]#Collects all the main branches into a single tree with the first node being the rootfor i in range(1, node_count):if nodes[i].parent == None and (not nodes[i] == nodes[0]):nodes[i].parent = nodes[0]return nodes[0]
# Prompt user for a decimal numberdecimal = int(input("Enter a decimal number: "))# Convert decimal to binarybinary = bin(decimal)# Convert decimal to hexadecimalhexadecimal = hex(decimal)# Display the resultsprint("Binary:", binary)print("Hexadecimal:", hexadecimal)
# Python binary search functiondef binary_search(arr, target):left = 0right = len(arr) - 1while left <= right:mid = (left + right) // 2if arr[mid] == target:return midelif arr[mid] < target:left = mid + 1else:right = mid - 1return -1# Usagearr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]target = 7result = binary_search(arr, target)if result != -1:print(f"Element is present at index {result}")else:print("Element is not present in array")
""" Binary Search Algorithm----------------------------------------"""#iterative implementation of binary search in Pythondef binary_search(a_list, item):"""Performs iterative binary search to find the position of an integer in a given, sorted, list.a_list -- sorted list of integersitem -- integer you are searching for the position of"""first = 0last = len(a_list) - 1while first <= last:i = (first + last) / 2if a_list[i] == item:return ' found at position '.format(item=item, i=i)elif a_list[i] > item:last = i - 1elif a_list[i] < item:first = i + 1else:return ' not found in the list'.format(item=item)#recursive implementation of binary search in Pythondef binary_search_recursive(a_list, item):"""Performs recursive binary search of an integer in a given, sorted, list.a_list -- sorted list of integersitem -- integer you are searching for the position of"""first = 0last = len(a_list) - 1if len(a_list) == 0:return ' was not found in the list'.format(item=item)else:i = (first + last) // 2if item == a_list[i]:return ' found'.format(item=item)else:if a_list[i] < item:return binary_search_recursive(a_list[i+1:], item)else:return binary_search_recursive(a_list[:i], item)