clamp number
0 likes • Nov 19, 2022
Python
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from collections import defaultdictdef combine_values(*dicts):res = defaultdict(list)for d in dicts:for key in d:res[key].append(d[key])return dict(res)d1 = {'a': 1, 'b': 'foo', 'c': 400}d2 = {'a': 3, 'b': 200, 'd': 400}combine_values(d1, d2) # {'a': [1, 3], 'b': ['foo', 200], 'c': [400], 'd': [400]}
# Input for row and columnR = int(input())C = int(input())# Using list comprehension for inputmatrix = [[int(input()) for x in range (C)] for y in range(R)]
# Python program for implementation of Bubble Sortdef bubbleSort(arr):n = len(arr)# Traverse through all array elementsfor i in range(n-1):# range(n) also work but outer loop will repeat one time more than needed.# Last i elements are already in placefor j in range(0, n-i-1):# traverse the array from 0 to n-i-1# Swap if the element found is greater# than the next elementif arr[j] > arr[j+1] :arr[j], arr[j+1] = arr[j+1], arr[j]# Driver code to test abovearr = [64, 34, 25, 12, 22, 11, 90]bubbleSort(arr)print ("Sorted array is:")for i in range(len(arr)):print ("%d" %arr[i]),
def print_x_pattern(size):i,j = 0,size - 1while j >= 0 and i < size:initial_spaces = ' '*min(i,j)middle_spaces = ' '*(abs(i - j) - 1)final_spaces = ' '*(size - 1 - max(i,j))if j == i:print(initial_spaces + '*' + final_spaces)else:print(initial_spaces + '*' + middle_spaces + '*' + final_spaces)i += 1j -= 1print_x_pattern(7)
from time import sleepdef delay(fn, ms, *args):sleep(ms / 1000)return fn(*args)delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)