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clamp number

Nov 19, 2022CodeCatch
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Multiply Two Matrices

May 31, 2023CodeCatch

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# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)

Connect to MYSQL and create a database

Nov 19, 2022CodeCatch

0 likes • 1 view

import mysql.connector
mydb = mysql.connector.connect(
host="localhost",
user="yourusername",
password="yourpassword"
)
mycursor = mydb.cursor()
mycursor.execute("CREATE DATABASE mydatabase")

find parity outliers

Nov 19, 2022CodeCatch

0 likes • 4 views

from collections import Counter
def find_parity_outliers(nums):
return [
x for x in nums
if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]
]
find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]

integer to roman numeral

Nov 19, 2022CodeCatch

0 likes • 1 view

def to_roman_numeral(num):
lookup = [
(1000, 'M'),
(900, 'CM'),
(500, 'D'),
(400, 'CD'),
(100, 'C'),
(90, 'XC'),
(50, 'L'),
(40, 'XL'),
(10, 'X'),
(9, 'IX'),
(5, 'V'),
(4, 'IV'),
(1, 'I'),
]
res = ''
for (n, roman) in lookup:
(d, num) = divmod(num, n)
res += roman * d
return res
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'

Python Fibonacci

Sep 6, 2020C S

0 likes • 0 views

def Fibonacci(n):
if n<0:
print("Incorrect input")
# First Fibonacci number is 0
elif n==1:
return 0
# Second Fibonacci number is 1
elif n==2:
return 1
else:
return Fibonacci(n-1)+Fibonacci(n-2)
# Driver Program
print(Fibonacci(9))

Color Gradient

Mar 10, 2021Skrome

0 likes • 1 view

color2 = (60, 74, 172)
color1 = (19, 28, 87)
percent = 1.0
for i in range(101):
resultRed = round(color1[0] + percent * (color2[0] - color1[0]))
resultGreen = round(color1[1] + percent * (color2[1] - color1[1]))
resultBlue = round(color1[2] + percent * (color2[2] - color1[2]))
print((resultRed, resultGreen, resultBlue))
percent -= 0.01