Loading...
More Python Posts
# Input for row and columnR = int(input())C = int(input())# Using list comprehension for inputmatrix = [[int(input()) for x in range (C)] for y in range(R)]
import os# Get the current directorycurrent_dir = os.getcwd()# Loop through each file in the current directoryfor filename in os.listdir(current_dir):# Check if the file name starts with a number followed by a period and a spaceif filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ':# Remove the number, period, and space from the file namenew_filename = filename[3:]# Rename the fileos.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))
mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0}# How to sort a dict by value Python 3>sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))}print(sort)# How to sort a dict by key Python 3>sort = {key:mydict[key] for key in sorted(mydict.keys())}print(sort)
def check_prop(fn, prop):return lambda obj: fn(obj[prop])check_age = check_prop(lambda x: x >= 18, 'age')user = {'name': 'Mark', 'age': 18}check_age(user) # True
# Python program for implementation of Radix Sort# A function to do counting sort of arr[] according to# the digit represented by exp.def countingSort(arr, exp1):n = len(arr)# The output array elements that will have sorted arroutput = [0] * (n)# initialize count array as 0count = [0] * (10)# Store count of occurrences in count[]for i in range(0, n):index = (arr[i]/exp1)count[int((index)%10)] += 1# Change count[i] so that count[i] now contains actual# position of this digit in output arrayfor i in range(1,10):count[i] += count[i-1]# Build the output arrayi = n-1while i>=0:index = (arr[i]/exp1)output[ count[ int((index)%10) ] - 1] = arr[i]count[int((index)%10)] -= 1i -= 1# Copying the output array to arr[],# so that arr now contains sorted numbersi = 0for i in range(0,len(arr)):arr[i] = output[i]# Method to do Radix Sortdef radixSort(arr):# Find the maximum number to know number of digitsmax1 = max(arr)# Do counting sort for every digit. Note that instead# of passing digit number, exp is passed. exp is 10^i# where i is current digit numberexp = 1while max1/exp > 0:countingSort(arr,exp)exp *= 10# Driver code to test abovearr = [ 170, 45, 75, 90, 802, 24, 2, 66]radixSort(arr)for i in range(len(arr)):print(arr[i]),
def calculate_values():value1 = 10value2 = 20return value1, value2result1, result2 = calculate_values()print("Result 1:", result1)print("Result 2:", result2)