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class Solution(object):def floodFill(self, image, sr, sc, newColor):R, C = len(image), len(image[0])color = image[sr][sc]if color == newColor: return imagedef dfs(r, c):if image[r][c] == color:image[r][c] = newColorif r >= 1: dfs(r-1, c)if r+1 < R: dfs(r+1, c)if c >= 1: dfs(r, c-1)if c+1 < C: dfs(r, c+1)dfs(sr, sc)return image
def to_roman_numeral(num):lookup = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I'),]res = ''for (n, roman) in lookup:(d, num) = divmod(num, n)res += roman * dreturn resto_roman_numeral(3) # 'III'to_roman_numeral(11) # 'XI'to_roman_numeral(1998) # 'MCMXCVIII'
def generate_floyds_triangle(num_rows):triangle = []number = 1for row in range(num_rows):current_row = []for _ in range(row + 1):current_row.append(number)number += 1triangle.append(current_row)return triangledef display_floyds_triangle(triangle):for row in triangle:for number in row:print(number, end=" ")print()# Prompt the user for the number of rowsnum_rows = int(input("Enter the number of rows for Floyd's Triangle: "))# Generate Floyd's Trianglefloyds_triangle = generate_floyds_triangle(num_rows)# Display Floyd's Triangledisplay_floyds_triangle(floyds_triangle)
def clamp_number(num, a, b):return max(min(num, max(a, b)), min(a, b))clamp_number(2, 3, 5) # 3clamp_number(1, -1, -5) # -1
# Python program for implementation of Bubble Sortdef bubbleSort(arr):n = len(arr)# Traverse through all array elementsfor i in range(n-1):# range(n) also work but outer loop will repeat one time more than needed.# Last i elements are already in placefor j in range(0, n-i-1):# traverse the array from 0 to n-i-1# Swap if the element found is greater# than the next elementif arr[j] > arr[j+1] :arr[j], arr[j+1] = arr[j+1], arr[j]# Driver code to test abovearr = [64, 34, 25, 12, 22, 11, 90]bubbleSort(arr)print ("Sorted array is:")for i in range(len(arr)):print ("%d" %arr[i]),
#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77# xor a list of integers to find the lonely integerres = a[0]for i in range(1,len(a)):res = res ^ a[i]