• May 5, 2026 •CodeCatch
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• Oct 15, 2022 •CodeCatch
1 like • 3 views
my_list = ["blue", "red", "green"] #1- Using sort or srted directly or with specifc keys my_list.sort() #sorts alphabetically or in an ascending order for numeric data my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest. # You can use reverse=True to flip the order #2- Using locale and functools import locale from functools import cmp_to_key my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
• Nov 19, 2022 •CodeCatch
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from collections import defaultdict def collect_dictionary(obj): inv_obj = defaultdict(list) for key, value in obj.items(): inv_obj[value].append(key) return dict(inv_obj) ages = { 'Peter': 10, 'Isabel': 10, 'Anna': 9, } collect_dictionary(ages) # { 10: ['Peter', 'Isabel'], 9: ['Anna'] }
def print_x_pattern(size): i,j = 0,size - 1 while j >= 0 and i < size: initial_spaces = ' '*min(i,j) middle_spaces = ' '*(abs(i - j) - 1) final_spaces = ' '*(size - 1 - max(i,j)) if j == i: print(initial_spaces + '*' + final_spaces) else: print(initial_spaces + '*' + middle_spaces + '*' + final_spaces) i += 1 j -= 1 print_x_pattern(7)
• Oct 4, 2023 •AustinLeath
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weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))