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Bogo Sort

Nov 19, 2022CodeCatch
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Binary search

Sep 22, 2023AustinLeath

0 likes • 24 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")

Radix sort

Nov 19, 2022CodeCatch

0 likes • 1 view

# Python program for implementation of Radix Sort
# A function to do counting sort of arr[] according to
# the digit represented by exp.
def countingSort(arr, exp1):
n = len(arr)
# The output array elements that will have sorted arr
output = [0] * (n)
# initialize count array as 0
count = [0] * (10)
# Store count of occurrences in count[]
for i in range(0, n):
index = (arr[i]/exp1)
count[int((index)%10)] += 1
# Change count[i] so that count[i] now contains actual
# position of this digit in output array
for i in range(1,10):
count[i] += count[i-1]
# Build the output array
i = n-1
while i>=0:
index = (arr[i]/exp1)
output[ count[ int((index)%10) ] - 1] = arr[i]
count[int((index)%10)] -= 1
i -= 1
# Copying the output array to arr[],
# so that arr now contains sorted numbers
i = 0
for i in range(0,len(arr)):
arr[i] = output[i]
# Method to do Radix Sort
def radixSort(arr):
# Find the maximum number to know number of digits
max1 = max(arr)
# Do counting sort for every digit. Note that instead
# of passing digit number, exp is passed. exp is 10^i
# where i is current digit number
exp = 1
while max1/exp > 0:
countingSort(arr,exp)
exp *= 10
# Driver code to test above
arr = [ 170, 45, 75, 90, 802, 24, 2, 66]
radixSort(arr)
for i in range(len(arr)):
print(arr[i]),
my_list = [1, 2, 3, 4, 5]
removed_element = my_list.pop(2) # Remove and return element at index 2
print(removed_element) # 3
print(my_list) # [1, 2, 4, 5]
last_element = my_list.pop() # Remove and return the last element
print(last_element) # 5
print(my_list) # [1, 2, 4]

Distinct Primes Finder > 1000

Nov 18, 2022AustinLeath

0 likes • 3 views

primes=[]
products=[]
def prime(num):
if num > 1:
for i in range(2,num):
if (num % i) == 0:
return False
else:
primes.append(num)
return True
for n in range(30,1000):
if len(primes) >= 20:
break;
else:
prime(n)
for previous, current in zip(primes[::2], primes[1::2]):
products.append(previous * current)
print (products)

Copy file to destination

Nov 18, 2022AustinLeath

0 likes • 1 view

# importing the modules
import os
import shutil
# getting the current working directory
src_dir = os.getcwd()
# printing current directory
print(src_dir)
# copying the files
shutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst
# printing the list of new files
print(os.listdir())

Untitled

Apr 21, 2023sebastianagauyao2002-61a8

0 likes • 0 views

print("hellur")