• Aug 1, 2025 •AustinLeath
0 likes • 2 views
import re _proposal_regex = r'(?:(?:(IKE|ESP):)?[\w/]+(?:/NO_EXT_SEQ)?(?:, ?(IKE|ESP):[\w/]+(?:/NO_EXT_SEQ)?)*)?' _proposals_re = rf'(?P<proposals>{_proposal_regex}|)' pattern = rf'received proposals: {_proposals_re}' match = re.match(pattern, 'received proposals: ') print(match.group('proposals') if match else "No match") # Prints "No match"
• Nov 19, 2022 •CodeCatch
0 likes • 11 views
""" Currency Converter ---------------------------------------- """ import urllib.request import json def currency_converter(currency_from, currency_to, currency_input): yql_base_url = "https://query.yahooapis.com/v1/public/yql" yql_query = 'select%20*%20from%20yahoo.finance.xchange%20where%20pair' \ '%20in%20("'+currency_from+currency_to+'")' yql_query_url = yql_base_url + "?q=" + yql_query + "&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys" try: yql_response = urllib.request.urlopen(yql_query_url) try: json_string = str(yql_response.read()) json_string = json_string[2: json_string = json_string[:-1] print(json_string) yql_json = json.loads(json_string) last_rate = yql_json['query']['results']['rate']['Rate'] currency_output = currency_input * float(last_rate) return currency_output except (ValueError, KeyError, TypeError): print(yql_query_url) return "JSON format error" except IOError as e: print(str(e)) currency_input = 1 #currency codes : http://en.wikipedia.org/wiki/ISO_4217 currency_from = "USD" currency_to = "TRY" rate = currency_converter(currency_from, currency_to, currency_input) print(rate)
• Jun 26, 2025 •AustinLeath
def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
• Mar 12, 2021 •mo_ak
0 likes • 3 views
prime_lists=[] # a list to store the prime numbers def prime(n): # define prime numbers if n <= 1: return False # divide n by 2... up to n-1 for i in range(2, n): if n % i == 0: # the remainder should'nt be a 0 return False else: prime_lists.append(n) return True for n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30 prime(n) check=0 # a var to limit the output to 10 only for n in prime_lists: for x in prime_lists: val= n *x if (val > 1000 ): check=check +1 if (check <10) : print("the num is:", val , "=",n , "* ", x ) break
• Nov 18, 2022 •AustinLeath
0 likes • 8 views
#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
• Oct 15, 2022 •CodeCatch
0 likes • 1 view
class Solution(object): def floodFill(self, image, sr, sc, newColor): R, C = len(image), len(image[0]) color = image[sr][sc] if color == newColor: return image def dfs(r, c): if image[r][c] == color: image[r][c] = newColor if r >= 1: dfs(r-1, c) if r+1 < R: dfs(r+1, c) if c >= 1: dfs(r, c-1) if c+1 < C: dfs(r, c+1) dfs(sr, sc) return image