• Nov 19, 2022 •CodeCatch
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import mysql.connector mydb = mysql.connector.connect( host="localhost", user="yourusername", password="yourpassword" ) mycursor = mydb.cursor() mycursor.execute("CREATE DATABASE mydatabase")
• Sep 9, 2023 •AustinLeath
0 likes • 25 views
print("test")
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""" Rock Paper Scissors ---------------------------------------- """ import random import os import re os.system('cls' if os.name=='nt' else 'clear') while (1 < 2): print "\n" print "Rock, Paper, Scissors - Shoot!" userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ") if not re.match("[SsRrPp]", userChoice): print "Please choose a letter:" print "[R]ock, [S]cissors or [P]aper." continue // Echo the user's choice print "You chose: " + userChoice choices = ['R', 'P', 'S'] opponenetChoice = random.choice(choices) print "I chose: " + opponenetChoice if opponenetChoice == str.upper(userChoice): print "Tie! " #if opponenetChoice == str("R") and str.upper(userChoice) == "P" elif opponenetChoice == 'R' and userChoice.upper() == 'S': print "Scissors beats rock, I win! " continue elif opponenetChoice == 'S' and userChoice.upper() == 'P': print "Scissors beats paper! I win! " continue elif opponenetChoice == 'P' and userChoice.upper() == 'R': print "Paper beat rock, I win! " continue else: print "You win!"
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# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
• Aug 1, 2025 •AustinLeath
import re _proposal_regex = r'(?:(?:(IKE|ESP):)?[\w/]+(?:/NO_EXT_SEQ)?(?:, ?(IKE|ESP):[\w/]+(?:/NO_EXT_SEQ)?)*)?' _proposals_re = rf'(?P<proposals>{_proposal_regex}|)' pattern = rf'received proposals: {_proposals_re}' match = re.match(pattern, 'received proposals: ') print(match.group('proposals') if match else "No match") # Prints "No match"
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)