• Nov 18, 2022 •AustinLeath
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primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)
• Nov 19, 2022 •CodeCatch
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list_1 = [1,2,3,4,5,6,7,8,9] cubed = map(lambda x: pow(x,3), list_1) print(list(cubed)) #Results #[1, 8, 27, 64, 125, 216, 343, 512, 729]
• Sep 14, 2024 •rgannedo-6205
0 likes • 2 views
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
from collections import Counter def find_parity_outliers(nums): return [ x for x in nums if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0] ] find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]
• May 31, 2023 •CodeCatch
0 likes • 3 views
import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
0 likes • 19 views
def sum_of_powers(end, power = 2, start = 1): return sum([(i) ** power for i in range(start, end + 1)]) sum_of_powers(10) # 385 sum_of_powers(10, 3) # 3025 sum_of_powers(10, 3, 5) # 2925