• Nov 19, 2022 •CodeCatch
0 likes • 4 views
list_1 = [1,2,3,4,5,6,7,8,9] cubed = map(lambda x: pow(x,3), list_1) print(list(cubed)) #Results #[1, 8, 27, 64, 125, 216, 343, 512, 729]
• Sep 3, 2025 •AustinLeath
0 likes • 5 views
import subprocess class CommandRunner: def run_command(self, command): command_process = subprocess.Popen(command, shell=True, stdout=subprocess.PIPE, text=True) output = command_process.communicate()[0].strip() return_code = command_process.returncode return output, return_code def main(): # Create instance of CommandRunner runner = CommandRunner() # Define the command command = 'ping -c 4 localhost' try: # Run the command and get output and return code output, return_code = runner.run_command(command) # Print the output and return code print(f"Command output:\n{output}") print(f"Return code: {return_code}") except Exception as e: print(f"An error occurred: {e}") if __name__ == "__main__": main()
• Nov 18, 2022 •AustinLeath
import itertools import string import time def guess_password(real): chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation attempts = 0 for password_length in range(1, 9): for guess in itertools.product(chars, repeat=password_length): startTime = time.time() attempts += 1 guess = ''.join(guess) if guess == real: return 'password is {}. found in {} guesses.'.format(guess, attempts) loopTime = (time.time() - startTime); print(guess, attempts, loopTime) print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n") val = input("Enter a password you want to crack that is 9 characters or below: ") print(guess_password(val.lower()))
0 likes • 0 views
""" Rock Paper Scissors ---------------------------------------- """ import random import os import re os.system('cls' if os.name=='nt' else 'clear') while (1 < 2): print "\n" print "Rock, Paper, Scissors - Shoot!" userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ") if not re.match("[SsRrPp]", userChoice): print "Please choose a letter:" print "[R]ock, [S]cissors or [P]aper." continue // Echo the user's choice print "You chose: " + userChoice choices = ['R', 'P', 'S'] opponenetChoice = random.choice(choices) print "I chose: " + opponenetChoice if opponenetChoice == str.upper(userChoice): print "Tie! " #if opponenetChoice == str("R") and str.upper(userChoice) == "P" elif opponenetChoice == 'R' and userChoice.upper() == 'S': print "Scissors beats rock, I win! " continue elif opponenetChoice == 'S' and userChoice.upper() == 'P': print "Scissors beats paper! I win! " continue elif opponenetChoice == 'P' and userChoice.upper() == 'R': print "Paper beat rock, I win! " continue else: print "You win!"
• Oct 4, 2023 •AustinLeath
0 likes • 10 views
weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))
• May 31, 2023 •CodeCatch
# Function to check Armstrong number def is_armstrong_number(number): # Convert number to string to iterate over its digits num_str = str(number) # Calculate the sum of the cubes of each digit digit_sum = sum(int(digit) ** len(num_str) for digit in num_str) # Compare the sum with the original number if digit_sum == number: return True else: return False # Prompt user for a number number = int(input("Enter a number: ")) # Check if the number is an Armstrong number if is_armstrong_number(number): print(number, "is an Armstrong number.") else: print(number, "is not an Armstrong number.")