• May 5, 2026 •CodeCatch
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Python
• Nov 19, 2022 •CodeCatch
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# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()
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{"output":{"name":"format_final_json_response","arguments":{"output":{}}}}
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• Oct 15, 2022 •CodeCatch
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class Solution(object): def floodFill(self, image, sr, sc, newColor): R, C = len(image), len(image[0]) color = image[sr][sc] if color == newColor: return image def dfs(r, c): if image[r][c] == color: image[r][c] = newColor if r >= 1: dfs(r-1, c) if r+1 < R: dfs(r+1, c) if c >= 1: dfs(r, c-1) if c+1 < C: dfs(r, c+1) dfs(sr, sc) return image