• Nov 19, 2022 •CodeCatch
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def key_of_min(d): return min(d, key = d.get) key_of_min({'a':4, 'b':0, 'c':13}) # b
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# Python code to demonstrate # method to remove i'th character # Naive Method # Initializing String test_str = "CodeCatch" # Printing original string print ("The original string is : " + test_str) # Removing char at pos 3 # using loop new_str = "" for i in range(len(test_str)): if i != 2: new_str = new_str + test_str[i] # Printing string after removal print ("The string after removal of i'th character : " + new_str)
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""" Rock Paper Scissors ---------------------------------------- """ import random import os import re os.system('cls' if os.name=='nt' else 'clear') while (1 < 2): print "\n" print "Rock, Paper, Scissors - Shoot!" userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ") if not re.match("[SsRrPp]", userChoice): print "Please choose a letter:" print "[R]ock, [S]cissors or [P]aper." continue // Echo the user's choice print "You chose: " + userChoice choices = ['R', 'P', 'S'] opponenetChoice = random.choice(choices) print "I chose: " + opponenetChoice if opponenetChoice == str.upper(userChoice): print "Tie! " #if opponenetChoice == str("R") and str.upper(userChoice) == "P" elif opponenetChoice == 'R' and userChoice.upper() == 'S': print "Scissors beats rock, I win! " continue elif opponenetChoice == 'S' and userChoice.upper() == 'P': print "Scissors beats paper! I win! " continue elif opponenetChoice == 'P' and userChoice.upper() == 'R': print "Paper beat rock, I win! " continue else: print "You win!"
• Mar 10, 2021 •Skrome
import string def caesar(text, shift, alphabets): def shift_alphabet(alphabet): return alphabet[shift:] + alphabet[:shift] shifted_alphabets = tuple(map(shift_alphabet, alphabets)) final_alphabet = "".join(alphabets) final_shifted_alphabet = "".join(shifted_alphabets) table = str.maketrans(final_alphabet, final_shifted_alphabet) return text.translate(table) plain_text = "Hey Skrome, welcome to CodeCatch" print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))
• Nov 18, 2022 •AustinLeath
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primes=[] products=[] def prime(num): if num > 1: for i in range(2,num): if (num % i) == 0: return False else: primes.append(num) return True for n in range(30,1000): if len(primes) >= 20: break; else: prime(n) for previous, current in zip(primes[::2], primes[1::2]): products.append(previous * current) print (products)
# List lst = [1, 2, 3, 'Alice', 'Alice'] # One-Liner indices = [i for i in range(len(lst)) if lst[i]=='Alice'] # Result print(indices) # [3, 4]