• Nov 19, 2022 •CodeCatch
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
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# Python program for implementation of Selection # Sort import sys A = [64, 25, 12, 22, 11] # Traverse through all array elements for i in range(len(A)): # Find the minimum element in remaining # unsorted array min_idx = i for j in range(i+1, len(A)): if A[min_idx] > A[j]: min_idx = j # Swap the found minimum element with # the first element A[i], A[min_idx] = A[min_idx], A[i] # Driver code to test above print ("Sorted array") for i in range(len(A)): print("%d" %A[i]),
• Dec 24, 2025 •CodeCatch
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string
• Oct 7, 2022 •KETRICK
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x[cat_var].isnull().sum().sort_values(ascending=False)
• May 5, 2026 •CodeCatch
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# Python program for implementation of Bogo Sort import random # Sorts array a[0..n-1] using Bogo sort def bogoSort(a): n = len(a) while (is_sorted(a)== False): shuffle(a) # To check if array is sorted or not def is_sorted(a): n = len(a) for i in range(0, n-1): if (a[i] > a[i+1] ): return False return True # To generate permuatation of the array def shuffle(a): n = len(a) for i in range (0,n): r = random.randint(0,n-1) a[i], a[r] = a[r], a[i] # Driver code to test above a = [3, 2, 4, 1, 0, 5] bogoSort(a) print("Sorted array :") for i in range(len(a)): print ("%d" %a[i]),