• May 31, 2023 •CodeCatch
0 likes • 8 views
my_list = [1, 2, 3, 4, 5] removed_element = my_list.pop(2) # Remove and return element at index 2 print(removed_element) # 3 print(my_list) # [1, 2, 4, 5] last_element = my_list.pop() # Remove and return the last element print(last_element) # 5 print(my_list) # [1, 2, 4]
• Nov 19, 2022 •CodeCatch
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def sum_of_powers(end, power = 2, start = 1): return sum([(i) ** power for i in range(start, end + 1)]) sum_of_powers(10) # 385 sum_of_powers(10, 3) # 3025 sum_of_powers(10, 3, 5) # 2925
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def byte_size(s): return len(s.encode('utf-8')) byte_size('😀') # 4 byte_size('Hello World') # 11
• Sep 14, 2024 •rgannedo-6205
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
• Nov 18, 2022 •AustinLeath
0 likes • 6 views
import itertools import string import time def guess_password(real): chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuation attempts = 0 for password_length in range(1, 9): for guess in itertools.product(chars, repeat=password_length): startTime = time.time() attempts += 1 guess = ''.join(guess) if guess == real: return 'password is {}. found in {} guesses.'.format(guess, attempts) loopTime = (time.time() - startTime); print(guess, attempts, loopTime) print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n") val = input("Enter a password you want to crack that is 9 characters or below: ") print(guess_password(val.lower()))
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from time import sleep def delay(fn, ms, *args): sleep(ms / 1000) return fn(*args) delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second