• Nov 18, 2022 •AustinLeath
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# question3.py from itertools import product V='∀' E='∃' def tt(f,n) : xss=product((0,1),repeat=n) print('function:',f.__name__) for xs in xss : print(*xs,':',int(f(*xs))) print('') # this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r) def parta(p,q,r) : a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c def partb(p,q,r) : a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c print("part A:") tt(parta,3) print("part B:") tt(partb,3)
• Oct 15, 2022 •CodeCatch
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my_list = ["blue", "red", "green"] #1- Using sort or srted directly or with specifc keys my_list.sort() #sorts alphabetically or in an ascending order for numeric data my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest. # You can use reverse=True to flip the order #2- Using locale and functools import locale from functools import cmp_to_key my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
• Nov 19, 2022 •CodeCatch
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def check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = check_prop(lambda x: x >= 18, 'age') user = {'name': 'Mark', 'age': 18} check_age(user) # True
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# Python program for implementation of Bogo Sort import random # Sorts array a[0..n-1] using Bogo sort def bogoSort(a): n = len(a) while (is_sorted(a)== False): shuffle(a) # To check if array is sorted or not def is_sorted(a): n = len(a) for i in range(0, n-1): if (a[i] > a[i+1] ): return False return True # To generate permuatation of the array def shuffle(a): n = len(a) for i in range (0,n): r = random.randint(0,n-1) a[i], a[r] = a[r], a[i] # Driver code to test above a = [3, 2, 4, 1, 0, 5] bogoSort(a) print("Sorted array :") for i in range(len(a)): print ("%d" %a[i]),
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""" Binary Search Algorithm ---------------------------------------- """ #iterative implementation of binary search in Python def binary_search(a_list, item): """Performs iterative binary search to find the position of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 while first <= last: i = (first + last) / 2 if a_list[i] == item: return ' found at position '.format(item=item, i=i) elif a_list[i] > item: last = i - 1 elif a_list[i] < item: first = i + 1 else: return ' not found in the list'.format(item=item) #recursive implementation of binary search in Python def binary_search_recursive(a_list, item): """Performs recursive binary search of an integer in a given, sorted, list. a_list -- sorted list of integers item -- integer you are searching for the position of """ first = 0 last = len(a_list) - 1 if len(a_list) == 0: return ' was not found in the list'.format(item=item) else: i = (first + last) // 2 if item == a_list[i]: return ' found'.format(item=item) else: if a_list[i] < item: return binary_search_recursive(a_list[i+1:], item) else: return binary_search_recursive(a_list[:i], item)
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# Python program for implementation of Bubble Sort def bubbleSort(arr): n = len(arr) # Traverse through all array elements for i in range(n-1): # range(n) also work but outer loop will repeat one time more than needed. # Last i elements are already in place for j in range(0, n-i-1): # traverse the array from 0 to n-i-1 # Swap if the element found is greater # than the next element if arr[j] > arr[j+1] : arr[j], arr[j+1] = arr[j+1], arr[j] # Driver code to test above arr = [64, 34, 25, 12, 22, 11, 90] bubbleSort(arr) print ("Sorted array is:") for i in range(len(arr)): print ("%d" %arr[i]),