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weigh = lambda a,b: sum(b)-sum(a)FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)])print(FindCoin([1,1,1,1,1,1,1,2,1]))
import itertoolsimport stringimport timedef guess_password(real):chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuationattempts = 0for password_length in range(1, 9):for guess in itertools.product(chars, repeat=password_length):startTime = time.time()attempts += 1guess = ''.join(guess)if guess == real:return 'password is {}. found in {} guesses.'.format(guess, attempts)loopTime = (time.time() - startTime);print(guess, attempts, loopTime)print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n")val = input("Enter a password you want to crack that is 9 characters or below: ")print(guess_password(val.lower()))
#question1.pydef rose(n) :if n==0 :yield []else :for k in range(0,n) :for l in rose(k) :for r in rose(n-1-k) :yield [l]+[r]+[r]def start(n) :for x in rose(n) :print(x) #basically I am printing x for each rose(n) fileprint("starting program: \n")start(2) # here is where I call the start function
bytes_data = b'Hello, World!'string_data = bytes_data.decode('utf-8')print("String:", string_data)
import pandas as pdx = pd.read_excel(FILE_NAME)print(x)
import anytree as atimport random as rm# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.def random_tree(node_count):# Generates the list of nodesnodes = []for i in range(node_count):test = rm.randint(1,2)if test == 1:nodes.append(at.Node(str(i),color="white"))else:nodes.append(at.Node(str(i),color="red"))#Creates the various main branchesfor i in range(node_count):for j in range(i, len(nodes)):test = rm.randint(1,len(nodes))if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):nodes[j].parent = nodes[i]#Collects all the main branches into a single tree with the first node being the rootfor i in range(1, node_count):if nodes[i].parent == None and (not nodes[i] == nodes[0]):nodes[i].parent = nodes[0]return nodes[0]