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Nov 19, 2022CodeCatch
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Currency Converter

Nov 19, 2022CodeCatch

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""" Currency Converter
----------------------------------------
"""
import urllib.request
import json
def currency_converter(currency_from, currency_to, currency_input):
yql_base_url = "https://query.yahooapis.com/v1/public/yql"
yql_query = 'select%20*%20from%20yahoo.finance.xchange%20where%20pair' \
'%20in%20("'+currency_from+currency_to+'")'
yql_query_url = yql_base_url + "?q=" + yql_query + "&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys"
try:
yql_response = urllib.request.urlopen(yql_query_url)
try:
json_string = str(yql_response.read())
json_string = json_string[2:
json_string = json_string[:-1]
print(json_string)
yql_json = json.loads(json_string)
last_rate = yql_json['query']['results']['rate']['Rate']
currency_output = currency_input * float(last_rate)
return currency_output
except (ValueError, KeyError, TypeError):
print(yql_query_url)
return "JSON format error"
except IOError as e:
print(str(e))
currency_input = 1
#currency codes : http://en.wikipedia.org/wiki/ISO_4217
currency_from = "USD"
currency_to = "TRY"
rate = currency_converter(currency_from, currency_to, currency_input)
print(rate)

AnyTree Randomizer

Apr 15, 2021NoahEaton

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import anytree as at
import random as rm
# Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white.
def random_tree(node_count):
# Generates the list of nodes
nodes = []
for i in range(node_count):
test = rm.randint(1,2)
if test == 1:
nodes.append(at.Node(str(i),color="white"))
else:
nodes.append(at.Node(str(i),color="red"))
#Creates the various main branches
for i in range(node_count):
for j in range(i, len(nodes)):
test = rm.randint(1,len(nodes))
if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]):
nodes[j].parent = nodes[i]
#Collects all the main branches into a single tree with the first node being the root
for i in range(1, node_count):
if nodes[i].parent == None and (not nodes[i] == nodes[0]):
nodes[i].parent = nodes[0]
return nodes[0]

Binary search

Sep 22, 2023AustinLeath

0 likes • 13 views

# Python binary search function
def binary_search(arr, target):
left = 0
right = len(arr) - 1
while left <= right:
mid = (left + right) // 2
if arr[mid] == target:
return mid
elif arr[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1
# Usage
arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
target = 7
result = binary_search(arr, target)
if result != -1:
print(f"Element is present at index {result}")
else:
print("Element is not present in array")

Check Armstrong Number

May 31, 2023CodeCatch

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# Function to check Armstrong number
def is_armstrong_number(number):
# Convert number to string to iterate over its digits
num_str = str(number)
# Calculate the sum of the cubes of each digit
digit_sum = sum(int(digit) ** len(num_str) for digit in num_str)
# Compare the sum with the original number
if digit_sum == number:
return True
else:
return False
# Prompt user for a number
number = int(input("Enter a number: "))
# Check if the number is an Armstrong number
if is_armstrong_number(number):
print(number, "is an Armstrong number.")
else:
print(number, "is not an Armstrong number.")

Mad libs generator

Nov 19, 2022CodeCatch

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#Loop back to this point once code finishes
loop = 1
while (loop < 10):
#All the questions that the program asks the user
noun = input("Choose a noun: ")
p_noun = input("Choose a plural noun: ")
noun2 = input("Choose a noun: ")
place = input("Name a place: ")
adjective = input("Choose an adjective (Describing word): ")
noun3 = input("Choose a noun: ")
#Displays the story based on the users input
print ("------------------------------------------")
print ("Be kind to your",noun,"- footed", p_noun)
print ("For a duck may be somebody's", noun2,",")
print ("Be kind to your",p_noun,"in",place)
print ("Where the weather is always",adjective,".")
print ()
print ("You may think that is this the",noun3,",")
print ("Well it is.")
print ("------------------------------------------")
#Loop back to "loop = 1"
loop = loop + 1

Bogo Sort

Nov 19, 2022CodeCatch

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# Python program for implementation of Bogo Sort
import random
# Sorts array a[0..n-1] using Bogo sort
def bogoSort(a):
n = len(a)
while (is_sorted(a)== False):
shuffle(a)
# To check if array is sorted or not
def is_sorted(a):
n = len(a)
for i in range(0, n-1):
if (a[i] > a[i+1] ):
return False
return True
# To generate permuatation of the array
def shuffle(a):
n = len(a)
for i in range (0,n):
r = random.randint(0,n-1)
a[i], a[r] = a[r], a[i]
# Driver code to test above
a = [3, 2, 4, 1, 0, 5]
bogoSort(a)
print("Sorted array :")
for i in range(len(a)):
print ("%d" %a[i]),