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return byte size

Nov 19, 2022CodeCatch
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convert bytes to a string

Jun 1, 2023CodeCatch

0 likes • 3 views

bytes_data = b'Hello, World!'
string_data = bytes_data.decode('utf-8')
print("String:", string_data)

UNT CSCE 2100 Question 1

Nov 18, 2022AustinLeath

0 likes • 8 views

#question1.py
def rose(n) :
if n==0 :
yield []
else :
for k in range(0,n) :
for l in rose(k) :
for r in rose(n-1-k) :
yield [l]+[r]+[r]
def start(n) :
for x in rose(n) :
print(x) #basically I am printing x for each rose(n) file
print("starting program: \n")
start(2) # here is where I call the start function

two-digit integer

Feb 26, 2023wabdelh

0 likes • 0 views

#You are given a two-digit integer n. Return the sum of its digits.
#Example
#For n = 29 the output should be solution (n) = 11
def solution(n):
return (n//10 + n%10)

Find URL in string

Nov 19, 2022CodeCatch

0 likes • 0 views

# Python code to find the URL from an input string
# Using the regular expression
import re
def Find(string):
# findall() has been used
# with valid conditions for urls in string
regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))"
url = re.findall(regex,string)
return [x[0] for x in url]
# Driver Code
string = 'My Profile: https://codecatch.net'
print("Urls: ", Find(string))

print colored text to IDE terminal

Jun 1, 2023CodeCatch

0 likes • 2 views

from colorama import init, Fore
# Initialize colorama
init()
print(Fore.RED + "This text is in red color.")
print(Fore.GREEN + "This text is in green color.")
print(Fore.BLUE + "This text is in blue color.")
# Reset colorama
print(Fore.RESET + "This text is back to the default color.")

Create a Pascal’s Triangle

May 31, 2023CodeCatch

0 likes • 1 view

def generate_pascals_triangle(num_rows):
triangle = []
for row in range(num_rows):
# Initialize the row with 1
current_row = [1]
# Calculate the values for the current row
if row > 0:
previous_row = triangle[row - 1]
for i in range(len(previous_row) - 1):
current_row.append(previous_row[i] + previous_row[i + 1])
# Append 1 at the end of the row
current_row.append(1)
# Add the current row to the triangle
triangle.append(current_row)
return triangle
def display_pascals_triangle(triangle):
for row in triangle:
for number in row:
print(number, end=" ")
print()
# Prompt the user for the number of rows
num_rows = int(input("Enter the number of rows for Pascal's Triangle: "))
# Generate Pascal's Triangle
pascals_triangle = generate_pascals_triangle(num_rows)
# Display Pascal's Triangle
display_pascals_triangle(pascals_triangle)